Can't show equation tag properly

begin{align*}

sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex} 

sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }} 

= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq 

 boldsymbol{ell}, } tag(3) label{eq:3}

end{align*}

which is very close to our goal, equation eqref{eq:2}. 

Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$). 

The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...

end{document}

I try to put a tag next to the equation, but the result comes out as:

enter image description here

The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)

edited 3 hours ago

Werner

437k649581648

asked 3 hours ago

HankY

111

New contributor

1

Welcome to TeX.SE! Replace tag(3) by tag{3} (curly brackets around 3). Otherwise LaTeX thinks you mean tag{(}.
– marmot
3 hours ago

It worked, thank you!
– HankY
3 hours ago

You're welcome! BTW, I'd recommend to move the comma after boldsymbol{ell} out of the subscript, and not to abbreviate textsuperscript by ts if you ever plan to share your documents with others.
– marmot
3 hours ago

add a comment |

begin{align*}

sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex} 

sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }} 

= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq 

 boldsymbol{ell}, } tag(3) label{eq:3}

end{align*}

which is very close to our goal, equation eqref{eq:2}. 

Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$). 

The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...

end{document}

I try to put a tag next to the equation, but the result comes out as:

enter image description here

The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)

edited 3 hours ago

Werner

437k649581648

asked 3 hours ago

HankY

111

New contributor

1

Welcome to TeX.SE! Replace tag(3) by tag{3} (curly brackets around 3). Otherwise LaTeX thinks you mean tag{(}.
– marmot
3 hours ago

It worked, thank you!
– HankY
3 hours ago

You're welcome! BTW, I'd recommend to move the comma after boldsymbol{ell} out of the subscript, and not to abbreviate textsuperscript by ts if you ever plan to share your documents with others.
– marmot
3 hours ago

add a comment |

begin{align*}

sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex} 

sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }} 

= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq 

 boldsymbol{ell}, } tag(3) label{eq:3}

end{align*}

which is very close to our goal, equation eqref{eq:2}. 

Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$). 

The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...

end{document}

I try to put a tag next to the equation, but the result comes out as:

enter image description here

The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)

edited 3 hours ago

Werner

437k649581648

asked 3 hours ago

HankY

111

New contributor

begin{align*}

sum_{j=1}^{m_0-1},(-1)^{j-1}hspace{-3ex} 

sum_{substack{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_{j+2} leq k_1 leq boldsymbol{ell} \ k_2 < cdots < k_j < k_{j+1} leq k_1 }} 

= sum_{ k_{m_0 +1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq 

 boldsymbol{ell}, } tag(3) label{eq:3}

end{align*}

which is very close to our goal, equation eqref{eq:2}. 

Comparing equation eqref{eq:3} with equation eqref{eq:2}, we discover that both have the identical 1ts{st} through $(m_0 -2)$ts{th} terms ($1 leq j leq m_0-2$). 

The only difference of the two is that the $(m_0 -1)$ts{th} term in equation eqref{eq:3} is ...

end{document}

I try to put a tag next to the equation, but the result comes out as:

enter image description here

The tag is not displayed correctly. Also, the eqref{eq:3} are displayed in the same, wrong way. (I omit the code having eq:2 and eq:1.)

1 Answer
1

active

oldest

votes

tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.

In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:

enter image description here

documentclass{article}



usepackage{amsmath,amssymb}



begin{document}



begin{align*}

  sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex} 

  sum_{

    substack

      { k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \

        k_2 < cdots < k_j < k_{j+1} leq k_1 

      }

  } 

  = sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}

end{align*}

which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical 

1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the 

$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots



end{document}

answered 2 hours ago

Werner

437k649581648

add a comment |

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1 Answer
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1 Answer
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active

oldest

votes

tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.

In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:

enter image description here

documentclass{article}



usepackage{amsmath,amssymb}



begin{document}



begin{align*}

  sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex} 

  sum_{

    substack

      { k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \

        k_2 < cdots < k_j < k_{j+1} leq k_1 

      }

  } 

  = sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}

end{align*}

which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical 

1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the 

$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots



end{document}

answered 2 hours ago

Werner

437k649581648

add a comment |

tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.

In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:

enter image description here

documentclass{article}



usepackage{amsmath,amssymb}



begin{document}



begin{align*}

  sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex} 

  sum_{

    substack

      { k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \

        k_2 < cdots < k_j < k_{j+1} leq k_1 

      }

  } 

  = sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}

end{align*}

which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical 

1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the 

$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots



end{document}

answered 2 hours ago

Werner

437k649581648

add a comment |

tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.

In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:

enter image description here

documentclass{article}



usepackage{amsmath,amssymb}



begin{document}



begin{align*}

  sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex} 

  sum_{

    substack

      { k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \

        k_2 < cdots < k_j < k_{j+1} leq k_1 

      }

  } 

  = sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}

end{align*}

which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical 

1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the 

$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots



end{document}

answered 2 hours ago

Werner

437k649581648

tag{<tag>} takes a mandatory argument. If you don't supply the surrounding braces, then it takes the next token as the argument.

In your case, tag(3) doesn't use the suggested format tag{<tag>}, so it turns into tag{(}3), numbering the equation with ( and leaving 3) in the input stream. You're looking for tag{3}:

enter image description here

documentclass{article}



usepackage{amsmath,amssymb}



begin{document}



begin{align*}

  sum_{j = 1}^{m_0 - 1},(-1)^{j - 1}hspace{-3ex} 

  sum_{

    substack

      { k_{m_0 + 1} leq k_{m_0} leq cdots leq k_{j + 2} leq k_1 leq boldsymbol{ell} \

        k_2 < cdots < k_j < k_{j+1} leq k_1 

      }

  } 

  = sum_{ k_{m_0 + 1} leq k_{m_0} leq cdots leq k_2 leq k_1 leq boldsymbol{ell} }, tag{3} label{eq:3}

end{align*}

which is very close to our goal, equation~(2). Comparing equation~eqref{eq:3} with equation~(2), we discover that both have the identical 

1textsuperscript{st} through $(m_0 - 2)$textsuperscript{th} terms ($1 leq j leq m_0 - 2$). The only difference of the two is that the 

$(m_0 - 1)$textsuperscript{th} term in equation eqref{eq:3} is ldots



end{document}

answered 2 hours ago

Werner

437k649581648

answered 2 hours ago

Werner

437k649581648

answered 2 hours ago

Werner

437k649581648

answered 2 hours ago

Werner

437k649581648

add a comment |

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