Is this an unsolvable function composition problem? Or an absurd?
up vote
-1
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I am solving a PDE problem. In a certain point, I achieve the following equality:
$G(3x+1) = y^2 + e^x$
This is,basically, a problem involving function composition. How do I find $G(x)$?
I have faced similar problems needing to find $G(x)$. However, this equality looks like an absurd. I can't see a way to solve this.
Maybe I made a previous mistake before arriving to this line. But I have double checked my previous operations.
functions function-and-relation-composition
asked Nov 19 at 19:35
Pedro Delfino
735
add a comment |
up vote
-1
down vote
favorite
I am solving a PDE problem. In a certain point, I achieve the following equality:
$G(3x+1) = y^2 + e^x$
This is,basically, a problem involving function composition. How do I find $G(x)$?
I have faced similar problems needing to find $G(x)$. However, this equality looks like an absurd. I can't see a way to solve this.
Maybe I made a previous mistake before arriving to this line. But I have double checked my previous operations.
functions function-and-relation-composition
asked Nov 19 at 19:35
Pedro Delfino
735
1
Is $y$ a function of $x$ ?
– Yves Daoust
Nov 19 at 19:49
@YvesDaoust, I am not sure how to handle y in this exercise. It could be an independent variable, a dependent variable (f(x)=y) or an unknown constant. I am treating it as an unknown constant.
– Pedro Delfino
Nov 19 at 20:03
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I am solving a PDE problem. In a certain point, I achieve the following equality:
$G(3x+1) = y^2 + e^x$
This is,basically, a problem involving function composition. How do I find $G(x)$?
I have faced similar problems needing to find $G(x)$. However, this equality looks like an absurd. I can't see a way to solve this.
Maybe I made a previous mistake before arriving to this line. But I have double checked my previous operations.
functions function-and-relation-composition
asked Nov 19 at 19:35
Pedro Delfino
735
I am solving a PDE problem. In a certain point, I achieve the following equality:
$G(3x+1) = y^2 + e^x$
This is,basically, a problem involving function composition. How do I find $G(x)$?
I have faced similar problems needing to find $G(x)$. However, this equality looks like an absurd. I can't see a way to solve this.
Maybe I made a previous mistake before arriving to this line. But I have double checked my previous operations.
functions function-and-relation-composition
functions function-and-relation-composition
asked Nov 19 at 19:35
Pedro Delfino
735
asked Nov 19 at 19:35
Pedro Delfino
735
asked Nov 19 at 19:35
Pedro Delfino
735
asked Nov 19 at 19:35
Pedro Delfino
735
asked Nov 19 at 19:35
Pedro Delfino
735
735
1
Is $y$ a function of $x$ ?
– Yves Daoust
Nov 19 at 19:49
@YvesDaoust, I am not sure how to handle y in this exercise. It could be an independent variable, a dependent variable (f(x)=y) or an unknown constant. I am treating it as an unknown constant.
– Pedro Delfino
Nov 19 at 20:03
add a comment |
1
Is $y$ a function of $x$ ?
– Yves Daoust
Nov 19 at 19:49
@YvesDaoust, I am not sure how to handle y in this exercise. It could be an independent variable, a dependent variable (f(x)=y) or an unknown constant. I am treating it as an unknown constant.
– Pedro Delfino
Nov 19 at 20:03
1
1
Is $y$ a function of $x$ ?
– Yves Daoust
Nov 19 at 19:49
Is $y$ a function of $x$ ?
– Yves Daoust
Nov 19 at 19:49
@YvesDaoust, I am not sure how to handle y in this exercise. It could be an independent variable, a dependent variable (f(x)=y) or an unknown constant. I am treating it as an unknown constant.
– Pedro Delfino
Nov 19 at 20:03
@YvesDaoust, I am not sure how to handle y in this exercise. It could be an independent variable, a dependent variable (f(x)=y) or an unknown constant. I am treating it as an unknown constant.
– Pedro Delfino
Nov 19 at 20:03
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
You may write
$$G(x)=y^2+e^{(x-1)/3}.$$
answered Nov 19 at 19:50
Yves Daoust
122k668217
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You may write
$$G(x)=y^2+e^{(x-1)/3}.$$
answered Nov 19 at 19:50
Yves Daoust
122k668217
add a comment |
up vote
1
down vote
accepted
You may write
$$G(x)=y^2+e^{(x-1)/3}.$$
answered Nov 19 at 19:50
Yves Daoust
122k668217
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You may write
$$G(x)=y^2+e^{(x-1)/3}.$$
answered Nov 19 at 19:50
Yves Daoust
122k668217
You may write
$$G(x)=y^2+e^{(x-1)/3}.$$
answered Nov 19 at 19:50
Yves Daoust
122k668217
answered Nov 19 at 19:50
Yves Daoust
122k668217
answered Nov 19 at 19:50
Yves Daoust
122k668217
answered Nov 19 at 19:50
Yves Daoust
122k668217
122k668217
add a comment |
add a comment |
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1
Is $y$ a function of $x$ ?
– Yves Daoust
Nov 19 at 19:49
@YvesDaoust, I am not sure how to handle y in this exercise. It could be an independent variable, a dependent variable (f(x)=y) or an unknown constant. I am treating it as an unknown constant.
– Pedro Delfino
Nov 19 at 20:03