The Metapost path fullcircle
2
Is the MetaPost path fullcircle cyclic?
I attempted to find the answer in "METAPOST - A User's Manual" but had no luck.
UPDATE:
show cycle fullcircle;
will print the answer true.
metapost
asked 6 hours ago
soegaard
1114
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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|
show 3 more comments
2
Is the MetaPost path fullcircle cyclic?
I attempted to find the answer in "METAPOST - A User's Manual" but had no luck.
UPDATE:
show cycle fullcircle;
will print the answer true.
metapost
asked 6 hours ago
soegaard
1114
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
How do you mean? Have you tried. Afair a closed curve in mp is cyclic as in you can go around as many times you want. (though I don't use metapost that much any more)
– daleif
5 hours ago
I know that there is an operatorcycle, but I don't know how to print the result ofcycle fullcircle.
– soegaard
5 hours ago
1
Draw a point at certain times on the curve. Afair fullcircle goes 0 1 2 3 4 0, as in (assuming complex plane), 1, I, -1, -i, 1. So at time 2 it is at (-1,0).
– daleif
5 hours ago
2
Perhaps you should explain why you need to know if a given path is closed? What do you need this information for?
– daleif
5 hours ago
1
Tak for tippet.
– soegaard
4 hours ago
|
show 3 more comments
2
2
2
Is the MetaPost path fullcircle cyclic?
I attempted to find the answer in "METAPOST - A User's Manual" but had no luck.
UPDATE:
show cycle fullcircle;
will print the answer true.
metapost
asked 6 hours ago
soegaard
1114
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Is the MetaPost path fullcircle cyclic?
I attempted to find the answer in "METAPOST - A User's Manual" but had no luck.
UPDATE:
show cycle fullcircle;
will print the answer true.
metapost
metapost
asked 6 hours ago
soegaard
1114
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 6 hours ago
soegaard
1114
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 5 hours ago
asked 6 hours ago
soegaard
1114
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 6 hours ago
soegaard
1114
asked 6 hours ago
soegaard
1114
1114
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
soegaard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
How do you mean? Have you tried. Afair a closed curve in mp is cyclic as in you can go around as many times you want. (though I don't use metapost that much any more)
– daleif
5 hours ago
I know that there is an operatorcycle, but I don't know how to print the result ofcycle fullcircle.
– soegaard
5 hours ago
1
Draw a point at certain times on the curve. Afair fullcircle goes 0 1 2 3 4 0, as in (assuming complex plane), 1, I, -1, -i, 1. So at time 2 it is at (-1,0).
– daleif
5 hours ago
2
Perhaps you should explain why you need to know if a given path is closed? What do you need this information for?
– daleif
5 hours ago
1
Tak for tippet.
– soegaard
4 hours ago
|
show 3 more comments
2
How do you mean? Have you tried. Afair a closed curve in mp is cyclic as in you can go around as many times you want. (though I don't use metapost that much any more)
– daleif
5 hours ago
I know that there is an operatorcycle, but I don't know how to print the result ofcycle fullcircle.
– soegaard
5 hours ago
1
Draw a point at certain times on the curve. Afair fullcircle goes 0 1 2 3 4 0, as in (assuming complex plane), 1, I, -1, -i, 1. So at time 2 it is at (-1,0).
– daleif
5 hours ago
2
Perhaps you should explain why you need to know if a given path is closed? What do you need this information for?
– daleif
5 hours ago
1
Tak for tippet.
– soegaard
4 hours ago
2
2
How do you mean? Have you tried. Afair a closed curve in mp is cyclic as in you can go around as many times you want. (though I don't use metapost that much any more)
– daleif
5 hours ago
How do you mean? Have you tried. Afair a closed curve in mp is cyclic as in you can go around as many times you want. (though I don't use metapost that much any more)
– daleif
5 hours ago
I know that there is an operator
cycle, but I don't know how to print the result of cycle fullcircle.– soegaard
5 hours ago
I know that there is an operator
cycle, but I don't know how to print the result of cycle fullcircle.– soegaard
5 hours ago
1
1
Draw a point at certain times on the curve. Afair fullcircle goes 0 1 2 3 4 0, as in (assuming complex plane), 1, I, -1, -i, 1. So at time 2 it is at (-1,0).
– daleif
5 hours ago
Draw a point at certain times on the curve. Afair fullcircle goes 0 1 2 3 4 0, as in (assuming complex plane), 1, I, -1, -i, 1. So at time 2 it is at (-1,0).
– daleif
5 hours ago
2
2
Perhaps you should explain why you need to know if a given path is closed? What do you need this information for?
– daleif
5 hours ago
Perhaps you should explain why you need to know if a given path is closed? What do you need this information for?
