Finding probability, when density function is given












0














I have density function $f(x,y)=4xy mathbb{I}_{[0,1] times [0,1]}(x,y)$.



I need to find:
1) $mathbb{P}_F([0,1/3]times[0,1/2])$



2) $mathbb{P}_F([2/3,1]timesmathbb{R})$



So in 1) I got $1/36$ I don’t know is it right, but I was integrating $f(x,y)$. Actually, I also find $Delta_s F$ and got the same.



2) I can’t get the answer. Or the answer is 0. I am not sure. I was doing the same as in 1) Can somebody help me with this?










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    0














    I have density function $f(x,y)=4xy mathbb{I}_{[0,1] times [0,1]}(x,y)$.



    I need to find:
    1) $mathbb{P}_F([0,1/3]times[0,1/2])$



    2) $mathbb{P}_F([2/3,1]timesmathbb{R})$



    So in 1) I got $1/36$ I don’t know is it right, but I was integrating $f(x,y)$. Actually, I also find $Delta_s F$ and got the same.



    2) I can’t get the answer. Or the answer is 0. I am not sure. I was doing the same as in 1) Can somebody help me with this?










    share|cite|improve this question

























      0












      0








      0







      I have density function $f(x,y)=4xy mathbb{I}_{[0,1] times [0,1]}(x,y)$.



      I need to find:
      1) $mathbb{P}_F([0,1/3]times[0,1/2])$



      2) $mathbb{P}_F([2/3,1]timesmathbb{R})$



      So in 1) I got $1/36$ I don’t know is it right, but I was integrating $f(x,y)$. Actually, I also find $Delta_s F$ and got the same.



      2) I can’t get the answer. Or the answer is 0. I am not sure. I was doing the same as in 1) Can somebody help me with this?










      share|cite|improve this question













      I have density function $f(x,y)=4xy mathbb{I}_{[0,1] times [0,1]}(x,y)$.



      I need to find:
      1) $mathbb{P}_F([0,1/3]times[0,1/2])$



      2) $mathbb{P}_F([2/3,1]timesmathbb{R})$



      So in 1) I got $1/36$ I don’t know is it right, but I was integrating $f(x,y)$. Actually, I also find $Delta_s F$ and got the same.



      2) I can’t get the answer. Or the answer is 0. I am not sure. I was doing the same as in 1) Can somebody help me with this?







      probability integration probability-theory density-function






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      asked Nov 28 '18 at 9:32









      Atstovas

      937




      937






















          1 Answer
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          Answer to 2) is $int_0^{1}int_{2/3}^{1} 4xy dx dy=5/9$.






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          • Got it! Thank you
            – Atstovas
            Nov 28 '18 at 9:44











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Answer to 2) is $int_0^{1}int_{2/3}^{1} 4xy dx dy=5/9$.






          share|cite|improve this answer





















          • Got it! Thank you
            – Atstovas
            Nov 28 '18 at 9:44
















          1














          Answer to 2) is $int_0^{1}int_{2/3}^{1} 4xy dx dy=5/9$.






          share|cite|improve this answer





















          • Got it! Thank you
            – Atstovas
            Nov 28 '18 at 9:44














          1












          1








          1






          Answer to 2) is $int_0^{1}int_{2/3}^{1} 4xy dx dy=5/9$.






          share|cite|improve this answer












          Answer to 2) is $int_0^{1}int_{2/3}^{1} 4xy dx dy=5/9$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 28 '18 at 9:36









          Kavi Rama Murthy

          50.7k31854




          50.7k31854












          • Got it! Thank you
            – Atstovas
            Nov 28 '18 at 9:44


















          • Got it! Thank you
            – Atstovas
            Nov 28 '18 at 9:44
















          Got it! Thank you
          – Atstovas
          Nov 28 '18 at 9:44




          Got it! Thank you
          – Atstovas
          Nov 28 '18 at 9:44


















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