Radical of an ideal using Macaulay2 software.
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What is the radical ideal of $(u^2v-a^3,uv^2-b^3,uv-ab)$ in $mathbb{C}[u,v,a,b]?$
Above all, to learn how to fish, what would be code that I can use to get the radical? I have not worked with Macaulay2 (computational algebra software) before, so what is a good reference to learn about?
commutative-algebra ideals math-software macaulay2
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add a comment |
$begingroup$
What is the radical ideal of $(u^2v-a^3,uv^2-b^3,uv-ab)$ in $mathbb{C}[u,v,a,b]?$
Above all, to learn how to fish, what would be code that I can use to get the radical? I have not worked with Macaulay2 (computational algebra software) before, so what is a good reference to learn about?
commutative-algebra ideals math-software macaulay2
$endgroup$
add a comment |
$begingroup$
What is the radical ideal of $(u^2v-a^3,uv^2-b^3,uv-ab)$ in $mathbb{C}[u,v,a,b]?$
Above all, to learn how to fish, what would be code that I can use to get the radical? I have not worked with Macaulay2 (computational algebra software) before, so what is a good reference to learn about?
commutative-algebra ideals math-software macaulay2
$endgroup$
What is the radical ideal of $(u^2v-a^3,uv^2-b^3,uv-ab)$ in $mathbb{C}[u,v,a,b]?$
Above all, to learn how to fish, what would be code that I can use to get the radical? I have not worked with Macaulay2 (computational algebra software) before, so what is a good reference to learn about?
commutative-algebra ideals math-software macaulay2
commutative-algebra ideals math-software macaulay2
edited Dec 8 '18 at 13:26
Rodrigo de Azevedo
13k41958
13k41958
asked Nov 30 '12 at 9:03
Ehsan M. KermaniEhsan M. Kermani
6,38412348
6,38412348
add a comment |
add a comment |
1 Answer
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The following code gives the radical of your ideal:
R = QQ[u,v,a,b]
I = ideal (u^2*v-a^3,u*v^2-b^3,u*v-a*b)
radI = radical I
So, according to Macaulay2, we have $sqrt{I} = (a^2-ub,va-b^2,uv-ab)$.
Beware, computing radicals can be extremely slow if you have many generators, because the algorithm must compute a Gröbner basis first. However, in this case, the ideal is binomial, and there are extremely efficient algorithms for computing with binomial ideals. (in Macaulay2, the package "BinomialIdeals" does this).
Some (two) references on how to learn Macaulay2:
The Macaulay2 homepage. Here are four guides that will teach you the basics. Follow them step-by-step.- The Macaulay2 book Computations in Algebraic Geometry with Macaulay2. Lots of examples. And the whole book is available free in all sorts of formats.
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Dear @Fredrik, thank you, it is very helpful.
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– Ehsan M. Kermani
Nov 30 '12 at 16:58
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By the way, could you add some references for learning how to use Macauley2?
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– Ehsan M. Kermani
Nov 30 '12 at 22:34
1
$begingroup$
@ehsanmo: Sure. I've added two helpful links. See the post.
$endgroup$
– Fredrik Meyer
Dec 1 '12 at 10:59
add a comment |
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1 Answer
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1 Answer
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$begingroup$
The following code gives the radical of your ideal:
R = QQ[u,v,a,b]
I = ideal (u^2*v-a^3,u*v^2-b^3,u*v-a*b)
radI = radical I
So, according to Macaulay2, we have $sqrt{I} = (a^2-ub,va-b^2,uv-ab)$.
Beware, computing radicals can be extremely slow if you have many generators, because the algorithm must compute a Gröbner basis first. However, in this case, the ideal is binomial, and there are extremely efficient algorithms for computing with binomial ideals. (in Macaulay2, the package "BinomialIdeals" does this).
Some (two) references on how to learn Macaulay2:
The Macaulay2 homepage. Here are four guides that will teach you the basics. Follow them step-by-step.- The Macaulay2 book Computations in Algebraic Geometry with Macaulay2. Lots of examples. And the whole book is available free in all sorts of formats.
$endgroup$
$begingroup$
Dear @Fredrik, thank you, it is very helpful.
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 16:58
$begingroup$
By the way, could you add some references for learning how to use Macauley2?
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 22:34
1
$begingroup$
@ehsanmo: Sure. I've added two helpful links. See the post.
$endgroup$
– Fredrik Meyer
Dec 1 '12 at 10:59
add a comment |
$begingroup$
The following code gives the radical of your ideal:
R = QQ[u,v,a,b]
I = ideal (u^2*v-a^3,u*v^2-b^3,u*v-a*b)
radI = radical I
So, according to Macaulay2, we have $sqrt{I} = (a^2-ub,va-b^2,uv-ab)$.
