Example Of A Non-Existent Retract
I am looking for an example that disproves the claim that given any subspace $A$ of a topological space $X$, there exists a retract of $X$ onto $A$.
general-topology algebraic-topology
add a comment |
I am looking for an example that disproves the claim that given any subspace $A$ of a topological space $X$, there exists a retract of $X$ onto $A$.
general-topology algebraic-topology
3
$S^1 subset mathbb{R}^2$
– Tim kinsella
Nov 26 at 1:41
1
How about the closed unit disk and the unit circle?
– ncmathsadist
Nov 26 at 1:41
Oh, duh, of course. Silly me. Thank you.
– Frederic Chopin
Nov 26 at 1:43
not silly -- its not at all obvious unless you think about it in terms of $pi_1$. $X$ retracts onto $A$ only if $pi_1(A)$ is a subgroup of $pi_1(X)$.
– Tim kinsella
Nov 26 at 2:07
That's true. But I was thinking indeed about it in terms of the fundamental group, so recalling that the homomorphism induced by the inclusion map is an injection if the space retracts onto some subspace makes this example clear immediately.
– Frederic Chopin
Nov 26 at 2:11
add a comment |
I am looking for an example that disproves the claim that given any subspace $A$ of a topological space $X$, there exists a retract of $X$ onto $A$.
general-topology algebraic-topology
I am looking for an example that disproves the claim that given any subspace $A$ of a topological space $X$, there exists a retract of $X$ onto $A$.
general-topology algebraic-topology
general-topology algebraic-topology
asked Nov 26 at 1:39
Frederic Chopin
322111
322111
3
$S^1 subset mathbb{R}^2$
– Tim kinsella
Nov 26 at 1:41
1
How about the closed unit disk and the unit circle?
– ncmathsadist
Nov 26 at 1:41
Oh, duh, of course. Silly me. Thank you.
– Frederic Chopin
Nov 26 at 1:43
not silly -- its not at all obvious unless you think about it in terms of $pi_1$. $X$ retracts onto $A$ only if $pi_1(A)$ is a subgroup of $pi_1(X)$.
– Tim kinsella
Nov 26 at 2:07
That's true. But I was thinking indeed about it in terms of the fundamental group, so recalling that the homomorphism induced by the inclusion map is an injection if the space retracts onto some subspace makes this example clear immediately.
– Frederic Chopin
Nov 26 at 2:11
add a comment |
3
$S^1 subset mathbb{R}^2$
– Tim kinsella
Nov 26 at 1:41
1
How about the closed unit disk and the unit circle?
– ncmathsadist
Nov 26 at 1:41
Oh, duh, of course. Silly me. Thank you.
– Frederic Chopin
Nov 26 at 1:43
not silly -- its not at all obvious unless you think about it in terms of $pi_1$. $X$ retracts onto $A$ only if $pi_1(A)$ is a subgroup of $pi_1(X)$.
– Tim kinsella
Nov 26 at 2:07
That's true. But I was thinking indeed about it in terms of the fundamental group, so recalling that the homomorphism induced by the inclusion map is an injection if the space retracts onto some subspace makes this example clear immediately.
– Frederic Chopin
Nov 26 at 2:11
3
3
$S^1 subset mathbb{R}^2$
– Tim kinsella
Nov 26 at 1:41
$S^1 subset mathbb{R}^2$
– Tim kinsella
Nov 26 at 1:41
1
1
How about the closed unit disk and the unit circle?
– ncmathsadist
Nov 26 at 1:41
How about the closed unit disk and the unit circle?
– ncmathsadist
Nov 26 at 1:41
Oh, duh, of course. Silly me. Thank you.
– Frederic Chopin
Nov 26 at 1:43
Oh, duh, of course. Silly me. Thank you.
– Frederic Chopin
Nov 26 at 1:43
not silly -- its not at all obvious unless you think about it in terms of $pi_1$. $X$ retracts onto $A$ only if $pi_1(A)$ is a subgroup of $pi_1(X)$.
– Tim kinsella
Nov 26 at 2:07
not silly -- its not at all obvious unless you think about it in terms of $pi_1$. $X$ retracts onto $A$ only if $pi_1(A)$ is a subgroup of $pi_1(X)$.
