Show the intermediate steps of integration
I have been reading some material in my General Relativity course and there is something that is just stated and I don't see how the result was produced. I will attach an image below
$k$ and $h$ are constants of integration. I am trying to get the two results but just can't. Like for equation $(9)$, I see that integrating the LHS would bring down the differential. But then I think the RHS would be
$$-intfrac{2}{r}left(frac{mathrm{d}r}{dtau}right),mathrm{d}tau = -intfrac{2}{r},mathrm{d}r = -2ln|r| + h$$
which is obviously not the result.
calculus integration
asked Nov 27 at 10:30
MRT
335115
add a comment |
I have been reading some material in my General Relativity course and there is something that is just stated and I don't see how the result was produced. I will attach an image below
$k$ and $h$ are constants of integration. I am trying to get the two results but just can't. Like for equation $(9)$, I see that integrating the LHS would bring down the differential. But then I think the RHS would be
$$-intfrac{2}{r}left(frac{mathrm{d}r}{dtau}right),mathrm{d}tau = -intfrac{2}{r},mathrm{d}r = -2ln|r| + h$$
which is obviously not the result.
calculus integration
asked Nov 27 at 10:30
MRT
335115
add a comment |
I have been reading some material in my General Relativity course and there is something that is just stated and I don't see how the result was produced. I will attach an image below
$k$ and $h$ are constants of integration. I am trying to get the two results but just can't. Like for equation $(9)$, I see that integrating the LHS would bring down the differential. But then I think the RHS would be
$$-intfrac{2}{r}left(frac{mathrm{d}r}{dtau}right),mathrm{d}tau = -intfrac{2}{r},mathrm{d}r = -2ln|r| + h$$
which is obviously not the result.
calculus integration
asked Nov 27 at 10:30
MRT
335115
I have been reading some material in my General Relativity course and there is something that is just stated and I don't see how the result was produced. I will attach an image below
$k$ and $h$ are constants of integration. I am trying to get the two results but just can't. Like for equation $(9)$, I see that integrating the LHS would bring down the differential. But then I think the RHS would be
$$-intfrac{2}{r}left(frac{mathrm{d}r}{dtau}right),mathrm{d}tau = -intfrac{2}{r},mathrm{d}r = -2ln|r| + h$$
which is obviously not the result.
calculus integration
calculus integration
asked Nov 27 at 10:30
MRT
335115
asked Nov 27 at 10:30
MRT
335115
asked Nov 27 at 10:30
MRT
335115
asked Nov 27 at 10:30
MRT
335115
asked Nov 27 at 10:30
MRT
335115
335115
add a comment |
add a comment |
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