Show every nonempty compact Hausdorff space is not the countable union of nowhere dense sets












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I know this proof is somewhat similar, or related to the Baire's Category Theorem but I can't seem to figure out how to do it.



The Baire Category theorem asserts that if X is a complete metric space or a locally compact Hausdorff space (my case), then the complement of a countable union of nowhere dense sets is always nonempty.



How can I use this on the proof?










share|cite|improve this question











$endgroup$

















    0












    $begingroup$


    I know this proof is somewhat similar, or related to the Baire's Category Theorem but I can't seem to figure out how to do it.



    The Baire Category theorem asserts that if X is a complete metric space or a locally compact Hausdorff space (my case), then the complement of a countable union of nowhere dense sets is always nonempty.



    How can I use this on the proof?










    share|cite|improve this question











    $endgroup$















      0












      0








      0


      0



      $begingroup$


      I know this proof is somewhat similar, or related to the Baire's Category Theorem but I can't seem to figure out how to do it.



      The Baire Category theorem asserts that if X is a complete metric space or a locally compact Hausdorff space (my case), then the complement of a countable union of nowhere dense sets is always nonempty.



      How can I use this on the proof?










      share|cite|improve this question











      $endgroup$




      I know this proof is somewhat similar, or related to the Baire's Category Theorem but I can't seem to figure out how to do it.



      The Baire Category theorem asserts that if X is a complete metric space or a locally compact Hausdorff space (my case), then the complement of a countable union of nowhere dense sets is always nonempty.



      How can I use this on the proof?







      general-topology compactness baire-category






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      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Dec 11 '18 at 11:26









      José Carlos Santos

      162k22130233




      162k22130233










      asked Dec 11 '18 at 10:54









      A curious oneA curious one

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      5318






















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          $begingroup$

          Since every compact Hausdorff space is locally compact, you can actually use the statement that you mentioned.






          share|cite|improve this answer









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            $begingroup$

            Since every compact Hausdorff space is locally compact, you can actually use the statement that you mentioned.






            share|cite|improve this answer









            $endgroup$


















              2












              $begingroup$

              Since every compact Hausdorff space is locally compact, you can actually use the statement that you mentioned.






              share|cite|improve this answer









              $endgroup$
















                2












                2








                2





                $begingroup$

                Since every compact Hausdorff space is locally compact, you can actually use the statement that you mentioned.






                share|cite|improve this answer









                $endgroup$



                Since every compact Hausdorff space is locally compact, you can actually use the statement that you mentioned.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 11 '18 at 10:57









                José Carlos SantosJosé Carlos Santos

                162k22130233




                162k22130233






























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