Simple couter-example of preservation of Jordan-Chevalley decomposition











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I was going through chapter 9 of Fulton and Harris, as I am teaching the course, and ran across the example of the Lie algebra $mathbb{C}$, with the following representation:



begin{equation}
rho: t mapsto begin{pmatrix} t & t \ 0 & 0 end{pmatrix}
end{equation}



The book presents this as an example where the matrix is ``neither diagonalizable nor nilpotent'', and where neither the semisimple and nilpotent parts will be in the image of $rho$.
The point they want to showcase is how the semisimplicity of the Lie algebra is crucial.



I'm having trouble with this example, as the matrix in question is already semisimple as it stands.



Can anyone `fix' this example, or show me another neat representation of $mathbb{C}$ where J.C. decomposition is not preserved?










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    up vote
    2
    down vote

    favorite












    I was going through chapter 9 of Fulton and Harris, as I am teaching the course, and ran across the example of the Lie algebra $mathbb{C}$, with the following representation:



    begin{equation}
    rho: t mapsto begin{pmatrix} t & t \ 0 & 0 end{pmatrix}
    end{equation}



    The book presents this as an example where the matrix is ``neither diagonalizable nor nilpotent'', and where neither the semisimple and nilpotent parts will be in the image of $rho$.
    The point they want to showcase is how the semisimplicity of the Lie algebra is crucial.



    I'm having trouble with this example, as the matrix in question is already semisimple as it stands.



    Can anyone `fix' this example, or show me another neat representation of $mathbb{C}$ where J.C. decomposition is not preserved?










    share|cite|improve this question







    New contributor




    Andrés Collinucci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






















      up vote
      2
      down vote

      favorite









      up vote
      2
      down vote

      favorite











      I was going through chapter 9 of Fulton and Harris, as I am teaching the course, and ran across the example of the Lie algebra $mathbb{C}$, with the following representation:



      begin{equation}
      rho: t mapsto begin{pmatrix} t & t \ 0 & 0 end{pmatrix}
      end{equation}



      The book presents this as an example where the matrix is ``neither diagonalizable nor nilpotent'', and where neither the semisimple and nilpotent parts will be in the image of $rho$.
      The point they want to showcase is how the semisimplicity of the Lie algebra is crucial.



      I'm having trouble with this example, as the matrix in question is already semisimple as it stands.



      Can anyone `fix' this example, or show me another neat representation of $mathbb{C}$ where J.C. decomposition is not preserved?










      share|cite|improve this question







      New contributor




      Andrés Collinucci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      I was going through chapter 9 of Fulton and Harris, as I am teaching the course, and ran across the example of the Lie algebra $mathbb{C}$, with the following representation:



      begin{equation}
      rho: t mapsto begin{pmatrix} t & t \ 0 & 0 end{pmatrix}
      end{equation}



      The book presents this as an example where the matrix is ``neither diagonalizable nor nilpotent'', and where neither the semisimple and nilpotent parts will be in the image of $rho$.
      The point they want to showcase is how the semisimplicity of the Lie algebra is crucial.



      I'm having trouble with this example, as the matrix in question is already semisimple as it stands.



      Can anyone `fix' this example, or show me another neat representation of $mathbb{C}$ where J.C. decomposition is not preserved?







      representation-theory






      share|cite|improve this question







      New contributor




      Andrés Collinucci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|cite|improve this question







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      Check out our Code of Conduct.









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      asked Nov 16 at 11:51









      Andrés Collinucci

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      111




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      Andrés Collinucci is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          Sure, just take the representation $$t mapsto left( begin{matrix} t & t \ 0 & t end{matrix} right)=left( begin{matrix} t & 0 \ 0 & t end{matrix} right)+left( begin{matrix} 0 & t \ 0 & 0 end{matrix} right).$$






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          • Thanks! Nice and simple.
            – Andrés Collinucci
            2 days ago











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          Sure, just take the representation $$t mapsto left( begin{matrix} t & t \ 0 & t end{matrix} right)=left( begin{matrix} t & 0 \ 0 & t end{matrix} right)+left( begin{matrix} 0 & t \ 0 & 0 end{matrix} right).$$






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          • Thanks! Nice and simple.
            – Andrés Collinucci
            2 days ago















          up vote
          1
          down vote













          Sure, just take the representation $$t mapsto left( begin{matrix} t & t \ 0 & t end{matrix} right)=left( begin{matrix} t & 0 \ 0 & t end{matrix} right)+left( begin{matrix} 0 & t \ 0 & 0 end{matrix} right).$$






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          • Thanks! Nice and simple.
            – Andrés Collinucci
            2 days ago













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          up vote
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          down vote









          Sure, just take the representation $$t mapsto left( begin{matrix} t & t \ 0 & t end{matrix} right)=left( begin{matrix} t & 0 \ 0 & t end{matrix} right)+left( begin{matrix} 0 & t \ 0 & 0 end{matrix} right).$$






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          Sure, just take the representation $$t mapsto left( begin{matrix} t & t \ 0 & t end{matrix} right)=left( begin{matrix} t & 0 \ 0 & t end{matrix} right)+left( begin{matrix} 0 & t \ 0 & 0 end{matrix} right).$$







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          answered Nov 16 at 14:37









          Stephen

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          • Thanks! Nice and simple.
            – Andrés Collinucci
            2 days ago


















          • Thanks! Nice and simple.
            – Andrés Collinucci
            2 days ago
















          Thanks! Nice and simple.
          – Andrés Collinucci
          2 days ago




          Thanks! Nice and simple.
          – Andrés Collinucci
          2 days ago










          Andrés Collinucci is a new contributor. Be nice, and check out our Code of Conduct.










           

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