Rearrangement of lists of strings
5
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 at 9:27
kglr
176k9197402
asked Nov 25 at 2:43
Suite401
981312
add a comment |
5
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 at 9:27
kglr
176k9197402
asked Nov 25 at 2:43
Suite401
981312
add a comment |
5
5
5
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
edited Nov 25 at 9:27
kglr
176k9197402
asked Nov 25 at 2:43
Suite401
981312
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis. As always, thanks for suggestions!
string-manipulation
string-manipulation
edited Nov 25 at 9:27
kglr
176k9197402
asked Nov 25 at 2:43
Suite401
981312
edited Nov 25 at 9:27
kglr
176k9197402
asked Nov 25 at 2:43
Suite401
981312
edited Nov 25 at 9:27
kglr
176k9197402
edited Nov 25 at 9:27
kglr
176k9197402
edited Nov 25 at 9:27
kglr
176k9197402
176k9197402
asked Nov 25 at 2:43
Suite401
981312
asked Nov 25 at 2:43
Suite401
981312
asked Nov 25 at 2:43
Suite401
981312
981312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
14
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
176k9197402
add a comment |
6
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
14
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
176k9197402
add a comment |
14
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
176k9197402
add a comment |
14
14
14
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
176k9197402
You can use StringRiffle:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered Nov 25 at 2:56
kglr
176k9197402
answered Nov 25 at 2:56
kglr
176k9197402
answered Nov 25 at 2:56
kglr
176k9197402
answered Nov 25 at 2:56
kglr
176k9197402
176k9197402
add a comment |
add a comment |
6
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
add a comment |
6
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
add a comment |
6
6
6
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
answered Nov 25 at 2:52
Bob Hanlon
58.5k23595
58.5k23595
add a comment |
add a comment |
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