Helix - number of turns [on hold]
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How to find the number of turns required for an helix if I have the radius, effective length of the helix, pitch and alpha angle?
geometry
asked Nov 22 at 5:49
Harish
52
put on hold as off-topic by user302797, A. Pongrácz, Rebellos, Xander Henderson, Did 7 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user302797, A. Pongrácz, Rebellos, Xander Henderson, Did
If this question can be reworded to fit the rules in the help center, please edit the question.
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up vote
-1
down vote
favorite
How to find the number of turns required for an helix if I have the radius, effective length of the helix, pitch and alpha angle?
geometry
asked Nov 22 at 5:49
Harish
52
put on hold as off-topic by user302797, A. Pongrácz, Rebellos, Xander Henderson, Did 7 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user302797, A. Pongrácz, Rebellos, Xander Henderson, Did
If this question can be reworded to fit the rules in the help center, please edit the question.
1
For me the terms need to be spelled out: effective length (if helix resting on table but standing vertically is length the height?) Also what angles are pitch and alpha?
– coffeemath
Nov 22 at 6:00
@Harish $n$= standing length ( or height of helix)/pitch.
– Narasimham
10 hours ago
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
How to find the number of turns required for an helix if I have the radius, effective length of the helix, pitch and alpha angle?
geometry
asked Nov 22 at 5:49
Harish
52
How to find the number of turns required for an helix if I have the radius, effective length of the helix, pitch and alpha angle?
geometry
geometry
asked Nov 22 at 5:49
Harish
52
asked Nov 22 at 5:49
Harish
52
asked Nov 22 at 5:49
Harish
52
asked Nov 22 at 5:49
Harish
52
asked Nov 22 at 5:49
Harish
52
52
put on hold as off-topic by user302797, A. Pongrácz, Rebellos, Xander Henderson, Did 7 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user302797, A. Pongrácz, Rebellos, Xander Henderson, Did
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by user302797, A. Pongrácz, Rebellos, Xander Henderson, Did 7 hours ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – user302797, A. Pongrácz, Rebellos, Xander Henderson, Did
If this question can be reworded to fit the rules in the help center, please edit the question.
1
For me the terms need to be spelled out: effective length (if helix resting on table but standing vertically is length the height?) Also what angles are pitch and alpha?
– coffeemath
Nov 22 at 6:00
@Harish $n$= standing length ( or height of helix)/pitch.
– Narasimham
10 hours ago
add a comment |
1
For me the terms need to be spelled out: effective length (if helix resting on table but standing vertically is length the height?) Also what angles are pitch and alpha?
– coffeemath
Nov 22 at 6:00
@Harish $n$= standing length ( or height of helix)/pitch.
– Narasimham
10 hours ago
1
1
For me the terms need to be spelled out: effective length (if helix resting on table but standing vertically is length the height?) Also what angles are pitch and alpha?
– coffeemath
Nov 22 at 6:00
For me the terms need to be spelled out: effective length (if helix resting on table but standing vertically is length the height?) Also what angles are pitch and alpha?
– coffeemath
Nov 22 at 6:00
@Harish $n$= standing length ( or height of helix)/pitch.
– Narasimham
10 hours ago
@Harish $n$= standing length ( or height of helix)/pitch.
– Narasimham
10 hours ago
add a comment |
2 Answers
2
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If you unroll the cylinder the helix winds around, you have a right triangle with the hypotenuse the helix, one leg the number of circumferences of the cylinder that corresponds to the number of turns and the other leg the height along the cylinder.
answered Nov 22 at 6:00
Ross Millikan
289k23195367
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$displaystyle begin{array}{{>{displaystyle}l}}
Let, Radius= R\
Pitch= P\
Effective length of helix= L\
And Number of turns= N\
First of all we should calculate the length associated with one turn within the helix. Let it be x.\
Now formula for x is
end{array}$
$displaystyle $ $displaystyle x^{2} =P^{2} +( Circumference)^{2}$
$displaystyle begin{array}{{>{displaystyle}l}}
Where Circumference= 2πR. Hence x=sqrt{P^{2} +( 2πR)^{2}}\
And number of turns, N=frac{L}{x}\
or N=frac{L}{sqrt{P^{2} +( 2πR)^{2}}}
end{array}$
answered Nov 22 at 6:15
Dikshit Gautam
815
1
Why is it all in italics? suggest MathJax edit.
