Does $int_1^infty f(x)ln(x)dx$ converge if $int_1^infty f(x)dx $ converges?











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Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!










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    Below you will find a hint. Please show your effort and share with us your thoughts.
    – Robert Z
    Nov 24 at 16:21















up vote
-3
down vote

favorite












Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!










share|cite|improve this question




















  • 1




    Below you will find a hint. Please show your effort and share with us your thoughts.
    – Robert Z
    Nov 24 at 16:21













up vote
-3
down vote

favorite









up vote
-3
down vote

favorite











Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!










share|cite|improve this question















Suppose a function $f:[1,infty)tomathbb R$ is such that $int_1^infty f(x),dx $ converges. Is it possible that $$int_1^infty f(x)ln(x),dx $$ diverges? I have a hard time finding such a function.

Edit: no idea why, but I had just thought naively (without checking) that $int frac 1{xln^k(x)},dx $ diverges for all $k$ just because $int frac 1{xln(x)},dx $ diverges. Sorry!







calculus integration convergence






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edited Nov 24 at 19:54

























asked Nov 24 at 16:16









Wolfgang

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320612








  • 1




    Below you will find a hint. Please show your effort and share with us your thoughts.
    – Robert Z
    Nov 24 at 16:21














  • 1




    Below you will find a hint. Please show your effort and share with us your thoughts.
    – Robert Z
    Nov 24 at 16:21








1




1




Below you will find a hint. Please show your effort and share with us your thoughts.
– Robert Z
Nov 24 at 16:21




Below you will find a hint. Please show your effort and share with us your thoughts.
– Robert Z
Nov 24 at 16:21










1 Answer
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Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






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    1 Answer
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    active

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

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    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



    Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






    share|cite|improve this answer

























      up vote
      1
      down vote



      accepted










      Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



      Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






      share|cite|improve this answer























        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



        Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?






        share|cite|improve this answer












        Hint. Consider the function $$f(x)=frac{1}{xln^2(1+x)}.$$



        Is $int_1^infty f(x)dx$ convergent? What about $int_1^infty f(x)ln(x) dx$?







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 24 at 16:19









        Robert Z

        92.7k1060130




        92.7k1060130






























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