– Tim kinsella
Nov 26 at 2:07
That's true. But I was thinking indeed about it in terms of the fundamental group, so recalling that the homomorphism induced by the inclusion map is an injection if the space retracts onto some subspace makes this example clear immediately.
– Frederic Chopin
Nov 26 at 2:11
That's true. But I was thinking indeed about it in terms of the fundamental group, so recalling that the homomorphism induced by the inclusion map is an injection if the space retracts onto some subspace makes this example clear immediately.
– Frederic Chopin
Nov 26 at 2:11
add a comment |
2 Answers
2
active
oldest
votes
Here's the simplest possible example:
Consider the space $X$ with three points $a,b,c$ and open sets $$emptyset, {a},{c}, {a,c}, {a,b,c}.$$ Let $A={a,c}$. There are only two maps from $X$ to $A$ which are the identity on $A$, and neither is continuous. E.g. if we send $b$ to $a$, then the preimage of the open set ${a}$ is the non-open set ${a,b}$.
This really is the simplest example, since any space retracts onto any of its singleton subsets and onto itself.
2
This is my favorite kind of answer to general topology questions, +1! Why get $pi_1$ involved if you don't have to? But I think $A$ should be ${a,c}$.
– Alex Kruckman
Nov 26 at 2:52
@AlexKruckman Thanks, and quite right - fixed!
– Noah Schweber
Nov 26 at 3:08
@AlexKruckman yeah, this is a better answer. but note that this is just using $pi_0$ instead of $pi_1$.
– Tim kinsella
Nov 29 at 6:43
add a comment |
A retract of a Hausdorff space is closed so $(0,1)$ is not a retract of $mathbb{R}$ (usual topology).
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3013691%2fexample-of-a-non-existent-retract%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Here's the simplest possible example:
Consider the space $X$ with three points $a,b,c$ and open sets $$emptyset, {a},{c}, {a,c}, {a,b,c}.$$ Let $A={a,c}$. There are only two maps from $X$ to $A$ which are the identity on $A$, and neither is continuous. E.g. if we send $b$ to $a$, then the preimage of the open set ${a}$ is the non-open set ${a,b}$.
This really is the simplest example, since any space retracts onto any of its singleton subsets and onto itself.
2
This is my favorite kind of answer to general topology questions, +1! Why get $pi_1$ involved if you don't have to? But I think $A$ should be ${a,c}$.
– Alex Kruckman
Nov 26 at 2:52
@AlexKruckman Thanks, and quite right - fixed!
– Noah Schweber
Nov 26 at 3:08
@AlexKruckman yeah, this is a better answer. but note that this is just using $pi_0$ instead of $pi_1$.
– Tim kinsella
Nov 29 at 6:43
add a comment |
Here's the simplest possible example:
Consider the space $X$ with three points $a,b,c$ and open sets $$emptyset, {a},{c}, {a,c}, {a,b,c}.$$ Let $A={a,c}$. There are only two maps from $X$ to $A$ which are the identity on $A$, and neither is continuous. E.g. if we send $b$ to $a$, then the preimage of the open set ${a}$ is the non-open set ${a,b}$.
This really is the simplest example, since any space retracts onto any of its singleton subsets and onto itself.
2
This is my favorite kind of answer to general topology questions, +1! Why get $pi_1$ involved if you don't have to? But I think $A$ should be ${a,c}$.
– Alex Kruckman
Nov 26 at 2:52
@AlexKruckman Thanks, and quite right - fixed!
– Noah Schweber
Nov 26 at 3:08
@AlexKruckman yeah, this is a better answer. but note that this is just using $pi_0$ instead of $pi_1$.
– Tim kinsella
Nov 29 at 6:43
add a comment |
Here's the simplest possible example:
Consider the space $X$ with three points $a,b,c$ and open sets $$emptyset, {a},{c}, {a,c}, {a,b,c}.$$ Let $A={a,c}$. There are only two maps from $X$ to $A$ which are the identity on $A$, and neither is continuous. E.g. if we send $b$ to $a$, then the preimage of the open set ${a}$ is the non-open set ${a,b}$.
