Inequality proof (Hilbert space)
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Show that if H is a Hilbert space, then: $$Vert(x+y)Vert^2 - Vert(x - y)Vert^2 le 4 Vert xVert Vert yVert, $$ for all $x, y in H. $
inequality hilbert-spaces
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Show that if H is a Hilbert space, then: $$Vert(x+y)Vert^2 - Vert(x - y)Vert^2 le 4 Vert xVert Vert yVert, $$ for all $x, y in H. $
inequality hilbert-spaces
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up vote
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down vote
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Show that if H is a Hilbert space, then: $$Vert(x+y)Vert^2 - Vert(x - y)Vert^2 le 4 Vert xVert Vert yVert, $$ for all $x, y in H. $
inequality hilbert-spaces
Show that if H is a Hilbert space, then: $$Vert(x+y)Vert^2 - Vert(x - y)Vert^2 le 4 Vert xVert Vert yVert, $$ for all $x, y in H. $
inequality hilbert-spaces
inequality hilbert-spaces
asked Nov 24 at 17:02
Loreen
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Observe that
$$ Vert xpm yVert^2 = langle xpm y,xpm y rangle = Vert x Vert^2 pm 2Re langle x, y rangle + Vert yVert^2, $$
so that
$$ Vert x + yVert^2 - Vert x - yVert^2 = 4 Relangle x, y rangle. $$
Now apply Cauchy-Schwarz.
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
Observe that
$$ Vert xpm yVert^2 = langle xpm y,xpm y rangle = Vert x Vert^2 pm 2Re langle x, y rangle + Vert yVert^2, $$
so that
$$ Vert x + yVert^2 - Vert x - yVert^2 = 4 Relangle x, y rangle. $$
Now apply Cauchy-Schwarz.
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up vote
0
down vote
accepted
Observe that
$$ Vert xpm yVert^2 = langle xpm y,xpm y rangle = Vert x Vert^2 pm 2Re langle x, y rangle + Vert yVert^2, $$
so that
$$ Vert x + yVert^2 - Vert x - yVert^2 = 4 Relangle x, y rangle. $$
Now apply Cauchy-Schwarz.
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up vote
0
down vote
accepted
up vote
0
down vote
accepted
Observe that
$$ Vert xpm yVert^2 = langle xpm y,xpm y rangle = Vert x Vert^2 pm 2Re langle x, y rangle + Vert yVert^2, $$
so that
$$ Vert x + yVert^2 - Vert x - yVert^2 = 4 Relangle x, y rangle. $$
Now apply Cauchy-Schwarz.
Observe that
$$ Vert xpm yVert^2 = langle xpm y,xpm y rangle = Vert x Vert^2 pm 2Re langle x, y rangle + Vert yVert^2, $$
so that
$$ Vert x + yVert^2 - Vert x - yVert^2 = 4 Relangle x, y rangle. $$
Now apply Cauchy-Schwarz.
answered Nov 24 at 17:06
MisterRiemann
5,7291624
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