Vrftsjtryk

I'm designing a puzzle game, and am trying to play-test some concepts. Can you solve these?

109253878934 = A + B + C.
What are the components and why?

Note for C: As a hint to correct an oversight, the product of the digits in C is 2488320.

Partial:

C

C = 94492888611 (29) or 94492788111 (29) or 94492788611 (29)

Rules:

1. Take the shortest path possible starting at green and ending at red.

2. If yellow dots, all must be retrieved before reaching red.

3. Red cannot be crossed, thus only reached once.

4. Colored squares are "locked doors" that are only passable once you have "retrieved" the associated colored triangle.

My qualm:

The final maze has multiple equidistant solutions. If there is a rule that only the lowest possible numbers for possible paths must be crossed (basically 94492788111 is correct), there is no previous example explicitly covering this.

Please correct me where I am wrong.

Based on Comment and Hint (and some trial and error):

I think the intended path was
$99453888111$

A

I am struggling with A.

There are a lot of factors to consider here, such as: The shape, the color, the tilt/orientation, filled or empty, etc. What's weird is, p1's and 43's pentagon tilts doesn't seem to be equal to the tilt of the pentagons in p2 and p3.

My thoughts so far:

The shape represents a number based on the sides of the shape, possibly modified by the other factors such as the color.

"But a star has 10 sides" you say. Well, either a star is 1 in lieu of drawing a line, or something to do with base conversion/dropping 0 etc, whatever.

7 = r3 and r4. I'd like to think this means red is a modification of 0 to the base numbers, and both tilting to the same direction (right) could be addition?

43 = r7 and r5. I dunno, maybe r7 is squared (because hollow) minus r5 (because tilts) and r5 = 6 because blue adds 1 to base number?

251 is a prime though, so yeah... not sure.

B

Hah, not a clue yet

Oh!!!

1. a_1_z -> pp=11

p falls in the range of a to z, thus p is 1. pp = 1 and 1, thus 11

2. a_1_ij_2_op_3_z -> pi = 31 ty =33

p between p and z, thus 3

i between a and i, thus 1

t and y both between p and z, thus 3 and 3.

3. so: well this one is confusing again

the q_1_k is odd.
a-p = 1

q is after k though... so all numbers not between k and q?

l-z = -1

p thus applicable for 1, -1 so 0

i for 1, 1 thus 2

4. rules:

a-m = 2

^b-n = 1

c-o = 1

p-u = 2

^c-v (apparently not inclusive) = 3

d-h = 1

i-z = 2

meaning:

p = 1 2 2 = 5

i = 2 1 2 = 5

c = 2 1 3 = 6

o = 1 1 2 = 4


5. rules:

a-z = 1

a-m = 1 n-z = 2

a-p = 2 q-z = 1

a-e = 1 f-z = 3

a-j = 1 k-s = 2 t-z = 3

a-p = -2 q-z = -1
Then why were #3 and #4 a thing!?!!?!?

meaning:

p = 1 2 2 3 2 -2 = 8

i = 3 1 = 4

t = 1 2 3 3 = 9

y = 1 2 3 3 = 9

l = 1 1 3 2 = 7

e = 1 1 1 1 = 4

a = 1 1 1 1 = 4

s = 1 2 3 2 = 8

________________

B = 8499874484

Answer:

19745379634 - A - B = C

19745379634 - 5238 - 8499874484 = 11245499912

But, this is wrong. So, where did we mess up?

T - C = $19745379634$ - $99453888111$ = $-79708508477$

Sigh*. Back to the drawing board.

B is a 10 digit number. T is 11, and so is my current C, thus there is a problem. Quite probably with my C still.

Rev 2:

If T is $109253878934$

And A is confirmed $5238$

And C is confirmed $99453888111$

Then B must be $109253878934$ - $5238$ - $99453888111$ = $9799985585$

However, I can't get my B formula to match.

Partial answer

For A,

if we ignore tilt and position, then I can fit the four numbers at the top with: colour is power of ten, shape is digit (star is one), filled is positive, empty is negative; sum all shapes.

- filled red star = 1

- filled red triangle and filled red square = 3 + 4 = 7

- filled blue pentagon and empty red heptagon = 50 - 7 = 43

- filled green triangle and empty blue square and empty red enneagon = 300 - 40 - 9 = 251

This gives P^1 = 157, P^2 = 857, P^3 = 1201. These are prime factors of the number at the bottom. P^4 is the missing factor is 3023. Their sum is A = 5238.

Part B: no clue

Part C: already solved by @Dorrulf

B.

Every a_b_c triple forms a range in the alphabet that scores b points, for example a_1_m means that every letter in [a,m] scores 1 point, with wrapround if the range is backwards. I get $B=8699874484$.