This really is the simplest example, since any space retracts onto any of its singleton subsets and onto itself.
Here's the simplest possible example:
Consider the space $X$ with three points $a,b,c$ and open sets $$emptyset, {a},{c}, {a,c}, {a,b,c}.$$ Let $A={a,c}$. There are only two maps from $X$ to $A$ which are the identity on $A$, and neither is continuous. E.g. if we send $b$ to $a$, then the preimage of the open set ${a}$ is the non-open set ${a,b}$.
This really is the simplest example, since any space retracts onto any of its singleton subsets and onto itself.
edited Nov 26 at 3:08
answered Nov 26 at 2:03
Noah Schweber
120k10146279
120k10146279
2
This is my favorite kind of answer to general topology questions, +1! Why get $pi_1$ involved if you don't have to? But I think $A$ should be ${a,c}$.
– Alex Kruckman
Nov 26 at 2:52
@AlexKruckman Thanks, and quite right - fixed!
– Noah Schweber
Nov 26 at 3:08
@AlexKruckman yeah, this is a better answer. but note that this is just using $pi_0$ instead of $pi_1$.
– Tim kinsella
Nov 29 at 6:43
add a comment |
2
This is my favorite kind of answer to general topology questions, +1! Why get $pi_1$ involved if you don't have to? But I think $A$ should be ${a,c}$.
– Alex Kruckman
Nov 26 at 2:52
@AlexKruckman Thanks, and quite right - fixed!
– Noah Schweber
Nov 26 at 3:08
@AlexKruckman yeah, this is a better answer. but note that this is just using $pi_0$ instead of $pi_1$.
– Tim kinsella
Nov 29 at 6:43
2
2
This is my favorite kind of answer to general topology questions, +1! Why get $pi_1$ involved if you don't have to? But I think $A$ should be ${a,c}$.
– Alex Kruckman
Nov 26 at 2:52
This is my favorite kind of answer to general topology questions, +1! Why get $pi_1$ involved if you don't have to? But I think $A$ should be ${a,c}$.
– Alex Kruckman
Nov 26 at 2:52
@AlexKruckman Thanks, and quite right - fixed!
– Noah Schweber
Nov 26 at 3:08
@AlexKruckman Thanks, and quite right - fixed!
– Noah Schweber
Nov 26 at 3:08
@AlexKruckman yeah, this is a better answer. but note that this is just using $pi_0$ instead of $pi_1$.
– Tim kinsella
Nov 29 at 6:43
@AlexKruckman yeah, this is a better answer. but note that this is just using $pi_0$ instead of $pi_1$.
– Tim kinsella
Nov 29 at 6:43
add a comment |
A retract of a Hausdorff space is closed so $(0,1)$ is not a retract of $mathbb{R}$ (usual topology).
add a comment |
A retract of a Hausdorff space is closed so $(0,1)$ is not a retract of $mathbb{R}$ (usual topology).
add a comment |
A retract of a Hausdorff space is closed so $(0,1)$ is not a retract of $mathbb{R}$ (usual topology).
A retract of a Hausdorff space is closed so $(0,1)$ is not a retract of $mathbb{R}$ (usual topology).
answered Nov 26 at 6:17
Henno Brandsma
104k346113
104k346113
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3013691%2fexample-of-a-non-existent-retract%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
3
$S^1 subset mathbb{R}^2$
– Tim kinsella
Nov 26 at 1:41
1
How about the closed unit disk and the unit circle?
– ncmathsadist
Nov 26 at 1:41
Oh, duh, of course. Silly me. Thank you.
– Frederic Chopin
Nov 26 at 1:43
not silly -- its not at all obvious unless you think about it in terms of $pi_1$. $X$ retracts onto $A$ only if $pi_1(A)$ is a subgroup of $pi_1(X)$.
– Tim kinsella
Nov 26 at 2:07
That's true. But I was thinking indeed about it in terms of the fundamental group, so recalling that the homomorphism induced by the inclusion map is an injection if the space retracts onto some subspace makes this example clear immediately.
– Frederic Chopin
Nov 26 at 2:11