Finding highest value in a dictionary











up vote
7
down vote

favorite
1












I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.



Here is my problem:



I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this



{'country': [population, GDP], ...}


My task is to loop through this and find the country with the highest population or GDP then print:



'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')


In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).



def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo

for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k

return highPop,highCountry


While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))] works. Does this just grab the first value it sees?



Thanks for your help in advance!



Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.










share|improve this question




















  • 3




    There is the function max() which can take something iterable (like the dict items). If you give a key function as parameter which extracts the desired value (here: population) it will return the item you want.
    – Michael Butscher
    3 hours ago















up vote
7
down vote

favorite
1












I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.



Here is my problem:



I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this



{'country': [population, GDP], ...}


My task is to loop through this and find the country with the highest population or GDP then print:



'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')


In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).



def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo

for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k

return highPop,highCountry


While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))] works. Does this just grab the first value it sees?



Thanks for your help in advance!



Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.










share|improve this question




















  • 3




    There is the function max() which can take something iterable (like the dict items). If you give a key function as parameter which extracts the desired value (here: population) it will return the item you want.
    – Michael Butscher
    3 hours ago













up vote
7
down vote

favorite
1









up vote
7
down vote

favorite
1






1





I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.



Here is my problem:



I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this



{'country': [population, GDP], ...}


My task is to loop through this and find the country with the highest population or GDP then print:



'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')


In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).



def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo

for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k

return highPop,highCountry


While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))] works. Does this just grab the first value it sees?



Thanks for your help in advance!



Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.










share|improve this question















I'm new to programming and currently taking a CSC 110 class. Our assignment is to create a bunch functions that do all sorts of things with some data that is given. I have taken all that data and put it into a dictionary but I'm having some trouble getting the data I want out of it.



Here is my problem:



I have a dictionary that stores a bunch of countries followed by a list that includes their population and GDP. Formatted something like this



{'country': [population, GDP], ...}


My task is to loop through this and find the country with the highest population or GDP then print:



'The country with the highest population is ' + highCountry+
' with a population of ' + format(highPop, ',.0f')+'.')


In order to do this I wrote this function (this one is specifically for highest population but they all look about the same).



def highestPop(worldInfo):
highPop = worldInfo[next(iter(worldInfo))][0] #Grabs first countries Population
highCountry = next(iter(worldInfo))#Grabs first country in worldInfo

for k,v in worldInfo.items():
if v[0] > highPop:
highPop = v[0]
highCountry = k

return highPop,highCountry


While this is working for me I gotta think there is an easier way to do this. Also I'm not 100% sure how [next(iter(worldInfo))] works. Does this just grab the first value it sees?



Thanks for your help in advance!



Edit: Sorry I guess I wasn't clear. I need to pass the countries population but also the countries name. So I can print both of them in my main function.







python computer-science






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 59 mins ago

























asked 3 hours ago









Luke Kelly

455




455








  • 3




    There is the function max() which can take something iterable (like the dict items). If you give a key function as parameter which extracts the desired value (here: population) it will return the item you want.
    – Michael Butscher
    3 hours ago














  • 3




    There is the function max() which can take something iterable (like the dict items). If you give a key function as parameter which extracts the desired value (here: population) it will return the item you want.
    – Michael Butscher
    3 hours ago








3




3




There is the function max() which can take something iterable (like the dict items). If you give a key function as parameter which extracts the desired value (here: population) it will return the item you want.
– Michael Butscher
3 hours ago




There is the function max() which can take something iterable (like the dict items). If you give a key function as parameter which extracts the desired value (here: population) it will return the item you want.
– Michael Butscher
3 hours ago












3 Answers
3






active

oldest

votes

















up vote
7
down vote



accepted










I think you're looking for this:



max(worldInfo.items(), key=lambda x: x[1][0])


This will return both the country name and its info. For instance:



('france', [100, 22])


The next() and iter() functions are for python iterators. For example:



mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)

print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry





share|improve this answer





















  • Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
    – Luke Kelly
    2 hours ago








  • 2




    The max() function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]. In this instance if the item is ('france', [100, 22]) then x[1][0] is 100. Make sense?
    – Conner
    2 hours ago












  • I think so. Thanks again
    – Luke Kelly
    2 hours ago


















up vote
7
down vote













Use the max() function, like so:



max(item[0] for item in county_dict.values()) #use item[1] for GDP!


Also try storing the values not in a list ([a, b]) but in a tuple ((a, b)).



Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:



max(data[0], country for country, data in country_dict.items())





share|improve this answer























  • So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
    – Luke Kelly
    3 hours ago










  • @LukeKelly Well, you could get the name from the value returned by max() if the values are always different. A loop would also work but I would not recommend it.
    – Ethan K
    3 hours ago






  • 1




    max(data[0], country for country, data in country_dict.items())
    – iamanigeeit
    2 hours ago










  • @iamanigeeit That works, nice! I would just swap the values of the first part to read: country, data[0] Other than that, awesome!
    – Ethan K
    2 hours ago










  • but tuples are compared from first element... that's why i put data[0] first
    – iamanigeeit
    2 hours ago


















up vote
6
down vote













An efficient solution to get the key with the highest value: you can use the max function this way:



highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])


The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())



And obviously :



highPop = worldInfo[highCountry][0]





share|improve this answer



















  • 1




    Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using max() with key for sorting!
    – Ethan K
    2 hours ago










  • I'm using both of the provided comments to fix this . highCountry = max(worldInfo, key=lambda k: worldInfo[k][0]) highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP! Is there any reason I shouldn't' do this?
    – Luke Kelly
    2 hours ago












  • Indeed @EthanK, however you can't get the key efficiently. :)
    – Axel Puig
    2 hours ago












  • @LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
    – Axel Puig
    2 hours ago










  • unless it's Python 2, then we'd need .itervalues() and .iteritems()
    – iamanigeeit
    2 hours ago











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53604668%2ffinding-highest-value-in-a-dictionary%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
7
down vote



accepted










I think you're looking for this:



max(worldInfo.items(), key=lambda x: x[1][0])


This will return both the country name and its info. For instance:



('france', [100, 22])


The next() and iter() functions are for python iterators. For example:



mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)

print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry





share|improve this answer





















  • Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
    – Luke Kelly
    2 hours ago








  • 2




    The max() function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]. In this instance if the item is ('france', [100, 22]) then x[1][0] is 100. Make sense?
    – Conner
    2 hours ago












  • I think so. Thanks again
    – Luke Kelly
    2 hours ago















up vote
7
down vote



accepted










I think you're looking for this:



max(worldInfo.items(), key=lambda x: x[1][0])


This will return both the country name and its info. For instance:



('france', [100, 22])


The next() and iter() functions are for python iterators. For example:



mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)

print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry





share|improve this answer





















  • Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
    – Luke Kelly
    2 hours ago








  • 2




    The max() function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]. In this instance if the item is ('france', [100, 22]) then x[1][0] is 100. Make sense?
    – Conner
    2 hours ago












  • I think so. Thanks again
    – Luke Kelly
    2 hours ago













up vote
7
down vote



accepted







up vote
7
down vote



accepted






I think you're looking for this:



max(worldInfo.items(), key=lambda x: x[1][0])


This will return both the country name and its info. For instance:



('france', [100, 22])


The next() and iter() functions are for python iterators. For example:



mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)

print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry





share|improve this answer












I think you're looking for this:



max(worldInfo.items(), key=lambda x: x[1][0])


This will return both the country name and its info. For instance:



('france', [100, 22])


The next() and iter() functions are for python iterators. For example:



mytuple = ("apple", "banana", "cherry")
myit = iter(mytuple)

print(next(myit)) #=> apple
print(next(myit)) #=> banana
print(next(myit)) #=> cherry






share|improve this answer












share|improve this answer



share|improve this answer










answered 2 hours ago









Conner

22.6k84567




22.6k84567












  • Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
    – Luke Kelly
    2 hours ago








  • 2




    The max() function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]. In this instance if the item is ('france', [100, 22]) then x[1][0] is 100. Make sense?
    – Conner
    2 hours ago












  • I think so. Thanks again
    – Luke Kelly
    2 hours ago


















  • Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
    – Luke Kelly
    2 hours ago








  • 2




    The max() function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]. In this instance if the item is ('france', [100, 22]) then x[1][0] is 100. Make sense?
    – Conner
    2 hours ago












  • I think so. Thanks again
    – Luke Kelly
    2 hours ago
















Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago






Yes this is exactly what i was looking for. Now I just need to spend 30 minutes figuring out what all that means.
– Luke Kelly
2 hours ago






2




2




The max() function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]. In this instance if the item is ('france', [100, 22]) then x[1][0] is 100. Make sense?
– Conner
2 hours ago






The max() function can work on python "iterables" which is a fancy word for anything that can be cycled or looped through. Thus it cycles or loops through the thing you put it in it and spits out the item that's the highest. But how does it judge a tuple that's highest? You have to specify a key (some specification for how to judge each item). The key=lambda etc specifies a function that given an item (x), judge that item based on x[1][0]. In this instance if the item is ('france', [100, 22]) then x[1][0] is 100. Make sense?
– Conner
2 hours ago














I think so. Thanks again
– Luke Kelly
2 hours ago




I think so. Thanks again
– Luke Kelly
2 hours ago












up vote
7
down vote













Use the max() function, like so:



max(item[0] for item in county_dict.values()) #use item[1] for GDP!


