How to get last integers of a number?
3
I have a number such as:
a=875952;
And I want to get last 3 numbers of a. I have tried this:
Take[IntegerDigits[a],-3];
I get {9,5,2}
And is there a concise way to get it?
functions
asked 2 hours ago
user61054
484
add a comment |
3
I have a number such as:
a=875952;
And I want to get last 3 numbers of a. I have tried this:
Take[IntegerDigits[a],-3];
I get {9,5,2}
And is there a concise way to get it?
functions
asked 2 hours ago
user61054
484
add a comment |
3
3
3
I have a number such as:
a=875952;
And I want to get last 3 numbers of a. I have tried this:
Take[IntegerDigits[a],-3];
I get {9,5,2}
And is there a concise way to get it?
functions
asked 2 hours ago
user61054
484
I have a number such as:
a=875952;
And I want to get last 3 numbers of a. I have tried this:
Take[IntegerDigits[a],-3];
I get {9,5,2}
And is there a concise way to get it?
functions
functions
asked 2 hours ago
user61054
484
asked 2 hours ago
user61054
484
asked 2 hours ago
user61054
484
asked 2 hours ago
user61054
484
asked 2 hours ago
user61054
484
484
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
5
You can use Part:
IntegerDigits[a][[-3 ;;]]
{9, 5, 2}
Update:
"Actually I want to see whether a is divisible by 1000"
Use Divisible:
Divisible[a, 1000]
False
answered 2 hours ago
kglr
176k9198404
add a comment |
4
It depends whether you want a three-digit number, in which case try using Mod, as in:
Mod[a, 1000]
If you want a List of the digits, then the other solutions above work fine.
If your goal is instead to see whether a is (evenly) divisible by 1000, then:
Mod[a,1000] == 0
yields a True or False.
answered 2 hours ago
David G. Stork
23k22051
Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
– user61054
2 hours ago
2
A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
– David G. Stork
2 hours ago
@DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
– The Great Duck
10 mins ago
@TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
– David G. Stork
7 mins ago
@DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
– The Great Duck
5 mins ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
You can use Part:
IntegerDigits[a][[-3 ;;]]
{9, 5, 2}
Update:
"Actually I want to see whether a is divisible by 1000"
Use Divisible:
Divisible[a, 1000]
False
answered 2 hours ago
kglr
176k9198404
add a comment |
5
You can use Part:
IntegerDigits[a][[-3 ;;]]
{9, 5, 2}
Update:
"Actually I want to see whether a is divisible by 1000"
Use Divisible:
Divisible[a, 1000]
False
answered 2 hours ago
kglr
176k9198404
add a comment |
5
5
5
You can use Part:
IntegerDigits[a][[-3 ;;]]
{9, 5, 2}
Update:
"Actually I want to see whether a is divisible by 1000"
Use Divisible:
Divisible[a, 1000]
False
answered 2 hours ago
kglr
176k9198404
You can use Part:
IntegerDigits[a][[-3 ;;]]
{9, 5, 2}
Update:
"Actually I want to see whether a is divisible by 1000"
Use Divisible:
Divisible[a, 1000]
False
answered 2 hours ago
kglr
176k9198404
edited 2 hours ago
answered 2 hours ago
kglr
176k9198404
answered 2 hours ago
kglr
176k9198404
answered 2 hours ago
kglr
176k9198404
176k9198404
add a comment |
add a comment |
4
It depends whether you want a three-digit number, in which case try using Mod, as in:
Mod[a, 1000]
If you want a List of the digits, then the other solutions above work fine.
If your goal is instead to see whether a is (evenly) divisible by 1000, then:
Mod[a,1000] == 0
yields a True or False.
answered 2 hours ago
David G. Stork
23k22051
Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
– user61054
2 hours ago
2
A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
– David G. Stork
2 hours ago
@DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
– The Great Duck
10 mins ago
@TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
– David G. Stork
7 mins ago
@DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
– The Great Duck
5 mins ago
add a comment |
4
It depends whether you want a three-digit number, in which case try using Mod, as in:
Mod[a, 1000]
If you want a List of the digits, then the other solutions above work fine.
If your goal is instead to see whether a is (evenly) divisible by 1000, then:
Mod[a,1000] == 0
yields a True or False.
answered 2 hours ago
David G. Stork
23k22051
Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
– user61054
2 hours ago
2
A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
– David G. Stork
2 hours ago
@DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
– The Great Duck
10 mins ago
@TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
– David G. Stork
7 mins ago
@DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
– The Great Duck
5 mins ago
add a comment |
4
4
4
It depends whether you want a three-digit number, in which case try using Mod, as in:
Mod[a, 1000]
If you want a List of the digits, then the other solutions above work fine.
If your goal is instead to see whether a is (evenly) divisible by 1000, then:
Mod[a,1000] == 0
yields a True or False.
answered 2 hours ago
David G. Stork
23k22051
It depends whether you want a three-digit number, in which case try using Mod, as in:
Mod[a, 1000]
If you want a List of the digits, then the other solutions above work fine.
If your goal is instead to see whether a is (evenly) divisible by 1000, then:
Mod[a,1000] == 0
yields a True or False.
answered 2 hours ago
David G. Stork
23k22051
edited 2 hours ago
answered 2 hours ago
David G. Stork
23k22051
answered 2 hours ago
David G. Stork
23k22051
answered 2 hours ago
David G. Stork
23k22051
23k22051
Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
– user61054
2 hours ago
2
A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
– David G. Stork
2 hours ago
@DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
– The Great Duck
10 mins ago
@TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
– David G. Stork
7 mins ago
@DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
– The Great Duck
5 mins ago
add a comment |
Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
– user61054
2 hours ago
2
A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
– David G. Stork
2 hours ago
@DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
– The Great Duck
10 mins ago
@TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
– David G. Stork
7 mins ago
@DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
– The Great Duck
5 mins ago
Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
– user61054
2 hours ago
Actually I want to see whether a is divisable by 1000, my ways is to judge the last number of a. But it seems complex. Do you have other ways? thanks.
– user61054
2 hours ago
2
2
A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
– David G. Stork
2 hours ago
A recommendation: Always ask your actual question, rather than an intermediate question. You're more likely to get better answers.
– David G. Stork
2 hours ago
@DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
– The Great Duck
10 mins ago
@DavidG.Stork but what if by last 3 digits we mean last 3 digits of even decimal fractions such as 13.535 returning 535 or the list {5,3,5} or any other equivalent representation? Right now your formula gives the last three whole number place values along with the decimal fraction. (And yes, I can see the askers usage/intention was something very different but it would be interesting to see a more precise answer to the original question.)
– The Great Duck
10 mins ago
@TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
– David G. Stork
7 mins ago
@TheGreatDuck: The OP is rather confused about what is desired: "Actually I want to see whether $a$ is divisable by 1000." I tried to answer his actual question. If the OP wants something different, I'm happy to address that.
– David G. Stork
7 mins ago
@DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
– The Great Duck
5 mins ago
@DavidG.Stork no the op asked a completely different question in the comments. The desired question is what is posted in the question at the top of this page which asks for how "to get last 3 numbers of a". Your first formula does not do that. Any fraction will not return 3 numbers with that formula.
– The Great Duck
5 mins ago
add a comment |
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