Why is there eight possible even extensions of a real finite length sequence?












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Apparently there is many versions of the discrete cosine transforms (DCT) mainly because we can perform an even extension of a real finite length sequence :



$$~~~~~~~~~~~~~~~~~~~~~~~~~~~x(n) ~~~~~~~~~~~~~, ~~n:0,...N-1$$



In eight different ways , but the only ways I can possibly see is the obvious one concatenating : $~~x(2N-1-n)~~$ at the end of $~~x(n)$ . What about the other seven remaining options ?










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  • 1




    $begingroup$
    Have you looked at the diagram in en.wikipedia.org/wiki/…?
    $endgroup$
    – Rahul
    Dec 20 '18 at 12:27
















0












$begingroup$


Apparently there is many versions of the discrete cosine transforms (DCT) mainly because we can perform an even extension of a real finite length sequence :



$$~~~~~~~~~~~~~~~~~~~~~~~~~~~x(n) ~~~~~~~~~~~~~, ~~n:0,...N-1$$



In eight different ways , but the only ways I can possibly see is the obvious one concatenating : $~~x(2N-1-n)~~$ at the end of $~~x(n)$ . What about the other seven remaining options ?










share|cite|improve this question









$endgroup$








  • 1




    $begingroup$
    Have you looked at the diagram in en.wikipedia.org/wiki/…?
    $endgroup$
    – Rahul
    Dec 20 '18 at 12:27














0












0








0





$begingroup$


Apparently there is many versions of the discrete cosine transforms (DCT) mainly because we can perform an even extension of a real finite length sequence :



$$~~~~~~~~~~~~~~~~~~~~~~~~~~~x(n) ~~~~~~~~~~~~~, ~~n:0,...N-1$$



In eight different ways , but the only ways I can possibly see is the obvious one concatenating : $~~x(2N-1-n)~~$ at the end of $~~x(n)$ . What about the other seven remaining options ?










share|cite|improve this question









$endgroup$




Apparently there is many versions of the discrete cosine transforms (DCT) mainly because we can perform an even extension of a real finite length sequence :



$$~~~~~~~~~~~~~~~~~~~~~~~~~~~x(n) ~~~~~~~~~~~~~, ~~n:0,...N-1$$



In eight different ways , but the only ways I can possibly see is the obvious one concatenating : $~~x(2N-1-n)~~$ at the end of $~~x(n)$ . What about the other seven remaining options ?







sequences-and-series fourier-analysis






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share|cite|improve this question










asked Dec 20 '18 at 12:23









HilbertHilbert

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1649








  • 1




    $begingroup$
    Have you looked at the diagram in en.wikipedia.org/wiki/…?
    $endgroup$
    – Rahul
    Dec 20 '18 at 12:27














  • 1




    $begingroup$
    Have you looked at the diagram in en.wikipedia.org/wiki/…?
    $endgroup$
    – Rahul
    Dec 20 '18 at 12:27








1




1




$begingroup$
Have you looked at the diagram in en.wikipedia.org/wiki/…?
$endgroup$
– Rahul
Dec 20 '18 at 12:27




$begingroup$
Have you looked at the diagram in en.wikipedia.org/wiki/…?
$endgroup$
– Rahul
Dec 20 '18 at 12:27










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