Zero constant mean curvature in Minkowski space versus in Euclidean space












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There's a famous result in $mathbb{R}^3$ which goes as: there are no compact minimal surfaces in $mathbb{R}^3$.So the mean curvature cannot be zero in compact surfaces in $mathbb{R}^3$. Now what's the intuition behind why that isn't true in the Minkowski space $E_1^3$ (also known as $mathbb{L}^3$)?










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    $begingroup$


    There's a famous result in $mathbb{R}^3$ which goes as: there are no compact minimal surfaces in $mathbb{R}^3$.So the mean curvature cannot be zero in compact surfaces in $mathbb{R}^3$. Now what's the intuition behind why that isn't true in the Minkowski space $E_1^3$ (also known as $mathbb{L}^3$)?










    share|cite|improve this question









    $endgroup$















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      0





      $begingroup$


      There's a famous result in $mathbb{R}^3$ which goes as: there are no compact minimal surfaces in $mathbb{R}^3$.So the mean curvature cannot be zero in compact surfaces in $mathbb{R}^3$. Now what's the intuition behind why that isn't true in the Minkowski space $E_1^3$ (also known as $mathbb{L}^3$)?










      share|cite|improve this question









      $endgroup$




      There's a famous result in $mathbb{R}^3$ which goes as: there are no compact minimal surfaces in $mathbb{R}^3$.So the mean curvature cannot be zero in compact surfaces in $mathbb{R}^3$. Now what's the intuition behind why that isn't true in the Minkowski space $E_1^3$ (also known as $mathbb{L}^3$)?







      differential-geometry riemannian-geometry semi-riemannian-geometry






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      asked Dec 8 '18 at 8:14









      user71487user71487

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