Find $a^3 + b^3 +c^3, $ given $a+b+c=12$ and $a^3 cdot b^4 cdot c^5 = 0.1 cdot (600)^3$
1
$begingroup$
$a+b+c=12$ and $a^3 cdot b^4 cdot c^5 = 0.1 cdot (600)^3$ . Find $a^3 + b^3 +c^3 = ?$ My approach is to use AM-GM inequality. Is it correct?
a.m.-g.m.-inequality
share | cite | improve this question
edited Dec 19 '18 at 15:58
Namaste
1
asked Dec 19 '18 at 14:56
Mark 7 Mark 7
9 5
$endgroup$