Nyquist diagram stability












0














I have 4 tasks from Nyquist diagram and they are similar. I don't know how to solve then so here is one example which I'm trying to solve.



For a system which transfer function is $displaystyle W(s)=Kfrac{(s+5)}{(s−2)(s+1)}$ , Nyquist diagram for $K=1$ is given on picture. Based on the diagram, find the range of gain for which the system is stable.



Can anybody help me how to solve this?



enter image description here










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  • I tried to draw the inverse part of this diagram and then to mark point on left side of real axis and then using this formula N=p-z to determine stability but I'm making mistake somewhere.
    – Mišel Ademi
    May 31 '18 at 16:22










  • So what should N, P and Z be? And when is that the case?
    – Kwin van der Veen
    May 31 '18 at 18:12










  • @KwinvanderVeen N is number of encirclements, P is number of poles on right side and if Z is 0 than in that part system is stable, otherwise is unstable.
    – Mišel Ademi
    May 31 '18 at 18:37










  • For N in what direction and around which point do you consider the encirclements? Also note that in order to count the encirclements you also have to plot the negative frequencies as well.
    – Kwin van der Veen
    Jun 1 '18 at 18:03










  • I use 1+jw point
    – Mišel Ademi
    Jun 1 '18 at 18:30
















0














I have 4 tasks from Nyquist diagram and they are similar. I don't know how to solve then so here is one example which I'm trying to solve.



For a system which transfer function is $displaystyle W(s)=Kfrac{(s+5)}{(s−2)(s+1)}$ , Nyquist diagram for $K=1$ is given on picture. Based on the diagram, find the range of gain for which the system is stable.



Can anybody help me how to solve this?



enter image description here










share|cite|improve this question
























  • I tried to draw the inverse part of this diagram and then to mark point on left side of real axis and then using this formula N=p-z to determine stability but I'm making mistake somewhere.
    – Mišel Ademi
    May 31 '18 at 16:22










  • So what should N, P and Z be? And when is that the case?
    – Kwin van der Veen
    May 31 '18 at 18:12










  • @KwinvanderVeen N is number of encirclements, P is number of poles on right side and if Z is 0 than in that part system is stable, otherwise is unstable.
    – Mišel Ademi
    May 31 '18 at 18:37










  • For N in what direction and around which point do you consider the encirclements? Also note that in order to count the encirclements you also have to plot the negative frequencies as well.
    – Kwin van der Veen
    Jun 1 '18 at 18:03










  • I use 1+jw point
    – Mišel Ademi
    Jun 1 '18 at 18:30














0












0








0


1





I have 4 tasks from Nyquist diagram and they are similar. I don't know how to solve then so here is one example which I'm trying to solve.



For a system which transfer function is $displaystyle W(s)=Kfrac{(s+5)}{(s−2)(s+1)}$ , Nyquist diagram for $K=1$ is given on picture. Based on the diagram, find the range of gain for which the system is stable.



Can anybody help me how to solve this?



enter image description here










share|cite|improve this question















I have 4 tasks from Nyquist diagram and they are similar. I don't know how to solve then so here is one example which I'm trying to solve.



For a system which transfer function is $displaystyle W(s)=Kfrac{(s+5)}{(s−2)(s+1)}$ , Nyquist diagram for $K=1$ is given on picture. Based on the diagram, find the range of gain for which the system is stable.



Can anybody help me how to solve this?



enter image description here







complex-analysis optimization control-theory






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share|cite|improve this question













share|cite|improve this question




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edited May 31 '18 at 11:09









caverac

13.8k21030




13.8k21030










asked May 31 '18 at 10:52









Mišel Ademi

1




1












  • I tried to draw the inverse part of this diagram and then to mark point on left side of real axis and then using this formula N=p-z to determine stability but I'm making mistake somewhere.
    – Mišel Ademi
    May 31 '18 at 16:22










  • So what should N, P and Z be? And when is that the case?
    – Kwin van der Veen
    May 31 '18 at 18:12










  • @KwinvanderVeen N is number of encirclements, P is number of poles on right side and if Z is 0 than in that part system is stable, otherwise is unstable.
    – Mišel Ademi
    May 31 '18 at 18:37










