if $f'(c)<0$ then there exists a nbd $I$ of $c$ such that $f'(x)<0$ for all $xin I$











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I have been trying to prove the statement:




Let $Dsubset mathbb{R}$ and $fcolon Dtomathbb{R}$.If $f'(c)<0$ then there exists a nbd $I$ of $c$ such that $f'(x)<0$
for all $xin I$.




Here's my attempt:



Let $S:={|x-c| : f'(x)ge 0 text{for some } xin D}$. Clearly, $S$ is bounded below by $0$. Now if $S$ is empty, then for all $x in D$, we have $f'(x) <0$ and we are done. Now, suppose that $S$ is not empty. Then let $delta := inf S$. Now, we have that for all $|x-c| < delta$, $|f'(x)|<0$.



Is this proof okay? Or did I go wrong? Alternative proofs?










share|cite|improve this question
























  • You need to specify what $D$ is, and any assumptions on $f$
    – user25959
    Nov 24 at 16:30










  • What if $delta = 0$?
    – xbh
    Nov 24 at 16:32










  • @xbh it seems i did not consider that. The answer below disprove my statement.
    – Ashish K
    Nov 24 at 16:49















up vote
-1
down vote

favorite












I have been trying to prove the statement:




Let $Dsubset mathbb{R}$ and $fcolon Dtomathbb{R}$.If $f'(c)<0$ then there exists a nbd $I$ of $c$ such that $f'(x)<0$
for all $xin I$.




Here's my attempt:



Let $S:={|x-c| : f'(x)ge 0 text{for some } xin D}$. Clearly, $S$ is bounded below by $0$. Now if $S$ is empty, then for all $x in D$, we have $f'(x) <0$ and we are done. Now, suppose that $S$ is not empty. Then let $delta := inf S$. Now, we have that for all $|x-c| < delta$, $|f'(x)|<0$.



Is this proof okay? Or did I go wrong? Alternative proofs?










share|cite|improve this question
























  • You need to specify what $D$ is, and any assumptions on $f$
    – user25959
    Nov 24 at 16:30










  • What if $delta = 0$?
    – xbh
    Nov 24 at 16:32










  • @xbh it seems i did not consider that. The answer below disprove my statement.
    – Ashish K
    Nov 24 at 16:49













up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I have been trying to prove the statement:




Let $Dsubset mathbb{R}$ and $fcolon Dtomathbb{R}$.If $f'(c)<0$ then there exists a nbd $I$ of $c$ such that $f'(x)<0$
for all $xin I$.




Here's my attempt:



Let $S:={|x-c| : f'(x)ge 0 text{for some } xin D}$. Clearly, $S$ is bounded below by $0$. Now if $S$ is empty, then for all $x in D$, we have $f'(x) <0$ and we are done. Now, suppose that $S$ is not empty. Then let $delta := inf S$. Now, we have that for all $|x-c| < delta$, $|f'(x)|<0$.



Is this proof okay? Or did I go wrong? Alternative proofs?










share|cite|improve this question















I have been trying to prove the statement:




Let $Dsubset mathbb{R}$ and $fcolon Dtomathbb{R}$.If $f'(c)<0$ then there exists a nbd $I$ of $c$ such that $f'(x)<0$
for all $xin I$.




Here's my attempt:



Let $S:={|x-c| : f'(x)ge 0 text{for some } xin D}$. Clearly, $S$ is bounded below by $0$. Now if $S$ is empty, then for all $x in D$, we have $f'(x) <0$ and we are done. Now, suppose that $S$ is not empty. Then let $delta := inf S$. Now, we have that for all $|x-c| < delta$, $|f'(x)|<0$.