– coffeemath
Nov 22 at 7:12
Is there any problem in italics?
– Dikshit Gautam
Nov 22 at 8:23
1
@JyrkiLahtonen Okay. Thanks
– Dikshit Gautam
Nov 22 at 8:39
@JyrkiLahtonen I'll take care of it in future
– Dikshit Gautam
Nov 22 at 8:40
@JyrkiLahtonen Is my answer right?
– Dikshit Gautam
Nov 22 at 8:42
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
If you unroll the cylinder the helix winds around, you have a right triangle with the hypotenuse the helix, one leg the number of circumferences of the cylinder that corresponds to the number of turns and the other leg the height along the cylinder.
answered Nov 22 at 6:00
Ross Millikan
289k23195367
add a comment |
up vote
0
down vote
If you unroll the cylinder the helix winds around, you have a right triangle with the hypotenuse the helix, one leg the number of circumferences of the cylinder that corresponds to the number of turns and the other leg the height along the cylinder.
answered Nov 22 at 6:00
Ross Millikan
289k23195367
add a comment |
up vote
0
down vote
up vote
0
down vote
If you unroll the cylinder the helix winds around, you have a right triangle with the hypotenuse the helix, one leg the number of circumferences of the cylinder that corresponds to the number of turns and the other leg the height along the cylinder.
answered Nov 22 at 6:00
Ross Millikan
289k23195367
If you unroll the cylinder the helix winds around, you have a right triangle with the hypotenuse the helix, one leg the number of circumferences of the cylinder that corresponds to the number of turns and the other leg the height along the cylinder.
answered Nov 22 at 6:00
Ross Millikan
289k23195367
answered Nov 22 at 6:00
Ross Millikan
289k23195367
answered Nov 22 at 6:00
Ross Millikan
289k23195367
answered Nov 22 at 6:00
Ross Millikan
289k23195367
289k23195367
add a comment |
add a comment |
up vote
0
down vote
$displaystyle begin{array}{{>{displaystyle}l}}
Let, Radius= R\
Pitch= P\
Effective length of helix= L\
And Number of turns= N\
First of all we should calculate the length associated with one turn within the helix. Let it be x.\
Now formula for x is
end{array}$
$displaystyle $ $displaystyle x^{2} =P^{2} +( Circumference)^{2}$
$displaystyle begin{array}{{>{displaystyle}l}}
Where Circumference= 2πR. Hence x=sqrt{P^{2} +( 2πR)^{2}}\
And number of turns, N=frac{L}{x}\
or N=frac{L}{sqrt{P^{2} +( 2πR)^{2}}}
end{array}$
answered Nov 22 at 6:15
Dikshit Gautam
815
1
Why is it all in italics? suggest MathJax edit.
– coffeemath
Nov 22 at 7:12
Is there any problem in italics?
– Dikshit Gautam
Nov 22 at 8:23
1
@JyrkiLahtonen Okay. Thanks
– Dikshit Gautam
Nov 22 at 8:39
@JyrkiLahtonen I'll take care of it in future
– Dikshit Gautam
Nov 22 at 8:40
@JyrkiLahtonen Is my answer right?
– Dikshit Gautam
Nov 22 at 8:42
add a comment |
up vote
0
down vote
$displaystyle begin{array}{{>{displaystyle}l}}
Let, Radius= R\
Pitch= P\
Effective length of helix= L\
And Number of turns= N\
First of all we should calculate the length associated with one turn within the helix. Let it be x.\
Now formula for x is
end{array}$
$displaystyle $ $displaystyle x^{2} =P^{2} +( Circumference)^{2}$
$displaystyle begin{array}{{>{displaystyle}l}}
Where Circumference= 2πR. Hence x=sqrt{P^{2} +( 2πR)^{2}}\
And number of turns, N=frac{L}{x}\
or N=frac{L}{sqrt{P^{2} +( 2πR)^{2}}}
end{array}$
answered Nov 22 at 6:15
Dikshit Gautam
815
1
Why is it all in italics? suggest MathJax edit.
– coffeemath
Nov 22 at 7:12
Is there any problem in italics?
– Dikshit Gautam
Nov 22 at 8:23
1
@JyrkiLahtonen Okay. Thanks
– Dikshit Gautam
Nov 22 at 8:39
@JyrkiLahtonen I'll take care of it in future
– Dikshit Gautam
Nov 22 at 8:40
@JyrkiLahtonen Is my answer right?