– daleif
5 hours ago
1
1
Tak for tippet.
– soegaard
4 hours ago
Tak for tippet.
– soegaard
4 hours ago
|
show 3 more comments
1 Answer
1
active
oldest
votes
3
A path such as
(0,0)..(1,0)..(1,1)..(0,1)..(0,0)
is open. You can check this by doing
*path p;
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0,0)
*show point 10 of p;
>> (0,0)
*show point 12 of p;
>> (0,0)
On the other hand, we can see
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0.08765,-0.07457)
*show point 10 of p;
>> (1,1)
*show point 12 of p;
>> (0,0)
Going on:
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show cycle p;
>> false
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show cycle p;
>> true
You can get the definition of fullcircle:
*show fullcircle;
>> Path at line 0:
(0.5,0)..controls (0.5,0.13261) and (0.44731,0.25978)
..(0.35355,0.35355)..controls (0.25978,0.44731) and (0.13261,0.5)
..(0,0.5)..controls (-0.13261,0.5) and (-0.25978,0.44731)
..(-0.35355,0.35355)..controls (-0.44731,0.25978) and (-0.5,0.13261)
..(-0.5,0)..controls (-0.5,-0.13261) and (-0.44731,-0.25978)
..(-0.35355,-0.35355)..controls (-0.25978,-0.44731) and (-0.13261,-0.5)
..(0,-0.5)..controls (0.13261,-0.5) and (0.25978,-0.44731)
..(0.35355,-0.35355)..controls (0.44731,-0.25978) and (0.5,-0.13261)
..cycle
and this is cyclic.
Actually you don't find the definition in plain.mp, because fullcircle is defined by fullcircle = makepath pencircle;, but when the path has been built it can be shown.
answered 4 hours ago
egreg
708k8618823164
add a comment |
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1 Answer
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1 Answer
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3
A path such as
(0,0)..(1,0)..(1,1)..(0,1)..(0,0)
is open. You can check this by doing
*path p;
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0,0)
*show point 10 of p;
>> (0,0)
*show point 12 of p;
>> (0,0)
On the other hand, we can see
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0.08765,-0.07457)
*show point 10 of p;
>> (1,1)
*show point 12 of p;
>> (0,0)
Going on:
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show cycle p;
>> false
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show cycle p;
>> true
You can get the definition of fullcircle:
*show fullcircle;
>> Path at line 0:
(0.5,0)..controls (0.5,0.13261) and (0.44731,0.25978)
..(0.35355,0.35355)..controls (0.25978,0.44731) and (0.13261,0.5)
..(0,0.5)..controls (-0.13261,0.5) and (-0.25978,0.44731)
..(-0.35355,0.35355)..controls (-0.44731,0.25978) and (-0.5,0.13261)
..(-0.5,0)..controls (-0.5,-0.13261) and (-0.44731,-0.25978)
..(-0.35355,-0.35355)..controls (-0.25978,-0.44731) and (-0.13261,-0.5)
..(0,-0.5)..controls (0.13261,-0.5) and (0.25978,-0.44731)
..(0.35355,-0.35355)..controls (0.44731,-0.25978) and (0.5,-0.13261)
..cycle
and this is cyclic.
Actually you don't find the definition in plain.mp, because fullcircle is defined by fullcircle = makepath pencircle;, but when the path has been built it can be shown.
answered 4 hours ago
egreg
708k8618823164
add a comment |
3
A path such as
(0,0)..(1,0)..(1,1)..(0,1)..(0,0)
is open. You can check this by doing
*path p;
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0,0)
*show point 10 of p;
>> (0,0)
*show point 12 of p;
>> (0,0)
On the other hand, we can see
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0.08765,-0.07457)
*show point 10 of p;
>> (1,1)
*show point 12 of p;
>> (0,0)
Going on:
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show cycle p;
>> false
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show cycle p;
>> true
You can get the definition of fullcircle:
*show fullcircle;
>> Path at line 0:
(0.5,0)..controls (0.5,0.13261) and (0.44731,0.25978)
..(0.35355,0.35355)..controls (0.25978,0.44731) and (0.13261,0.5)
..(0,0.5)..controls (-0.13261,0.5) and (-0.25978,0.44731)
..(-0.35355,0.35355)..controls (-0.44731,0.25978) and (-0.5,0.13261)
..(-0.5,0)..controls (-0.5,-0.13261) and (-0.44731,-0.25978)
..(-0.35355,-0.35355)..controls (-0.25978,-0.44731) and (-0.13261,-0.5)
..(0,-0.5)..controls (0.13261,-0.5) and (0.25978,-0.44731)
..(0.35355,-0.35355)..controls (0.44731,-0.25978) and (0.5,-0.13261)
..cycle
and this is cyclic.