Beware, computing radicals can be extremely slow if you have many generators, because the algorithm must compute a Gröbner basis first. However, in this case, the ideal is binomial, and there are extremely efficient algorithms for computing with binomial ideals. (in Macaulay2, the package "BinomialIdeals" does this).
Some (two) references on how to learn Macaulay2:
The Macaulay2 homepage. Here are four guides that will teach you the basics. Follow them step-by-step.- The Macaulay2 book Computations in Algebraic Geometry with Macaulay2. Lots of examples. And the whole book is available free in all sorts of formats.
$endgroup$
$begingroup$
Dear @Fredrik, thank you, it is very helpful.
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 16:58
$begingroup$
By the way, could you add some references for learning how to use Macauley2?
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 22:34
1
$begingroup$
@ehsanmo: Sure. I've added two helpful links. See the post.
$endgroup$
– Fredrik Meyer
Dec 1 '12 at 10:59
add a comment |
$begingroup$
The following code gives the radical of your ideal:
R = QQ[u,v,a,b]
I = ideal (u^2*v-a^3,u*v^2-b^3,u*v-a*b)
radI = radical I
So, according to Macaulay2, we have $sqrt{I} = (a^2-ub,va-b^2,uv-ab)$.
Beware, computing radicals can be extremely slow if you have many generators, because the algorithm must compute a Gröbner basis first. However, in this case, the ideal is binomial, and there are extremely efficient algorithms for computing with binomial ideals. (in Macaulay2, the package "BinomialIdeals" does this).
Some (two) references on how to learn Macaulay2:
The Macaulay2 homepage. Here are four guides that will teach you the basics. Follow them step-by-step.- The Macaulay2 book Computations in Algebraic Geometry with Macaulay2. Lots of examples. And the whole book is available free in all sorts of formats.
$endgroup$
The following code gives the radical of your ideal:
R = QQ[u,v,a,b]
I = ideal (u^2*v-a^3,u*v^2-b^3,u*v-a*b)
radI = radical I
So, according to Macaulay2, we have $sqrt{I} = (a^2-ub,va-b^2,uv-ab)$.
Beware, computing radicals can be extremely slow if you have many generators, because the algorithm must compute a Gröbner basis first. However, in this case, the ideal is binomial, and there are extremely efficient algorithms for computing with binomial ideals. (in Macaulay2, the package "BinomialIdeals" does this).
Some (two) references on how to learn Macaulay2:
The Macaulay2 homepage. Here are four guides that will teach you the basics. Follow them step-by-step.- The Macaulay2 book Computations in Algebraic Geometry with Macaulay2. Lots of examples. And the whole book is available free in all sorts of formats.
edited Jun 27 '15 at 8:53
user26857
39.4k124183
39.4k124183
answered Nov 30 '12 at 10:14
Fredrik MeyerFredrik Meyer
15.3k24165
15.3k24165
$begingroup$
Dear @Fredrik, thank you, it is very helpful.
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 16:58
$begingroup$
By the way, could you add some references for learning how to use Macauley2?
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 22:34
1
$begingroup$
@ehsanmo: Sure. I've added two helpful links. See the post.
$endgroup$
– Fredrik Meyer
Dec 1 '12 at 10:59
add a comment |
$begingroup$
Dear @Fredrik, thank you, it is very helpful.
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 16:58
$begingroup$
By the way, could you add some references for learning how to use Macauley2?
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 22:34
1
$begingroup$
@ehsanmo: Sure. I've added two helpful links. See the post.
$endgroup$
– Fredrik Meyer
Dec 1 '12 at 10:59
$begingroup$
Dear @Fredrik, thank you, it is very helpful.
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 16:58
$begingroup$
Dear @Fredrik, thank you, it is very helpful.
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 16:58
$begingroup$
By the way, could you add some references for learning how to use Macauley2?
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 22:34
$begingroup$
By the way, could you add some references for learning how to use Macauley2?
$endgroup$
– Ehsan M. Kermani
Nov 30 '12 at 22:34
1
1
$begingroup$
@ehsanmo: Sure. I've added two helpful links. See the post.
$endgroup$
– Fredrik Meyer
Dec 1 '12 at 10:59
$begingroup$
@ehsanmo: Sure. I've added two helpful links. See the post.
$endgroup$
– Fredrik Meyer
Dec 1 '12 at 10:59
add a comment |
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