Vrftsjtryk

I have multiple revisions of a text file in separate files in the same folder.

How can I grep all files in that folder without listing any duplicate of lines with identical text?

Pipe the result into sort to filter duplicates.

grep exampletext | sort -u

If what you need is to find which file(s) match some text, use:

$ grep -rl 'text to find' ./dir

If you need only the first match of each file:

$ for file in ./*; do sed -n '/text to match/{p,q}' "$file"; done

which will not print the name of the files matching, but will be fast.

Or:

$ find ../* -type f -exec sh -c '

      a=$(sed -n "/echo/{p;q}" "$1");

      [ "$a" ] && printf "%sn" "$1 : $a"

  ' findsh {} ;

If you need the filename also (separated with :).

I use:

grep test files* | puniq

puniq is: perl -ne '$seen{$_}++ or print;'

It is similar to sort -u but it does not sort the file.

I would use something like:

#!/bin/bash

echo "What is the base name to reduce to unique lines? "

read filename

for i in *$filename*; do 

    cat $i >> tempfile

    cat tempfile | sort -u -o tempfile

done

or

cat *filename* | sort -u

The placement of the *'s is based on how you name your itterations.

• When done read tempfile.


• Rename to whatever.

Use with caution in a test directory with test files first

• Tailor to your needs.