  • For N in what direction and around which point do you consider the encirclements? Also note that in order to count the encirclements you also have to plot the negative frequencies as well.
    – Kwin van der Veen
    Jun 1 '18 at 18:03










  • I use 1+jw point
    – Mišel Ademi
    Jun 1 '18 at 18:30


















  • I tried to draw the inverse part of this diagram and then to mark point on left side of real axis and then using this formula N=p-z to determine stability but I'm making mistake somewhere.
    – Mišel Ademi
    May 31 '18 at 16:22










  • So what should N, P and Z be? And when is that the case?
    – Kwin van der Veen
    May 31 '18 at 18:12










  • @KwinvanderVeen N is number of encirclements, P is number of poles on right side and if Z is 0 than in that part system is stable, otherwise is unstable.
    – Mišel Ademi
    May 31 '18 at 18:37










  • For N in what direction and around which point do you consider the encirclements? Also note that in order to count the encirclements you also have to plot the negative frequencies as well.
    – Kwin van der Veen
    Jun 1 '18 at 18:03










  • I use 1+jw point
    – Mišel Ademi
    Jun 1 '18 at 18:30
















I tried to draw the inverse part of this diagram and then to mark point on left side of real axis and then using this formula N=p-z to determine stability but I'm making mistake somewhere.
– Mišel Ademi
May 31 '18 at 16:22




I tried to draw the inverse part of this diagram and then to mark point on left side of real axis and then using this formula N=p-z to determine stability but I'm making mistake somewhere.
– Mišel Ademi
May 31 '18 at 16:22












So what should N, P and Z be? And when is that the case?
– Kwin van der Veen
May 31 '18 at 18:12




So what should N, P and Z be? And when is that the case?
– Kwin van der Veen
May 31 '18 at 18:12












@KwinvanderVeen N is number of encirclements, P is number of poles on right side and if Z is 0 than in that part system is stable, otherwise is unstable.
– Mišel Ademi
May 31 '18 at 18:37




@KwinvanderVeen N is number of encirclements, P is number of poles on right side and if Z is 0 than in that part system is stable, otherwise is unstable.
– Mišel Ademi
May 31 '18 at 18:37












For N in what direction and around which point do you consider the encirclements? Also note that in order to count the encirclements you also have to plot the negative frequencies as well.
– Kwin van der Veen
Jun 1 '18 at 18:03




For N in what direction and around which point do you consider the encirclements? Also note that in order to count the encirclements you also have to plot the negative frequencies as well.
– Kwin van der Veen
Jun 1 '18 at 18:03












I use 1+jw point
– Mišel Ademi
Jun 1 '18 at 18:30




I use 1+jw point
– Mišel Ademi
Jun 1 '18 at 18:30










1 Answer
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2














You have to complete the complex trace of $W(s)$ to see the number of encirclements:



enter image description here



Note that since $K=1$ you can view the plot as the trace of $W(s)/K$, so you can consider encirclements of the point $-1/K+0cdot i$. The number of clockwise encirclements $N$ of that point equals the number of zeros $Z$ of $1/K+W(s)$ in the right-half plane minus the numbers of poles $P$ of $1/K+W(s)$ in the right half-plane:



$$N=Z-Ptag{1}$$



The term $s-2$ in the denominator contributes one pole in the right half-plane, so in order to have no zeros ($Z=0$), we need to have $N=-1$ clockwise encirclements of the point $-1/K+0cdot i$, which is equivalent to $1$ counter-clockwise encirclement.



From the Nyquist plot, a counter-clockwise encirclement is achieved if the point $-1/K+0cdot i$ is inside the right-hand side closed part of the curve, i.e. if $1/K$ is in the range



$$-1<-1/K<0$$



which is equivalent to $K>1$. Consequently, for $K>1$ the corresponding closed-loop transfer function is stable.






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    1 Answer
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    1 Answer
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    You have to complete the complex trace of $W(s)$ to see the number of encirclements:



    enter image description here



    Note that since $K=1$ you can view the plot as the trace of $W(s)/K$, so you can consider encirclements of the point $-1/K+0cdot i$. The number of clockwise encirclements $N$ of that point equals the number of zeros $Z$ of $1/K+W(s)$ in the right-half plane minus the numbers of poles $P$ of $1/K+W(s)$ in the right half-plane:



    $$N=Z-Ptag{1}$$



    The term $s-2$ in the denominator contributes one pole in the right half-plane, so in order to have no zeros ($Z=0$), we need to have $N=-1$ clockwise encirclements of the point $-1/K+0cdot i$, which is equivalent to $1$ counter-clockwise encirclement.