– Dikshit Gautam
Nov 22 at 8:42
add a comment |
up vote
0
down vote
up vote
0
down vote
$displaystyle begin{array}{{>{displaystyle}l}}
Let, Radius= R\
Pitch= P\
Effective length of helix= L\
And Number of turns= N\
First of all we should calculate the length associated with one turn within the helix. Let it be x.\
Now formula for x is
end{array}$
$displaystyle $ $displaystyle x^{2} =P^{2} +( Circumference)^{2}$
$displaystyle begin{array}{{>{displaystyle}l}}
Where Circumference= 2πR. Hence x=sqrt{P^{2} +( 2πR)^{2}}\
And number of turns, N=frac{L}{x}\
or N=frac{L}{sqrt{P^{2} +( 2πR)^{2}}}
end{array}$
answered Nov 22 at 6:15
Dikshit Gautam
815
$displaystyle begin{array}{{>{displaystyle}l}}
Let, Radius= R\
Pitch= P\
Effective length of helix= L\
And Number of turns= N\
First of all we should calculate the length associated with one turn within the helix. Let it be x.\
Now formula for x is
end{array}$
$displaystyle $ $displaystyle x^{2} =P^{2} +( Circumference)^{2}$
$displaystyle begin{array}{{>{displaystyle}l}}
Where Circumference= 2πR. Hence x=sqrt{P^{2} +( 2πR)^{2}}\
And number of turns, N=frac{L}{x}\
or N=frac{L}{sqrt{P^{2} +( 2πR)^{2}}}
end{array}$
answered Nov 22 at 6:15
Dikshit Gautam
815
edited Nov 22 at 8:15
answered Nov 22 at 6:15
Dikshit Gautam
815
answered Nov 22 at 6:15
Dikshit Gautam
815
answered Nov 22 at 6:15
Dikshit Gautam
815
815
1
Why is it all in italics? suggest MathJax edit.
– coffeemath
Nov 22 at 7:12
Is there any problem in italics?
– Dikshit Gautam
Nov 22 at 8:23
1
@JyrkiLahtonen Okay. Thanks
– Dikshit Gautam
Nov 22 at 8:39
@JyrkiLahtonen I'll take care of it in future
– Dikshit Gautam
Nov 22 at 8:40
@JyrkiLahtonen Is my answer right?
– Dikshit Gautam
Nov 22 at 8:42
add a comment |
1
Why is it all in italics? suggest MathJax edit.
– coffeemath
Nov 22 at 7:12
Is there any problem in italics?
– Dikshit Gautam
Nov 22 at 8:23
1
@JyrkiLahtonen Okay. Thanks
– Dikshit Gautam
Nov 22 at 8:39
@JyrkiLahtonen I'll take care of it in future
– Dikshit Gautam
Nov 22 at 8:40
@JyrkiLahtonen Is my answer right?
– Dikshit Gautam
Nov 22 at 8:42
1
1
Why is it all in italics? suggest MathJax edit.
– coffeemath
Nov 22 at 7:12
Why is it all in italics? suggest MathJax edit.
– coffeemath
Nov 22 at 7:12
Is there any problem in italics?
– Dikshit Gautam
Nov 22 at 8:23
Is there any problem in italics?
– Dikshit Gautam
Nov 22 at 8:23
1
1
@JyrkiLahtonen Okay. Thanks
– Dikshit Gautam
Nov 22 at 8:39
@JyrkiLahtonen Okay. Thanks
– Dikshit Gautam
Nov 22 at 8:39
@JyrkiLahtonen I'll take care of it in future
– Dikshit Gautam
Nov 22 at 8:40
@JyrkiLahtonen I'll take care of it in future
– Dikshit Gautam
Nov 22 at 8:40
@JyrkiLahtonen Is my answer right?
– Dikshit Gautam
Nov 22 at 8:42
@JyrkiLahtonen Is my answer right?
– Dikshit Gautam
Nov 22 at 8:42
add a comment |
1
For me the terms need to be spelled out: effective length (if helix resting on table but standing vertically is length the height?) Also what angles are pitch and alpha?
– coffeemath
Nov 22 at 6:00
@Harish $n$= standing length ( or height of helix)/pitch.
– Narasimham
10 hours ago