Also try storing the values not in a list ([a, b]) but in a tuple ((a, b)).



Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:



max(data[0], country for country, data in country_dict.items())





share|improve this answer























  • So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
    – Luke Kelly
    3 hours ago










  • @LukeKelly Well, you could get the name from the value returned by max() if the values are always different. A loop would also work but I would not recommend it.
    – Ethan K
    3 hours ago






  • 1




    max(data[0], country for country, data in country_dict.items())
    – iamanigeeit
    2 hours ago










  • @iamanigeeit That works, nice! I would just swap the values of the first part to read: country, data[0] Other than that, awesome!
    – Ethan K
    2 hours ago










  • but tuples are compared from first element... that's why i put data[0] first
    – iamanigeeit
    2 hours ago















up vote
7
down vote













Use the max() function, like so:



max(item[0] for item in county_dict.values()) #use item[1] for GDP!


Also try storing the values not in a list ([a, b]) but in a tuple ((a, b)).



Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:



max(data[0], country for country, data in country_dict.items())





share|improve this answer























  • So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
    – Luke Kelly
    3 hours ago










  • @LukeKelly Well, you could get the name from the value returned by max() if the values are always different. A loop would also work but I would not recommend it.
    – Ethan K
    3 hours ago






  • 1




    max(data[0], country for country, data in country_dict.items())
    – iamanigeeit
    2 hours ago










  • @iamanigeeit That works, nice! I would just swap the values of the first part to read: country, data[0] Other than that, awesome!
    – Ethan K
    2 hours ago










  • but tuples are compared from first element... that's why i put data[0] first
    – iamanigeeit
    2 hours ago













up vote
7
down vote










up vote
7
down vote









Use the max() function, like so:



max(item[0] for item in county_dict.values()) #use item[1] for GDP!


Also try storing the values not in a list ([a, b]) but in a tuple ((a, b)).



Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:



max(data[0], country for country, data in country_dict.items())





share|improve this answer














Use the max() function, like so:



max(item[0] for item in county_dict.values()) #use item[1] for GDP!


Also try storing the values not in a list ([a, b]) but in a tuple ((a, b)).



Edit: Like iamanigeeit said in the comments, this works to give you the country name as well:



max(data[0], country for country, data in country_dict.items())






share|improve this answer














share|improve this answer



share|improve this answer








edited 2 hours ago

























answered 3 hours ago









Ethan K

127111




127111












  • So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
    – Luke Kelly
    3 hours ago










  • @LukeKelly Well, you could get the name from the value returned by max() if the values are always different. A loop would also work but I would not recommend it.
    – Ethan K
    3 hours ago






  • 1




    max(data[0], country for country, data in country_dict.items())
    – iamanigeeit
    2 hours ago










  • @iamanigeeit That works, nice! I would just swap the values of the first part to read: country, data[0] Other than that, awesome!
    – Ethan K
    2 hours ago










  • but tuples are compared from first element... that's why i put data[0] first
    – iamanigeeit
    2 hours ago


















  • So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
    – Luke Kelly
    3 hours ago










  • @LukeKelly Well, you could get the name from the value returned by max() if the values are always different. A loop would also work but I would not recommend it.
    – Ethan K
    3 hours ago






  • 1




    max(data[0], country for country, data in country_dict.items())
    – iamanigeeit
    2 hours ago










  • @iamanigeeit That works, nice! I would just swap the values of the first part to read: country, data[0] Other than that, awesome!
    – Ethan K
    2 hours ago










  • but tuples are compared from first element... that's why i put data[0] first
    – iamanigeeit
    2 hours ago
















So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago




So i have to pass back not just the countries population but also the countries name as well. Is there a way to get that info from what is given above?
– Luke Kelly
3 hours ago












@LukeKelly Well, you could get the name from the value returned by max() if the values are always different. A loop would also work but I would not recommend it.
– Ethan K
3 hours ago




@LukeKelly Well, you could get the name from the value returned by max() if the values are always different. A loop would also work but I would not recommend it.
– Ethan K
3 hours ago




1




1




max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago




max(data[0], country for country, data in country_dict.items())
– iamanigeeit
2 hours ago












@iamanigeeit That works, nice! I would just swap the values of the first part to read: country, data[0] Other than that, awesome!
– Ethan K
2 hours ago




@iamanigeeit That works, nice! I would just swap the values of the first part to read: country, data[0] Other than that, awesome!
– Ethan K
2 hours ago












but tuples are compared from first element... that's why i put data[0] first
– iamanigeeit
2 hours ago




but tuples are compared from first element... that's why i put data[0] first
– iamanigeeit
2 hours ago










up vote
6
down vote













An efficient solution to get the key with the highest value: you can use the max function this way:



highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])


The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())



