Calculate Lebesgue and Hausdorf measure of a hexagon












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Given this hexagon $P$, I've got to calculate the Lebesgue measure $lambda_{2}(P)$ and the Hausdorff measure $mathscr{H}^1(partial P)$. My thoughts are:
You can leave out the 6 line segments of length 1 that makes the boundary, as they are presentable as graph of a steady function (so their lebesgue measure is zero).My intuition tells me that $lambda_{2}(P)=6*frac{sqrt{3}}{4}= frac{3sqrt{3}}{2}$ ( as one triangle has one triangle has the area:$frac{sqrt{3}}{4}$) and $mathscr{H}^1(partial P)=6$(the lenght of the boundary). I'm not sure if it's right and how to argue the right results. Any help would be greatly aprpreciated.










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    1














    enter image description here



    Given this hexagon $P$, I've got to calculate the Lebesgue measure $lambda_{2}(P)$ and the Hausdorff measure $mathscr{H}^1(partial P)$. My thoughts are:
    You can leave out the 6 line segments of length 1 that makes the boundary, as they are presentable as graph of a steady function (so their lebesgue measure is zero).My intuition tells me that $lambda_{2}(P)=6*frac{sqrt{3}}{4}= frac{3sqrt{3}}{2}$ ( as one triangle has one triangle has the area:$frac{sqrt{3}}{4}$) and $mathscr{H}^1(partial P)=6$(the lenght of the boundary). I'm not sure if it's right and how to argue the right results. Any help would be greatly aprpreciated.










    share|cite|improve this question

























      1












      1








      1


      1





      enter image description here



      Given this hexagon $P$, I've got to calculate the Lebesgue measure $lambda_{2}(P)$ and the Hausdorff measure $mathscr{H}^1(partial P)$. My thoughts are:
      You can leave out the 6 line segments of length 1 that makes the boundary, as they are presentable as graph of a steady function (so their lebesgue measure is zero).My intuition tells me that $lambda_{2}(P)=6*frac{sqrt{3}}{4}= frac{3sqrt{3}}{2}$ ( as one triangle has one triangle has the area:$frac{sqrt{3}}{4}$) and $mathscr{H}^1(partial P)=6$(the lenght of the boundary). I'm not sure if it's right and how to argue the right results. Any help would be greatly aprpreciated.










      share|cite|improve this question













      enter image description here



      Given this hexagon $P$, I've got to calculate the Lebesgue measure $lambda_{2}(P)$ and the Hausdorff measure $mathscr{H}^1(partial P)$. My thoughts are:
      You can leave out the 6 line segments of length 1 that makes the boundary, as they are presentable as graph of a steady function (so their lebesgue measure is zero).My intuition tells me that $lambda_{2}(P)=6*frac{sqrt{3}}{4}= frac{3sqrt{3}}{2}$ ( as one triangle has one triangle has the area:$frac{sqrt{3}}{4}$) and $mathscr{H}^1(partial P)=6$(the lenght of the boundary). I'm not sure if it's right and how to argue the right results. Any help would be greatly aprpreciated.







      measure-theory lebesgue-measure hausdorff-measure






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      asked Nov 28 '18 at 16:14









      Thesinus

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