Actually you don't find the definition in plain.mp, because fullcircle is defined by fullcircle = makepath pencircle;, but when the path has been built it can be shown.
answered 4 hours ago
egreg
708k8618823164
add a comment |
3
3
3
A path such as
(0,0)..(1,0)..(1,1)..(0,1)..(0,0)
is open. You can check this by doing
*path p;
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0,0)
*show point 10 of p;
>> (0,0)
*show point 12 of p;
>> (0,0)
On the other hand, we can see
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0.08765,-0.07457)
*show point 10 of p;
>> (1,1)
*show point 12 of p;
>> (0,0)
Going on:
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show cycle p;
>> false
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show cycle p;
>> true
You can get the definition of fullcircle:
*show fullcircle;
>> Path at line 0:
(0.5,0)..controls (0.5,0.13261) and (0.44731,0.25978)
..(0.35355,0.35355)..controls (0.25978,0.44731) and (0.13261,0.5)
..(0,0.5)..controls (-0.13261,0.5) and (-0.25978,0.44731)
..(-0.35355,0.35355)..controls (-0.44731,0.25978) and (-0.5,0.13261)
..(-0.5,0)..controls (-0.5,-0.13261) and (-0.44731,-0.25978)
..(-0.35355,-0.35355)..controls (-0.25978,-0.44731) and (-0.13261,-0.5)
..(0,-0.5)..controls (0.13261,-0.5) and (0.25978,-0.44731)
..(0.35355,-0.35355)..controls (0.44731,-0.25978) and (0.5,-0.13261)
..cycle
and this is cyclic.
Actually you don't find the definition in plain.mp, because fullcircle is defined by fullcircle = makepath pencircle;, but when the path has been built it can be shown.
answered 4 hours ago
egreg
708k8618823164
A path such as
(0,0)..(1,0)..(1,1)..(0,1)..(0,0)
is open. You can check this by doing
*path p;
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0,0)
*show point 10 of p;
>> (0,0)
*show point 12 of p;
>> (0,0)
On the other hand, we can see
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show point 3 of p;
>> (0,1)
*show point 3.5 of p;
>> (-0.20709,0.49998)
*show point 4 of p;
>> (0,0)
*show point 4.1 of p;
>> (0.08765,-0.07457)
*show point 10 of p;
>> (1,1)
*show point 12 of p;
>> (0,0)
Going on:
*p:=(0,0)..(1,0)..(1,1)..(0,1)..(0,0);
*show cycle p;
>> false
*p:=(0,0)..(1,0)..(1,1)..(0,1)..cycle;
*show cycle p;
>> true
You can get the definition of fullcircle:
*show fullcircle;
>> Path at line 0:
(0.5,0)..controls (0.5,0.13261) and (0.44731,0.25978)
..(0.35355,0.35355)..controls (0.25978,0.44731) and (0.13261,0.5)
..(0,0.5)..controls (-0.13261,0.5) and (-0.25978,0.44731)
..(-0.35355,0.35355)..controls (-0.44731,0.25978) and (-0.5,0.13261)
..(-0.5,0)..controls (-0.5,-0.13261) and (-0.44731,-0.25978)
..(-0.35355,-0.35355)..controls (-0.25978,-0.44731) and (-0.13261,-0.5)
..(0,-0.5)..controls (0.13261,-0.5) and (0.25978,-0.44731)
..(0.35355,-0.35355)..controls (0.44731,-0.25978) and (0.5,-0.13261)
..cycle
and this is cyclic.
Actually you don't find the definition in plain.mp, because fullcircle is defined by fullcircle = makepath pencircle;, but when the path has been built it can be shown.
answered 4 hours ago
egreg
708k8618823164
answered 4 hours ago
egreg
708k8618823164
answered 4 hours ago
egreg
708k8618823164
answered 4 hours ago
egreg
708k8618823164
708k8618823164
add a comment |
add a comment |
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2
How do you mean? Have you tried. Afair a closed curve in mp is cyclic as in you can go around as many times you want. (though I don't use metapost that much any more)
– daleif
5 hours ago
I know that there is an operator
cycle, but I don't know how to print the result ofcycle fullcircle.– soegaard
5 hours ago
1
Draw a point at certain times on the curve. Afair fullcircle goes 0 1 2 3 4 0, as in (assuming complex plane), 1, I, -1, -i, 1. So at time 2 it is at (-1,0).
– daleif
5 hours ago
2
Perhaps you should explain why you need to know if a given path is closed? What do you need this information for?
– daleif
5 hours ago
1
Tak for tippet.
– soegaard
4 hours ago