Is this proof okay? Or did I go wrong? Alternative proofs?







real-analysis proof-verification alternative-proof






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share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Nov 24 at 16:57

























asked Nov 24 at 16:22









Ashish K

776513




776513












  • You need to specify what $D$ is, and any assumptions on $f$
    – user25959
    Nov 24 at 16:30










  • What if $delta = 0$?
    – xbh
    Nov 24 at 16:32










  • @xbh it seems i did not consider that. The answer below disprove my statement.
    – Ashish K
    Nov 24 at 16:49


















  • You need to specify what $D$ is, and any assumptions on $f$
    – user25959
    Nov 24 at 16:30










  • What if $delta = 0$?
    – xbh
    Nov 24 at 16:32










  • @xbh it seems i did not consider that. The answer below disprove my statement.
    – Ashish K
    Nov 24 at 16:49
















You need to specify what $D$ is, and any assumptions on $f$
– user25959
Nov 24 at 16:30




You need to specify what $D$ is, and any assumptions on $f$
– user25959
Nov 24 at 16:30












What if $delta = 0$?
– xbh
Nov 24 at 16:32




What if $delta = 0$?
– xbh
Nov 24 at 16:32












@xbh it seems i did not consider that. The answer below disprove my statement.
– Ashish K
Nov 24 at 16:49




@xbh it seems i did not consider that. The answer below disprove my statement.
– Ashish K
Nov 24 at 16:49










1 Answer
1






active

oldest

votes

















up vote
2
down vote



accepted










It's not true. Take
$$
f(x)=cases{x^2sin(1/x)+x/2& if $xneq0$\0& otherwise}
$$

Then $f'(0)=0.5$, but for there are $x$ arbitrarily close to $0$ such that $f'(x)=-0.5$.






share|cite|improve this answer





















  • Hey, can you expand it a bit more? My statement seeks $f'(c)<0$ but for $f'(0)=0.5>0$?
    – Ashish K
    Nov 24 at 16:53











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
2
down vote



accepted










It's not true. Take
$$
f(x)=cases{x^2sin(1/x)+x/2& if $xneq0$\0& otherwise}
$$

Then $f'(0)=0.5$, but for there are $x$ arbitrarily close to $0$ such that $f'(x)=-0.5$.






share|cite|improve this answer





















  • Hey, can you expand it a bit more? My statement seeks $f'(c)<0$ but for $f'(0)=0.5>0$?
    – Ashish K
    Nov 24 at 16:53















up vote
2
down vote



accepted










It's not true. Take
$$
f(x)=cases{x^2sin(1/x)+x/2& if $xneq0$\0& otherwise}
$$

Then $f'(0)=0.5$, but for there are $x$ arbitrarily close to $0$ such that $f'(x)=-0.5$.






share|cite|improve this answer





















  • Hey, can you expand it a bit more? My statement seeks $f'(c)<0$ but for $f'(0)=0.5>0$?
    – Ashish K
    Nov 24 at 16:53













up vote
2
down vote



accepted







up vote
2
down vote



accepted






It's not true. Take
$$
f(x)=cases{x^2sin(1/x)+x/2& if $xneq0$\0& otherwise}
$$

Then $f'(0)=0.5$, but for there are $x$ arbitrarily close to $0$ such that $f'(x)=-0.5$.






share|cite|improve this answer












It's not true. Take
$$
f(x)=cases{x^2sin(1/x)+x/2& if $xneq0$\0& otherwise}
$$

Then $f'(0)=0.5$, but for there are $x$ arbitrarily close to $0$ such that $f'(x)=-0.5$.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Nov 24 at 16:31









Arthur

110k7105186




110k7105186












  • Hey, can you expand it a bit more? My statement seeks $f'(c)<0$ but for $f'(0)=0.5>0$?
    – Ashish K
    Nov 24 at 16:53


















  • Hey, can you expand it a bit more? My statement seeks $f'(c)<0$ but for $f'(0)=0.5>0$?
    – Ashish K
    Nov 24 at 16:53
















Hey, can you expand it a bit more? My statement seeks $f'(c)<0$ but for $f'(0)=0.5>0$?
– Ashish K
Nov 24 at 16:53




Hey, can you expand it a bit more? My statement seeks $f'(c)<0$ but for $f'(0)=0.5>0$?
– Ashish K
Nov 24 at 16:53


















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