Unlock My Phone! February 2018
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?

Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?

Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
2 hours ago
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
20 mins ago
add a comment |
$begingroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?

Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I forgot my password again! I changed it a few days ago but already forgot!
What is my phone's password this month?

Hint #1:
My passwords do tend to be fairly long, as mentioned in the comments.
Hint #2:
The number itself may not have been on the moon, but maybe something it shares a trait with.
knowledge visual
knowledge visual
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 26 mins ago
Tyler22Alex
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 hours ago
Tyler22AlexTyler22Alex
835
835
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Tyler22Alex is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
2 hours ago
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
20 mins ago
add a comment |
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
2 hours ago
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
20 mins ago
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
2 hours ago
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
2 hours ago
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
20 mins ago
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
20 mins ago
add a comment |
6 Answers
6
active
oldest
votes
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
$endgroup$
2
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
6 hours ago
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
$endgroup$
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
15 mins ago
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
7 mins ago
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
$endgroup$
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
14 mins ago
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
$endgroup$
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
$endgroup$
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
23 mins ago
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "559"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81316%2funlock-my-phone-february-2018%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
6 Answers
6
active
oldest
votes
6 Answers
6
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
$endgroup$
2
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
6 hours ago
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
$endgroup$
2
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
6 hours ago
add a comment |
$begingroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
$endgroup$
Okay, so first of all, I checked the image and contrast to see if there was something hidden there. I couldn't find anything. Next, I followed the literal interpratation of the text, that is:
The first man to walk on the moon was Neil Armstrong. I tried looking for any items that he wore that would have a serial number or something like that. According to this site, https://www.fratellowatches.com/speedy-tuesday-speedmaster-professional-105-012-with-serial-number-2400xxxx/, the Speedwatches were the only ones used on the moon.
Neil Armstrong's serial number on his watch (again, according to the site) is 24002981, which I believe is your password.
answered 7 hours ago
Joe-You-KnowJoe-You-Know
6,56821072
6,56821072
2
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
6 hours ago
add a comment |
2
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
6 hours ago
2
2
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
6 hours ago
$begingroup$
As a number, you don't need people onboard to be first on the moon.
$endgroup$
– Arnaud Mortier
6 hours ago
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
$endgroup$
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
15 mins ago
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
7 mins ago
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
$endgroup$
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
15 mins ago
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
7 mins ago
add a comment |
$begingroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
$endgroup$
I believe the answer is
1000
I think that we are supposed to take this literally as
"first of the word moon, which is M (1000 in Roman)"
answered 5 hours ago
AProughAPrough
5,8561244
5,8561244
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
15 mins ago
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
7 mins ago
add a comment |
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
15 mins ago
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
7 mins ago
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
15 mins ago
$begingroup$
A tag of the puzzle is knowledge. (ROT13) Oryvrir vg be abg, lbh pna gnxr bhg yrggref sebz "Ebzna Xabjyrqtr" arprffnel gb znxr gur jbeq "zbba". Creuncf lbh ner ba gur evtug genpx, ubjrire gur ahzore zvtug or n ovg fznyy nppbeqvat gb Uvag 1. $(+1)$ though!
$endgroup$
– user477343
15 mins ago
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
7 mins ago
$begingroup$
Very interesting answer, but not quite! Maybe take a look at the hints I added?
$endgroup$
– Tyler22Alex
7 mins ago
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
$endgroup$
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
14 mins ago
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
$endgroup$
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
14 mins ago
add a comment |
$begingroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
$endgroup$
Perhaps the password is
11 or eleven or some variation of it
because
Apollo 11 was the first manned mission to the moon, and it had the “largest number” of anything that was first to the moon, greater that Luna 2, which was the first successful unmanned spacecraft to land.
answered 5 hours ago
PiIsNot3PiIsNot3
1,29721
1,29721
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
14 mins ago
add a comment |
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
14 mins ago
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
14 mins ago
$begingroup$
I see the number in Apollo! $(+1)$
$endgroup$
– user477343
14 mins ago
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
$endgroup$
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
$endgroup$
add a comment |
$begingroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
$endgroup$
There are a lot of ways to find numbers that are "first on the moon", so this question may need some more specificity to rule out answers; right now there doesn't seem to be any criteria beyond "the largest" number an answerer might justify somehow, which is probably too broad.
It's possible the password is
201901030226
We know that
OP uses passwords that are usually pretty long, as we learned in Unlock My Phone! January 2018.
We're looking for the largest "first on the moon" number.
China recently made the first landing ever on the far side of the moon - the robotic
Chang'e 4 mission touched down in the Von Kármán Crater at 10:26am Jan. 3, Beijing time.
This is clearly a "first" on the moon, both for China (first moon landing at all) and for humanity (first landing on the dark side of the moon).
If we take the date and time, in GMT, of this moon landing, we get 201901030226. Seconds were not given, so this is the most specific timedate stamp we can get.
Since this is the most recent moon landing, if we were to consider any other "first" - by nation, by mission type, whatever - and take their corresponding YYYYMMDDHMM number, this one would be the largest.
answered 2 hours ago
Rubio♦Rubio
30.4k567188
30.4k567188
add a comment |
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
$endgroup$
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
23 mins ago
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
$endgroup$
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
23 mins ago
add a comment |
$begingroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
$endgroup$
Perhaps the password is
1959
Explanation:
Luna 2 was the first spacecraft to make contact with the moon.
According to Wikipedia, Luna 2 was engraved with "1959 январь" and "СОЮЗ СОВЕТСКИХ СОЦИАЛИСТИЧЕСКИХ РЕСПУБЛИК"1, making "1959" the first number on the moon.
Furthermore, phone passcodes are typically 4 digits long, so using a year as a passcode makes sense.
answered 3 hours ago
user1812user1812
612
612
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
23 mins ago
add a comment |
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
23 mins ago
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
23 mins ago
$begingroup$
Pursuant to Hint 1 however, this does not quite match, thus making it unlikely to be the answer; nevertheless, I like it! $(+1)$ :P
$endgroup$
– user477343
23 mins ago
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I think it's:
23.9 billion
Explanation:
According to Wikipedia:
In January 1969, NASA prepared an itemized estimate of the run-out cost of the Apollo program. The total came to $23.9 billion
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 3 hours ago
tuvokkituvokki
1212
1212
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
tuvokki is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Tyler22Alex is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f81316%2funlock-my-phone-february-2018%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
As a small recommendation, linked with Rubio's answer, if the January 2018 puzzle's hint also applies to this question, it would be better to also place it. It's better to get a repeated hint than a missing yet important hint
$endgroup$
– Belhenix
2 hours ago
$begingroup$
@Belhenix I added that hint as well as one more. I'll keep this in mind for all future puzzles too, thanks!
$endgroup$
– Tyler22Alex
20 mins ago