Why boldmath fails in a tikz node?
7
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
asked 10 hours ago
RmanoRmano
8,34121649
add a comment |
7
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
asked 10 hours ago
RmanoRmano
8,34121649
5
boldmathis not deprecated.
– David Carlisle
10 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the;and the full definition ofboldmathis rather complicated so perhaps it is too much....
– David Carlisle
10 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
6 hours ago
Not only unofficial it is completely wrong.
– David Carlisle
6 hours ago
add a comment |
7
7
7
0
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
asked 10 hours ago
RmanoRmano
8,34121649
I think that probably boldmath is deprecated, although I can't find any "official" reference, but anyway:
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (0,0) node[draw]{boldmath (+)} (1,1);
end{tikzpicture}
end{document}
Fails to compile with a strange:
! Package tikz Error: Giving up on this path. Did you forget a semicolon?.
See the tikz package documentation for explanation.
Type H <return> for immediate help.
...
l.6 path (0,0) node[draw]{boldmath (+)}
(1,1);
?
If I double the braces in the node, as
path (0,0) node[draw]{{boldmath (+)}} (1,1);
it works ok:
Is this expected behavior?
tikz-pgf boldmath
tikz-pgf boldmath
asked 10 hours ago
RmanoRmano
8,34121649
asked 10 hours ago
RmanoRmano
8,34121649
asked 10 hours ago
RmanoRmano
8,34121649
asked 10 hours ago
RmanoRmano
8,34121649
asked 10 hours ago
RmanoRmano
8,34121649
8,34121649
5
boldmathis not deprecated.
– David Carlisle
10 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the;and the full definition ofboldmathis rather complicated so perhaps it is too much....
– David Carlisle
10 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
6 hours ago
Not only unofficial it is completely wrong.
– David Carlisle
6 hours ago
add a comment |
5
boldmathis not deprecated.
– David Carlisle
10 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the;and the full definition ofboldmathis rather complicated so perhaps it is too much....
– David Carlisle
10 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
6 hours ago
Not only unofficial it is completely wrong.
– David Carlisle
6 hours ago
5
5
boldmath is not deprecated.– David Carlisle
10 hours ago
boldmath is not deprecated.– David Carlisle
10 hours ago
4
4
I seem to recall that tikz only allows a certain number of expansions while looking for the
; and the full definition of boldmath is rather complicated so perhaps it is too much....– David Carlisle
10 hours ago
I seem to recall that tikz only allows a certain number of expansions while looking for the
; and the full definition of boldmath is rather complicated so perhaps it is too much....– David Carlisle
10 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
6 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
6 hours ago
Not only unofficial it is completely wrong.
– David Carlisle
6 hours ago
Not only unofficial it is completely wrong.
– David Carlisle
6 hours ago
add a comment |
1 Answer
1
active
oldest
votes
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
121k6159297
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "85"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f487777%2fwhy-boldmath-fails-in-a-tikz-node%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
121k6159297
add a comment |
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
121k6159297
add a comment |
4
4
4
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
121k6159297
TikZ has the key font (as well as node font for such things) with which it works.
documentclass[border=10pt]{standalone}
usepackage{tikz}
begin{document}
begin{tikzpicture}
path (1,0) node[draw,font=boldmath]{ (+)};
path (2,0) node[draw,node font=boldmath]{ (+)};
path (3,0) node[draw]{ (+)};
end{tikzpicture}
end{document}
answered 9 hours ago
marmotmarmot
121k6159297
answered 9 hours ago
marmotmarmot
121k6159297
answered 9 hours ago
marmotmarmot
121k6159297
answered 9 hours ago
marmotmarmot
121k6159297
121k6159297
add a comment |
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to TeX - LaTeX Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2ftex.stackexchange.com%2fquestions%2f487777%2fwhy-boldmath-fails-in-a-tikz-node%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
5
boldmathis not deprecated.– David Carlisle
10 hours ago
4
I seem to recall that tikz only allows a certain number of expansions while looking for the
;and the full definition ofboldmathis rather complicated so perhaps it is too much....– David Carlisle
10 hours ago
Ah, ok, I thought it was deprecated for this joshua.smcvt.edu/latex2e/… but I see this is not official...
– Rmano
6 hours ago
Not only unofficial it is completely wrong.
– David Carlisle
6 hours ago