And obviously :



highPop = worldInfo[highCountry][0]





share|improve this answer



















  • 1




    Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using max() with key for sorting!
    – Ethan K
    2 hours ago










  • I'm using both of the provided comments to fix this . highCountry = max(worldInfo, key=lambda k: worldInfo[k][0]) highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP! Is there any reason I shouldn't' do this?
    – Luke Kelly
    2 hours ago












  • Indeed @EthanK, however you can't get the key efficiently. :)
    – Axel Puig
    2 hours ago












  • @LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
    – Axel Puig
    2 hours ago










  • unless it's Python 2, then we'd need .itervalues() and .iteritems()
    – iamanigeeit
    2 hours ago















up vote
6
down vote













An efficient solution to get the key with the highest value: you can use the max function this way:



highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])


The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())



And obviously :



highPop = worldInfo[highCountry][0]





share|improve this answer



















  • 1




    Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using max() with key for sorting!
    – Ethan K
    2 hours ago










  • I'm using both of the provided comments to fix this . highCountry = max(worldInfo, key=lambda k: worldInfo[k][0]) highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP! Is there any reason I shouldn't' do this?
    – Luke Kelly
    2 hours ago












  • Indeed @EthanK, however you can't get the key efficiently. :)
    – Axel Puig
    2 hours ago












  • @LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
    – Axel Puig
    2 hours ago










  • unless it's Python 2, then we'd need .itervalues() and .iteritems()
    – iamanigeeit
    2 hours ago













up vote
6
down vote










up vote
6
down vote









An efficient solution to get the key with the highest value: you can use the max function this way:



highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])


The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())



And obviously :



highPop = worldInfo[highCountry][0]





share|improve this answer














An efficient solution to get the key with the highest value: you can use the max function this way:



highCountry = max(worldInfo, key=lambda k: worldInfo[k][0])


The key argument is a function that specifies what values you want to use to determine the max.max(data[0], country for country, data in country_dict.items())



And obviously :



highPop = worldInfo[highCountry][0]






share|improve this answer














share|improve this answer



share|improve this answer








edited 2 hours ago

























answered 3 hours ago









Axel Puig

1536




1536








  • 1




    Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using max() with key for sorting!
    – Ethan K
    2 hours ago










  • I'm using both of the provided comments to fix this . highCountry = max(worldInfo, key=lambda k: worldInfo[k][0]) highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP! Is there any reason I shouldn't' do this?
    – Luke Kelly
    2 hours ago












  • Indeed @EthanK, however you can't get the key efficiently. :)
    – Axel Puig
    2 hours ago












  • @LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
    – Axel Puig
    2 hours ago










  • unless it's Python 2, then we'd need .itervalues() and .iteritems()
    – iamanigeeit
    2 hours ago














  • 1




    Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using max() with key for sorting!
    – Ethan K
    2 hours ago










  • I'm using both of the provided comments to fix this . highCountry = max(worldInfo, key=lambda k: worldInfo[k][0]) highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP! Is there any reason I shouldn't' do this?
    – Luke Kelly
    2 hours ago












  • Indeed @EthanK, however you can't get the key efficiently. :)
    – Axel Puig
    2 hours ago












  • @LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
    – Axel Puig
    2 hours ago










  • unless it's Python 2, then we'd need .itervalues() and .iteritems()
    – iamanigeeit
    2 hours ago








1




1




Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using max() with key for sorting!
– Ethan K
2 hours ago




Correction - I used a generator comprension, which generates the values lazily, so it is not slow (or less efficient). However, great idea using max() with key for sorting!
– Ethan K
2 hours ago












I'm using both of the provided comments to fix this . highCountry = max(worldInfo, key=lambda k: worldInfo[k][0]) highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP! Is there any reason I shouldn't' do this?
– Luke Kelly
2 hours ago






I'm using both of the provided comments to fix this . highCountry = max(worldInfo, key=lambda k: worldInfo[k][0]) highPop = max(item[0] for item in worldInfo.values()) #use item[1] for GDP! Is there any reason I shouldn't' do this?
– Luke Kelly
2 hours ago














Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago






Indeed @EthanK, however you can't get the key efficiently. :)
– Axel Puig
2 hours ago














@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago




@LukeKelly once you have the key, you can directly access the corresponding value, it is more efficient. See my edited answer.
– Axel Puig
2 hours ago












unless it's Python 2, then we'd need .itervalues() and .iteritems()
– iamanigeeit
2 hours ago




unless it's Python 2, then we'd need .itervalues() and .iteritems()
– iamanigeeit
2 hours ago


















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.





Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


Please pay close attention to the following guidance:


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53604668%2ffinding-highest-value-in-a-dictionary%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Le Mesnil-Réaume

Ida-Boy-Ed-Garten

web3.py web3.isConnected() returns false always