Fourier transform of delta(dirac) function-multiplication with exp function
$begingroup$
I am trying to find an integral of multiplication exponential function with a delta function.
I know a property of delta function that if I would like to take the integral of the multiplication delta function with function, I get this function:
begin{equation}
iint f(t)delta(t-a)=f(a)
end{equation}
Quastion 1 :
How to find :
begin{equation}
iint f(t)delta(t+a)=?
end{equation}
fourier-analysis dirac-delta fast-fourier-transform
$endgroup$
add a comment |
$begingroup$
I am trying to find an integral of multiplication exponential function with a delta function.
I know a property of delta function that if I would like to take the integral of the multiplication delta function with function, I get this function:
begin{equation}
iint f(t)delta(t-a)=f(a)
end{equation}
Quastion 1 :
How to find :
begin{equation}
iint f(t)delta(t+a)=?
end{equation}
fourier-analysis dirac-delta fast-fourier-transform
$endgroup$
$begingroup$
$$delta(t+a)=delta(t-(-a))$$
$endgroup$
– Fakemistake
Dec 8 '18 at 8:52
add a comment |
$begingroup$
I am trying to find an integral of multiplication exponential function with a delta function.
I know a property of delta function that if I would like to take the integral of the multiplication delta function with function, I get this function:
begin{equation}
iint f(t)delta(t-a)=f(a)
end{equation}
Quastion 1 :
How to find :
begin{equation}
iint f(t)delta(t+a)=?
end{equation}
fourier-analysis dirac-delta fast-fourier-transform
$endgroup$
I am trying to find an integral of multiplication exponential function with a delta function.
I know a property of delta function that if I would like to take the integral of the multiplication delta function with function, I get this function:
begin{equation}
iint f(t)delta(t-a)=f(a)
end{equation}
Quastion 1 :
How to find :
begin{equation}
iint f(t)delta(t+a)=?
end{equation}
fourier-analysis dirac-delta fast-fourier-transform
fourier-analysis dirac-delta fast-fourier-transform
asked Dec 8 '18 at 8:32
LenaParkLenaPark
83
83
$begingroup$
$$delta(t+a)=delta(t-(-a))$$
$endgroup$
– Fakemistake
Dec 8 '18 at 8:52
add a comment |
$begingroup$
$$delta(t+a)=delta(t-(-a))$$
$endgroup$
– Fakemistake
Dec 8 '18 at 8:52
$begingroup$
$$delta(t+a)=delta(t-(-a))$$
$endgroup$
– Fakemistake
Dec 8 '18 at 8:52
$begingroup$
$$delta(t+a)=delta(t-(-a))$$
$endgroup$
– Fakemistake
Dec 8 '18 at 8:52
add a comment |
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$begingroup$
$$delta(t+a)=delta(t-(-a))$$
$endgroup$
– Fakemistake
Dec 8 '18 at 8:52