Equilateral triangles with $3$ vertex in a regular hexagon
The problem is: What is the probability of making an inscribed equilateral triangle, taking $3$ vertex of a regular hexagon?.
I think the answer is $1/10$ but i don't know how to do it with combinatorics.
combinatorics
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
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The problem is: What is the probability of making an inscribed equilateral triangle, taking $3$ vertex of a regular hexagon?.
I think the answer is $1/10$ but i don't know how to do it with combinatorics.
combinatorics
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
add a comment |
The problem is: What is the probability of making an inscribed equilateral triangle, taking $3$ vertex of a regular hexagon?.
I think the answer is $1/10$ but i don't know how to do it with combinatorics.
combinatorics
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
The problem is: What is the probability of making an inscribed equilateral triangle, taking $3$ vertex of a regular hexagon?.
I think the answer is $1/10$ but i don't know how to do it with combinatorics.
combinatorics
combinatorics
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
asked Nov 27 '18 at 16:38
Rodrigo Pizarro
834217
834217
add a comment |
add a comment |
1 Answer
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HINT
In a regular hexagon $ABCDEF$, you pick 3 vertices (order is not important). If you pick $ACE$ or $BDF$, you end up with equilateral triangle you desire.
- How many total vertex selections are possible?
- What is the probability of getting the desired result?
answered Nov 27 '18 at 16:49
gt6989b
33k22452
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
HINT
In a regular hexagon $ABCDEF$, you pick 3 vertices (order is not important). If you pick $ACE$ or $BDF$, you end up with equilateral triangle you desire.
- How many total vertex selections are possible?
- What is the probability of getting the desired result?
answered Nov 27 '18 at 16:49
gt6989b
33k22452
add a comment |
HINT
In a regular hexagon $ABCDEF$, you pick 3 vertices (order is not important). If you pick $ACE$ or $BDF$, you end up with equilateral triangle you desire.
- How many total vertex selections are possible?
- What is the probability of getting the desired result?
answered Nov 27 '18 at 16:49
gt6989b
33k22452
add a comment |
HINT
In a regular hexagon $ABCDEF$, you pick 3 vertices (order is not important). If you pick $ACE$ or $BDF$, you end up with equilateral triangle you desire.
- How many total vertex selections are possible?
- What is the probability of getting the desired result?
answered Nov 27 '18 at 16:49
gt6989b
33k22452
HINT
In a regular hexagon $ABCDEF$, you pick 3 vertices (order is not important). If you pick $ACE$ or $BDF$, you end up with equilateral triangle you desire.
- How many total vertex selections are possible?
- What is the probability of getting the desired result?
answered Nov 27 '18 at 16:49
gt6989b
33k22452
answered Nov 27 '18 at 16:49
gt6989b
33k22452
answered Nov 27 '18 at 16:49
gt6989b
33k22452
answered Nov 27 '18 at 16:49
gt6989b
33k22452
33k22452
add a comment |
add a comment |
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