    From the Nyquist plot, a counter-clockwise encirclement is achieved if the point $-1/K+0cdot i$ is inside the right-hand side closed part of the curve, i.e. if $1/K$ is in the range



    $$-1<-1/K<0$$



    which is equivalent to $K>1$. Consequently, for $K>1$ the corresponding closed-loop transfer function is stable.






    share|cite|improve this answer


























      2














      You have to complete the complex trace of $W(s)$ to see the number of encirclements:



      enter image description here



      Note that since $K=1$ you can view the plot as the trace of $W(s)/K$, so you can consider encirclements of the point $-1/K+0cdot i$. The number of clockwise encirclements $N$ of that point equals the number of zeros $Z$ of $1/K+W(s)$ in the right-half plane minus the numbers of poles $P$ of $1/K+W(s)$ in the right half-plane:



      $$N=Z-Ptag{1}$$



      The term $s-2$ in the denominator contributes one pole in the right half-plane, so in order to have no zeros ($Z=0$), we need to have $N=-1$ clockwise encirclements of the point $-1/K+0cdot i$, which is equivalent to $1$ counter-clockwise encirclement.



      From the Nyquist plot, a counter-clockwise encirclement is achieved if the point $-1/K+0cdot i$ is inside the right-hand side closed part of the curve, i.e. if $1/K$ is in the range



      $$-1<-1/K<0$$



      which is equivalent to $K>1$. Consequently, for $K>1$ the corresponding closed-loop transfer function is stable.






      share|cite|improve this answer
























        2












        2








        2






        You have to complete the complex trace of $W(s)$ to see the number of encirclements:



        enter image description here



        Note that since $K=1$ you can view the plot as the trace of $W(s)/K$, so you can consider encirclements of the point $-1/K+0cdot i$. The number of clockwise encirclements $N$ of that point equals the number of zeros $Z$ of $1/K+W(s)$ in the right-half plane minus the numbers of poles $P$ of $1/K+W(s)$ in the right half-plane:



        $$N=Z-Ptag{1}$$



        The term $s-2$ in the denominator contributes one pole in the right half-plane, so in order to have no zeros ($Z=0$), we need to have $N=-1$ clockwise encirclements of the point $-1/K+0cdot i$, which is equivalent to $1$ counter-clockwise encirclement.



        From the Nyquist plot, a counter-clockwise encirclement is achieved if the point $-1/K+0cdot i$ is inside the right-hand side closed part of the curve, i.e. if $1/K$ is in the range



        $$-1<-1/K<0$$



        which is equivalent to $K>1$. Consequently, for $K>1$ the corresponding closed-loop transfer function is stable.






        share|cite|improve this answer












        You have to complete the complex trace of $W(s)$ to see the number of encirclements:



        enter image description here



        Note that since $K=1$ you can view the plot as the trace of $W(s)/K$, so you can consider encirclements of the point $-1/K+0cdot i$. The number of clockwise encirclements $N$ of that point equals the number of zeros $Z$ of $1/K+W(s)$ in the right-half plane minus the numbers of poles $P$ of $1/K+W(s)$ in the right half-plane:



        $$N=Z-Ptag{1}$$



        The term $s-2$ in the denominator contributes one pole in the right half-plane, so in order to have no zeros ($Z=0$), we need to have $N=-1$ clockwise encirclements of the point $-1/K+0cdot i$, which is equivalent to $1$ counter-clockwise encirclement.



        From the Nyquist plot, a counter-clockwise encirclement is achieved if the point $-1/K+0cdot i$ is inside the right-hand side closed part of the curve, i.e. if $1/K$ is in the range



        $$-1<-1/K<0$$



        which is equivalent to $K>1$. Consequently, for $K>1$ the corresponding closed-loop transfer function is stable.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Nov 28 '18 at 10:25









        Matt L.

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        8,871822






























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