Finding highest value in a dictionary
up vote
7
down vote
favorite
I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.
Here is my problem:
I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this
{'country': [population, GDP], ...}
My task is to loop through this and find the country with the highest population or GDP then print:
'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')
In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).
def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo
for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k
return highPop,highCountry
While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))]
works. Does this just grab the first value it sees?
Thanks for your help in advance!
Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.
python computer-science
add a comment |
up vote
7
down vote
favorite
I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.
Here is my problem:
I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this
{'country': [population, GDP], ...}
My task is to loop through this and find the country with the highest population or GDP then print:
'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')
In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).
def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo
for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k
return highPop,highCountry
While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))]
works. Does this just grab the first value it sees?
Thanks for your help in advance!
Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.
python computer-science
3
There is the functionmax()
which can take something iterable (like the dict items). If you give akey
function as parameter which extracts the desired value (here: population) it will return the item you want.
– Michael Butscher
3 hours ago
add a comment |
up vote
7
down vote
favorite
up vote
7
down vote
favorite
I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.
Here is my problem:
I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this
{'country': [population, GDP], ...}
My task is to loop through this and find the country with the highest population or GDP then print:
'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')
In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).
def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo
for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k
return highPop,highCountry
While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))]
works. Does this just grab the first value it sees?
Thanks for your help in advance!
Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.
python computer-science
I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.
Here is my problem:
I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this
{'country': [population, GDP], ...}
My task is to loop through this and find the country with the highest population or GDP then print:
'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')
In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).
def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo
for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k
return highPop,highCountry
While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))]
works. Does this just grab the first value it sees?
Thanks for your help in advance!
Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.
python computer-science
python computer-science
edited 59 mins ago
asked 3 hours ago
Luke Kelly
455
455
3
There is the functionmax()
which can take something iterable (like the dict items). If you give akey
function as parameter which extracts the desired value (here: population) it will return the item you want.
– Michael Butscher
3 hours ago
add a comment |
3
There is the functionmax()
which can take something iterable (like the dict items). If you give akey
function as parameter which extracts the desired value (here: population) it will return the item you want.
– Michael Butscher
3 hours ago
3
3
There is the function
max()
which can take something iterable (like the dict items). If you give a key
function as parameter which extracts the desired value (here: population) it will return the item you want.– Michael Butscher
3 hours ago
There is the function
max()
which can take something iterable (like the dict items). If you give a key
function as parameter which extracts the desired value (here: population) it will return the item you want.– Michael Butscher
3 hours ago
add a comment |
3 Answers
3
active
oldest
votes
up vote
7
down vote
accepted
I think you're looking for this:
max(worldInfo.items(), key=lambda x: x[1][0])
This will return both the country name and its info. For instance:
('france', [100, 22])
The next() and iter() functions are for python iterators. For example:
mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)
print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry
Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago
2
Themax()
function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based onx[1][0]
. In this instance if the item is('france', [100, 22])
thenx[1][0]
is100
. Make sense?
– Conner
2 hours ago
I think so. Thanks again
– Luke Kelly
2 hours ago
add a comment |
up vote
7
down vote
Use the max()
function, like so:
max(item[0] for item in county_dict.values()) #use item[1] for GDP!
Also try storing the values not in a list ([a, b]
) but in a tuple ((a, b)
).
Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:
max(data[0], country for country, data in country_dict.items())
So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago
@LukeKelly Well, you could get the name from the value returned bymax()
if the values are always different. A loop would also work but I would not recommend it.
– Ethan K
3 hours ago
1
max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago
@iamanigeeit That works, nice! I would just swap the values of the first part to read:country, data[0]
Other than that, awesome!
– Ethan K
2 hours ago
but tuples are compared from first element... that's why i putdata[0]
first
– iamanigeeit
2 hours ago
|
show 1 more comment
up vote
6
down vote
An efficient solution to get the key with the highest value: you can use the max
function this way:
highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())
And obviously :
highPop = worldInfo[highCountry][0]
1
Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea usingmax()
withkey
for sorting!
– Ethan K
2 hours ago
I'm using both of the provided comments to fix this .highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP!
Is there any reason I shouldn't' do this?
– Luke Kelly
2 hours ago
Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago
@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago
unless it's Python 2, then we'd need.itervalues()
and.iteritems()
– iamanigeeit
2 hours ago
|
show 1 more comment
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
7
down vote
accepted
I think you're looking for this:
max(worldInfo.items(), key=lambda x: x[1][0])
This will return both the country name and its info. For instance:
('france', [100, 22])
The next() and iter() functions are for python iterators. For example:
mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)
print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry
Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago
2
Themax()
function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based onx[1][0]
. In this instance if the item is('france', [100, 22])
thenx[1][0]
is100
. Make sense?
