Proving Ratios And Proportions












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Help me solve this problem!
I have tried it many times but nothing appeared.
This is the question:
If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).










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    0












    $begingroup$


    Help me solve this problem!
    I have tried it many times but nothing appeared.
    This is the question:
    If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).










    share|cite|improve this question









    $endgroup$















      0












      0








      0





      $begingroup$


      Help me solve this problem!
      I have tried it many times but nothing appeared.
      This is the question:
      If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).










      share|cite|improve this question









      $endgroup$




      Help me solve this problem!
      I have tried it many times but nothing appeared.
      This is the question:
      If a:b=c:d=e:f, prove that each is equal to (a+c-e):(b+d-f).







      ratio






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      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Oct 16 '14 at 11:02









      Wilson Royce Ong KingWilson Royce Ong King

      1




      1






















          1 Answer
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          0












          $begingroup$

          Let $$frac ab=frac cd=frac ef=k$$



          $implies Xa+Yc+Ze=k(Xb+Yd+Zd)$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
            $endgroup$
            – Wilson Royce Ong King
            Oct 16 '14 at 11:09












          • $begingroup$
            @WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
            $endgroup$
            – lab bhattacharjee
            Oct 16 '14 at 11:16












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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0












          $begingroup$

          Let $$frac ab=frac cd=frac ef=k$$



          $implies Xa+Yc+Ze=k(Xb+Yd+Zd)$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
            $endgroup$
            – Wilson Royce Ong King
            Oct 16 '14 at 11:09












          • $begingroup$
            @WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
            $endgroup$
            – lab bhattacharjee
            Oct 16 '14 at 11:16
















          0












          $begingroup$

          Let $$frac ab=frac cd=frac ef=k$$



          $implies Xa+Yc+Ze=k(Xb+Yd+Zd)$






          share|cite|improve this answer









          $endgroup$













          • $begingroup$
            Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
            $endgroup$
            – Wilson Royce Ong King
            Oct 16 '14 at 11:09












          • $begingroup$
            @WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
            $endgroup$
            – lab bhattacharjee
            Oct 16 '14 at 11:16














          0












          0








          0





          $begingroup$

          Let $$frac ab=frac cd=frac ef=k$$



          $implies Xa+Yc+Ze=k(Xb+Yd+Zd)$






          share|cite|improve this answer









          $endgroup$



          Let $$frac ab=frac cd=frac ef=k$$



          $implies Xa+Yc+Ze=k(Xb+Yd+Zd)$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Oct 16 '14 at 11:04









          lab bhattacharjeelab bhattacharjee

          229k15159280




          229k15159280












          • $begingroup$
            Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
            $endgroup$
            – Wilson Royce Ong King
            Oct 16 '14 at 11:09












          • $begingroup$
            @WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
            $endgroup$
            – lab bhattacharjee
            Oct 16 '14 at 11:16


















          • $begingroup$
            Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
            $endgroup$
            – Wilson Royce Ong King
            Oct 16 '14 at 11:09












          • $begingroup$
            @WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
            $endgroup$
            – lab bhattacharjee
            Oct 16 '14 at 11:16
















          $begingroup$
          Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
          $endgroup$
          – Wilson Royce Ong King
          Oct 16 '14 at 11:09






          $begingroup$
          Thank you but I need more solution but my teacher left me clues and I don't know if it is correct or not: a/b=c/d=e/f=a+c-e/b+d-f a=bk, c=dk, e=fk and I don't know what to do next, please help.
          $endgroup$
          – Wilson Royce Ong King
          Oct 16 '14 at 11:09














          $begingroup$
          @WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
          $endgroup$
          – lab bhattacharjee
          Oct 16 '14 at 11:16




          $begingroup$
          @WilsonRoyceOngKing, Here $$X=Y=1, Z=-1$$
          $endgroup$
          – lab bhattacharjee
          Oct 16 '14 at 11:16


















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