When running a command on a file, is there any way to reference the file without typing the entire name?
up vote
4
down vote
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For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
edited 34 mins ago
SeldomNeedy
1436
asked 8 hours ago
user327021
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up vote
4
down vote
favorite
For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
edited 34 mins ago
SeldomNeedy
1436
asked 8 hours ago
user327021
211
New contributor
user327021 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
up vote
4
down vote
favorite
up vote
4
down vote
favorite
For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
edited 34 mins ago
SeldomNeedy
1436
asked 8 hours ago
user327021
211
New contributor
user327021 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
For example:
tar xvf test.tar.gz ; rm test.tar.gz
Is there a faster way to reference the file name on the second execution?
I was thinking something like this (which is invalid):
tar xvf test.tar.gz ; rm $1
Anything possible?
I'm fully aware of wildcards.
bash
bash
edited 34 mins ago
SeldomNeedy
1436
asked 8 hours ago
user327021
211
New contributor
user327021 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 34 mins ago
SeldomNeedy
1436
asked 8 hours ago
user327021
211
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edited 34 mins ago
SeldomNeedy
1436
edited 34 mins ago
SeldomNeedy
1436
edited 34 mins ago
SeldomNeedy
1436
1436
asked 8 hours ago
user327021
211
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asked 8 hours ago
user327021
211
asked 8 hours ago
user327021
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211
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2 Answers
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up vote
9
down vote
You could assign the filename to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_ special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
This works with multiple commands too, as long as the filename is always the last argument to the commands (e.g. echo foo; echo $_; echo $_ prints three times foo.)
As an aside, you may want to consider using tar ... && rm ..., i.e. with the && operator instead of a semicolon. That way, the rm will not run if the first command fails.
answered 8 hours ago
ilkkachu
54.9k782149
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
6 hours ago
add a comment |
up vote
2
down vote
You can use !$ if you move the second command to a new line.
tar xvf test.tar.gz
rm !$
edited 2 hours ago
guntbert
1,0371917
answered 2 hours ago
RiaD
1215
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
9
down vote
You could assign the filename to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_ special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
This works with multiple commands too, as long as the filename is always the last argument to the commands (e.g. echo foo; echo $_; echo $_ prints three times foo.)
As an aside, you may want to consider using tar ... && rm ..., i.e. with the && operator instead of a semicolon. That way, the rm will not run if the first command fails.
answered 8 hours ago
ilkkachu
54.9k782149
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
6 hours ago
add a comment |
up vote
9
down vote
You could assign the filename to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_ special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
This works with multiple commands too, as long as the filename is always the last argument to the commands (e.g. echo foo; echo $_; echo $_ prints three times foo.)
As an aside, you may want to consider using tar ... && rm ..., i.e. with the && operator instead of a semicolon. That way, the rm will not run if the first command fails.
answered 8 hours ago
ilkkachu
54.9k782149
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
6 hours ago
add a comment |
up vote
9
down vote
up vote
9
down vote
You could assign the filename to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_ special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
This works with multiple commands too, as long as the filename is always the last argument to the commands (e.g. echo foo; echo $_; echo $_ prints three times foo.)
As an aside, you may want to consider using tar ... && rm ..., i.e. with the && operator instead of a semicolon. That way, the rm will not run if the first command fails.
answered 8 hours ago
ilkkachu
54.9k782149
You could assign the filename to a variable first:
f=test.tar.gz; tar xvf "$f"; rm "$f"
Or use the $_ special parameter, it contains the last word of the previous command, which is often (but of course not always) the filename you've been working with:
tar xvf test.tar.gz; rm "$_"
This works with multiple commands too, as long as the filename is always the last argument to the commands (e.g. echo foo; echo $_; echo $_ prints three times foo.)
As an aside, you may want to consider using tar ... && rm ..., i.e. with the && operator instead of a semicolon. That way, the rm will not run if the first command fails.
answered 8 hours ago
ilkkachu
54.9k782149
edited 2 hours ago
answered 8 hours ago
ilkkachu
54.9k782149
answered 8 hours ago
ilkkachu
54.9k782149
answered 8 hours ago
ilkkachu
54.9k782149
54.9k782149
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
6 hours ago
add a comment |
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
6 hours ago
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
6 hours ago
Loved “$_” didn’t knew about it! Thanks a lot for your contribution, well put!
– Marco
6 hours ago
add a comment |
up vote
2
down vote
You can use !$ if you move the second command to a new line.
tar xvf test.tar.gz
rm !$
edited 2 hours ago
guntbert
1,0371917
answered 2 hours ago
RiaD
1215
New contributor
RiaD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
2
down vote
You can use !$ if you move the second command to a new line.
tar xvf test.tar.gz
rm !$
edited 2 hours ago
guntbert
1,0371917
answered 2 hours ago
RiaD
1215
New contributor
RiaD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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up vote
2
down vote
up vote
2
down vote
You can use !$ if you move the second command to a new line.
tar xvf test.tar.gz
rm !$
edited 2 hours ago
guntbert
1,0371917
answered 2 hours ago
RiaD
1215
New contributor
RiaD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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You can use !$ if you move the second command to a new line.
tar xvf test.tar.gz
rm !$
edited 2 hours ago
guntbert
1,0371917
answered 2 hours ago
RiaD
1215
New contributor
RiaD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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edited 2 hours ago
guntbert
1,0371917
edited 2 hours ago
guntbert
1,0371917
edited 2 hours ago
guntbert
1,0371917
1,0371917
answered 2 hours ago
RiaD
1215
New contributor
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answered 2 hours ago
RiaD
1215
answered 2 hours ago
RiaD
1215
1215
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New contributor
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