– Conner
2 hours ago
I think so. Thanks again
– Luke Kelly
2 hours ago
add a comment |
up vote
7
down vote
accepted
I think you're looking for this:
max(worldInfo.items(), key=lambda x: x[1][0])
This will return both the country name and its info. For instance:
('france', [100, 22])
The next() and iter() functions are for python iterators. For example:
mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)
print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry
Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago
2
Themax()
function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based onx[1][0]
. In this instance if the item is('france', [100, 22])
thenx[1][0]
is100
. Make sense?
– Conner
2 hours ago
I think so. Thanks again
– Luke Kelly
2 hours ago
add a comment |
up vote
7
down vote
accepted
up vote
7
down vote
accepted
I think you're looking for this:
max(worldInfo.items(), key=lambda x: x[1][0])
This will return both the country name and its info. For instance:
('france', [100, 22])
The next() and iter() functions are for python iterators. For example:
mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)
print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry
I think you're looking for this:
max(worldInfo.items(), key=lambda x: x[1][0])
This will return both the country name and its info. For instance:
('france', [100, 22])
The next() and iter() functions are for python iterators. For example:
mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)
print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry
answered 2 hours ago
Conner
22.6k84567
22.6k84567
Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago
2
Themax()
function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based onx[1][0]
. In this instance if the item is('france', [100, 22])
thenx[1][0]
is100
. Make sense?
– Conner
2 hours ago
I think so. Thanks again
– Luke Kelly
2 hours ago
add a comment |
Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago
2
Themax()
function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based onx[1][0]
. In this instance if the item is('france', [100, 22])
thenx[1][0]
is100
. Make sense?
– Conner
2 hours ago
I think so. Thanks again
– Luke Kelly
2 hours ago
Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago
Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago
2
2
The
max()
function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]
. In this instance if the item is ('france', [100, 22])
then x[1][0]
is 100
. Make sense?– Conner
2 hours ago
The
max()
function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]
. In this instance if the item is ('france', [100, 22])
then x[1][0]
is 100
. Make sense?– Conner
2 hours ago
I think so. Thanks again
– Luke Kelly
2 hours ago
I think so. Thanks again
– Luke Kelly
2 hours ago
add a comment |
up vote
7
down vote
Use the max()
function, like so:
max(item[0] for item in county_dict.values()) #use item[1] for GDP!
Also try storing the values not in a list ([a, b]
) but in a tuple ((a, b)
).
Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:
max(data[0], country for country, data in country_dict.items())
So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago
@LukeKelly Well, you could get the name from the value returned bymax()
if the values are always different. A loop would also work but I would not recommend it.
– Ethan K
3 hours ago
1
max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago
@iamanigeeit That works, nice! I would just swap the values of the first part to read:country, data[0]
Other than that, awesome!
– Ethan K
2 hours ago
but tuples are compared from first element... that's why i putdata[0]
first
– iamanigeeit
2 hours ago
|
show 1 more comment
up vote
7
down vote
Use the max()
function, like so:
max(item[0] for item in county_dict.values()) #use item[1] for GDP!
Also try storing the values not in a list ([a, b]
) but in a tuple ((a, b)
).
Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:
max(data[0], country for country, data in country_dict.items())
So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago
@LukeKelly Well, you could get the name from the value returned bymax()
if the values are always different. A loop would also work but I would not recommend it.
– Ethan K
3 hours ago
1
max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago
@iamanigeeit That works, nice! I would just swap the values of the first part to read:country, data[0]
Other than that, awesome!
– Ethan K
2 hours ago
but tuples are compared from first element... that's why i putdata[0]
first
– iamanigeeit
2 hours ago
|
show 1 more comment
up vote
7
down vote
up vote
7
down vote
Use the max()
function, like so:
max(item[0] for item in county_dict.values()) #use item[1] for GDP!
Also try storing the values not in a list ([a, b]
) but in a tuple ((a, b)
).
Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:
max(data[0], country for country, data in country_dict.items())
Use the max()
function, like so:
max(item[0] for item in county_dict.values()) #use item[1] for GDP!
Also try storing the values not in a list ([a, b]
) but in a tuple ((a, b)
).
Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:
max(data[0], country for country, data in country_dict.items())
edited 2 hours ago
answered 3 hours ago
Ethan K
127111
127111
So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago
@LukeKelly Well, you could get the name from the value returned bymax()
if the values are always different. A loop would also work but I would not recommend it.
– Ethan K
3 hours ago
1
max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago
@iamanigeeit That works, nice! I would just swap the values of the first part to read:country, data[0]
Other than that, awesome!
