Why is restriction $varphi_R$ a homeomorphism in showing cross is not locally Euclidean in Tu Manifolds?
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Tu Manifolds Section 5.1
Definition of locally Euclidean of dimension n.
Example
To show $varphi_R: U setminus p to B setminus 0$ is also a homeomorphism, I think:
$varphi_R = r circ varphi circ j$ where $j: U setminus p to U$ is inclusion and $r$ is some function $r: B(0,varepsilon) to B(0,varepsilon) setminus 0$, $varphi_R$ is bijective because $varphi(p)=0$ and $varphi$ is bijective and $varphi_R$ is continuous if we can find a continuous $r$ because $j$ and $varphi$ are continuous. Then $varphi_R$ is a homeomorphism if we can find an $r$ and show either that $varphi_R$ is an open or closed map or that $varphi_R^{-1}$ is continuous.
Is that correct?
What $r$ can we select?
Must $r$ be a retraction? That is, is it insufficient to find a continuous $r$ that isn't a retraction, if it's possible?
Is it possible? (to find a continuous $r$ that isn't a retraction)
Why is $varphi_R^{-1}$ continuous?
- What is $varphi_R^{-1}$ anyway? I don't think $j^{-1}$ or $r^{-1}$ exist.
What properties of open or closed maps are there to say $varphi_R$ is an open or closed map because $varphi$ is an open or closed map and some other facts?
We have $varphi(x)=varphi_R(x)$ for all $x in U setminus p$, so I think $varphi_R(x)$ is an open map too. This might be relevant:
Theorem 22.1 in Munkres:
general-topology differential-geometry algebraic-topology manifolds quotient-spaces
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up vote
0
down vote
favorite
Tu Manifolds Section 5.1
Definition of locally Euclidean of dimension n.
Example
To show $varphi_R: U setminus p to B setminus 0$ is also a homeomorphism, I think:
$varphi_R = r circ varphi circ j$ where $j: U setminus p to U$ is inclusion and $r$ is some function $r: B(0,varepsilon) to B(0,varepsilon) setminus 0$, $varphi_R$ is bijective because $varphi(p)=0$ and $varphi$ is bijective and $varphi_R$ is continuous if we can find a continuous $r$ because $j$ and $varphi$ are continuous. Then $varphi_R$ is a homeomorphism if we can find an $r$ and show either that $varphi_R$ is an open or closed map or that $varphi_R^{-1}$ is continuous.
Is that correct?
What $r$ can we select?
Must $r$ be a retraction? That is, is it insufficient to find a continuous $r$ that isn't a retraction, if it's possible?
Is it possible? (to find a continuous $r$ that isn't a retraction)
Why is $varphi_R^{-1}$ continuous?
- What is $varphi_R^{-1}$ anyway? I don't think $j^{-1}$ or $r^{-1}$ exist.
What properties of open or closed maps are there to say $varphi_R$ is an open or closed map because $varphi$ is an open or closed map and some other facts?
We have $varphi(x)=varphi_R(x)$ for all $x in U setminus p$, so I think $varphi_R(x)$ is an open map too. This might be relevant:
Theorem 22.1 in Munkres:
general-topology differential-geometry algebraic-topology manifolds quotient-spaces
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Tu Manifolds Section 5.1
Definition of locally Euclidean of dimension n.
Example
To show $varphi_R: U setminus p to B setminus 0$ is also a homeomorphism, I think:
$varphi_R = r circ varphi circ j$ where $j: U setminus p to U$ is inclusion and $r$ is some function $r: B(0,varepsilon) to B(0,varepsilon) setminus 0$, $varphi_R$ is bijective because $varphi(p)=0$ and $varphi$ is bijective and $varphi_R$ is continuous if we can find a continuous $r$ because $j$ and $varphi$ are continuous. Then $varphi_R$ is a homeomorphism if we can find an $r$ and show either that $varphi_R$ is an open or closed map or that $varphi_R^{-1}$ is continuous.
Is that correct?
What $r$ can we select?
Must $r$ be a retraction? That is, is it insufficient to find a continuous $r$ that isn't a retraction, if it's possible?
Is it possible? (to find a continuous $r$ that isn't a retraction)
Why is $varphi_R^{-1}$ continuous?
- What is $varphi_R^{-1}$ anyway? I don't think $j^{-1}$ or $r^{-1}$ exist.
What properties of open or closed maps are there to say $varphi_R$ is an open or closed map because $varphi$ is an open or closed map and some other facts?
We have $varphi(x)=varphi_R(x)$ for all $x in U setminus p$, so I think $varphi_R(x)$ is an open map too. This might be relevant:
Theorem 22.1 in Munkres:
general-topology differential-geometry algebraic-topology manifolds quotient-spaces
Tu Manifolds Section 5.1
Definition of locally Euclidean of dimension n.
Example
To show $varphi_R: U setminus p to B setminus 0$ is also a homeomorphism, I think:
$varphi_R = r circ varphi circ j$ where $j: U setminus p to U$ is inclusion and $r$ is some function $r: B(0,varepsilon) to B(0,varepsilon) setminus 0$, $varphi_R$ is bijective because $varphi(p)=0$ and $varphi$ is bijective and $varphi_R$ is continuous if we can find a continuous $r$ because $j$ and $varphi$ are continuous. Then $varphi_R$ is a homeomorphism if we can find an $r$ and show either that $varphi_R$ is an open or closed map or that $varphi_R^{-1}$ is continuous.
Is that correct?
What $r$ can we select?
Must $r$ be a retraction? That is, is it insufficient to find a continuous $r$ that isn't a retraction, if it's possible?
Is it possible? (to find a continuous $r$ that isn't a retraction)
Why is $varphi_R^{-1}$ continuous?
- What is $varphi_R^{-1}$ anyway? I don't think $j^{-1}$ or $r^{-1}$ exist.
What properties of open or closed maps are there to say $varphi_R$ is an open or closed map because $varphi$ is an open or closed map and some other facts?
We have $varphi(x)=varphi_R(x)$ for all $x in U setminus p$, so I think $varphi_R(x)$ is an open map too. This might be relevant:
Theorem 22.1 in Munkres:
general-topology differential-geometry algebraic-topology manifolds quotient-spaces
general-topology differential-geometry algebraic-topology manifolds quotient-spaces
asked Nov 22 at 3:49
Jack Bauer
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