Question on judging a regular surface in differential geometry











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This is the proposition and proof saying that if we know that S is a regular surface and x is a candidate of parametrization which satisfies 1)differentiable 2)surjective differential map 3)continuous bijective then, x has a continuous inverse thus resulting that x is a real parametrization



However, in the proof, I cannot see that where I used the condition that S is a regular surface



Please let me know where the condition S is a regular surface used and is there any counter-example that x does not have a continuous inverse when S is not a regular surface?





condition 1 in the proposition is that x is differentiable



condition 2 is that locally homeomorphism



condition 3 is that differential dx is one-to-one










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    up vote
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    enter image description here



    This is the proposition and proof saying that if we know that S is a regular surface and x is a candidate of parametrization which satisfies 1)differentiable 2)surjective differential map 3)continuous bijective then, x has a continuous inverse thus resulting that x is a real parametrization



    However, in the proof, I cannot see that where I used the condition that S is a regular surface



    Please let me know where the condition S is a regular surface used and is there any counter-example that x does not have a continuous inverse when S is not a regular surface?





    condition 1 in the proposition is that x is differentiable



    condition 2 is that locally homeomorphism



    condition 3 is that differential dx is one-to-one










    share|cite|improve this question


























      up vote
      1
      down vote

      favorite
      1









      up vote
      1
      down vote

      favorite
      1






      1





      enter image description here



      This is the proposition and proof saying that if we know that S is a regular surface and x is a candidate of parametrization which satisfies 1)differentiable 2)surjective differential map 3)continuous bijective then, x has a continuous inverse thus resulting that x is a real parametrization



      However, in the proof, I cannot see that where I used the condition that S is a regular surface



      Please let me know where the condition S is a regular surface used and is there any counter-example that x does not have a continuous inverse when S is not a regular surface?





      condition 1 in the proposition is that x is differentiable



      condition 2 is that locally homeomorphism



      condition 3 is that differential dx is one-to-one










      share|cite|improve this question















      enter image description here



      This is the proposition and proof saying that if we know that S is a regular surface and x is a candidate of parametrization which satisfies 1)differentiable 2)surjective differential map 3)continuous bijective then, x has a continuous inverse thus resulting that x is a real parametrization



      However, in the proof, I cannot see that where I used the condition that S is a regular surface



      Please let me know where the condition S is a regular surface used and is there any counter-example that x does not have a continuous inverse when S is not a regular surface?





      condition 1 in the proposition is that x is differentiable



      condition 2 is that locally homeomorphism



      condition 3 is that differential dx is one-to-one







      differential-geometry surfaces parametrization






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      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Nov 21 at 5:25

























      asked Nov 14 at 6:56









      Jaeyoon Yoo

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