– Ethan K
2 hours ago
but tuples are compared from first element... that's why i putdata[0]
first
– iamanigeeit
2 hours ago
|
show 1 more comment
So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago
@LukeKelly Well, you could get the name from the value returned bymax()
if the values are always different. A loop would also work but I would not recommend it.
– Ethan K
3 hours ago
1
max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago
@iamanigeeit That works, nice! I would just swap the values of the first part to read:country, data[0]
Other than that, awesome!
– Ethan K
2 hours ago
but tuples are compared from first element... that's why i putdata[0]
first
– iamanigeeit
2 hours ago
So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago
So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago
@LukeKelly Well, you could get the name from the value returned by
max()
if the values are always different. A loop would also work but I would not recommend it.– Ethan K
3 hours ago
@LukeKelly Well, you could get the name from the value returned by
max()
if the values are always different. A loop would also work but I would not recommend it.– Ethan K
3 hours ago
1
1
max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago
max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago
@iamanigeeit That works, nice! I would just swap the values of the first part to read:
country, data[0]
Other than that, awesome!– Ethan K
2 hours ago
@iamanigeeit That works, nice! I would just swap the values of the first part to read:
country, data[0]
Other than that, awesome!– Ethan K
2 hours ago
but tuples are compared from first element... that's why i put
data[0]
first– iamanigeeit
2 hours ago
but tuples are compared from first element... that's why i put
data[0]
first– iamanigeeit
2 hours ago
|
show 1 more comment
up vote
6
down vote
An efficient solution to get the key with the highest value: you can use the max
function this way:
highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())
And obviously :
highPop = worldInfo[highCountry][0]
1
Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea usingmax()
withkey
for sorting!
– Ethan K
2 hours ago
I'm using both of the provided comments to fix this .highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP!
Is there any reason I shouldn't' do this?
– Luke Kelly
2 hours ago
Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago
@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago
unless it's Python 2, then we'd need.itervalues()
and.iteritems()
– iamanigeeit
2 hours ago
|
show 1 more comment
up vote
6
down vote
An efficient solution to get the key with the highest value: you can use the max
function this way:
highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())
And obviously :
highPop = worldInfo[highCountry][0]
1
Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea usingmax()
withkey
for sorting!
– Ethan K
2 hours ago
I'm using both of the provided comments to fix this .highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP!
Is there any reason I shouldn't' do this?
– Luke Kelly
2 hours ago
Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago
@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago
unless it's Python 2, then we'd need.itervalues()
and.iteritems()
– iamanigeeit
2 hours ago
|
show 1 more comment
up vote
6
down vote
up vote
6
down vote
An efficient solution to get the key with the highest value: you can use the max
function this way:
highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())
And obviously :
highPop = worldInfo[highCountry][0]
An efficient solution to get the key with the highest value: you can use the max
function this way:
highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())
And obviously :
highPop = worldInfo[highCountry][0]
edited 2 hours ago
answered 3 hours ago
Axel Puig
1536
1536
1
Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea usingmax()
withkey
for sorting!
– Ethan K
2 hours ago
I'm using both of the provided comments to fix this .highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP!
Is there any reason I shouldn't' do this?
– Luke Kelly
2 hours ago
Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago
@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago
unless it's Python 2, then we'd need.itervalues()
and.iteritems()
– iamanigeeit
2 hours ago
|
show 1 more comment
1
Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea usingmax()
withkey
for sorting!
– Ethan K
2 hours ago
I'm using both of the provided comments to fix this .highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP!
Is there any reason I shouldn't' do this?
– Luke Kelly
2 hours ago
Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago
@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago
unless it's Python 2, then we'd need.itervalues()
and.iteritems()
– iamanigeeit
2 hours ago
1
1
Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using
max()
with key
for sorting!– Ethan K
2 hours ago
Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using
max()
with key
for sorting!– Ethan K
2 hours ago
I'm using both of the provided comments to fix this .
highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP!
Is there any reason I shouldn't' do this?– Luke Kelly
2 hours ago
I'm using both of the provided comments to fix this .
highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])
highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP!
Is there any reason I shouldn't' do this?– Luke Kelly
2 hours ago
Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago
Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago
@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago
@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago
unless it's Python 2, then we'd need
.itervalues()
and .iteritems()
– iamanigeeit
2 hours ago
unless it's Python 2, then we'd need
.itervalues()
and .iteritems()
– iamanigeeit
2 hours ago
|
show 1 more comment
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3
There is the function
max()
which can take something iterable (like the dict items). If you give akey
function as parameter which extracts the desired value (here: population) it will return the item you want.– Michael Butscher
3 hours ago