Create all numbers from 1-100 using 1,3,3,6
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Create all the numbers from $1$ to $100$ using the numbers $1$,$3$,$3$, and $6$.
- You can only use each number once, except for the $3$, of which you have two.
- You can use addition ($x+y$), subtraction ($x-y$), division ($frac{x}{y}$), multiplication ($xtimes y$), exponentiation ($x^y$) and roots ($sqrt[leftroot{-2}uproot{2}x]{y}$).
- You can combine numbers like $1$ and $3$ to $13$ etc.
- You must use all numbers.
calculation-puzzle formation-of-numbers
edited 4 hours ago
Hugh
1,4861617
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
New contributor
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$endgroup$
add a comment |
$begingroup$
Create all the numbers from $1$ to $100$ using the numbers $1$,$3$,$3$, and $6$.
- You can only use each number once, except for the $3$, of which you have two.
- You can use addition ($x+y$), subtraction ($x-y$), division ($frac{x}{y}$), multiplication ($xtimes y$), exponentiation ($x^y$) and roots ($sqrt[leftroot{-2}uproot{2}x]{y}$).
- You can combine numbers like $1$ and $3$ to $13$ etc.
- You must use all numbers.
calculation-puzzle formation-of-numbers
edited 4 hours ago
Hugh
1,4861617
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
New contributor
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
2
$begingroup$
Can we combine the results of operations? For example, is $(1+3) | 36 = 436$ (where | indicates concatenation)
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– Hugh
5 hours ago
1
$begingroup$
If we need to take a square root, is the two implied?
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– Hugh
5 hours ago
1
$begingroup$
can we use factorial?
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– Omega Krypton
4 hours ago
2
$begingroup$
Factorials are most likely out, but what about parentheses, unary minus (like starting with -1) and decimal points?
$endgroup$
– Bass
3 hours ago
$begingroup$
If decimal is allowed then round would probably valid too?
$endgroup$
– Mukyuu
13 mins ago
add a comment |
$begingroup$
Create all the numbers from $1$ to $100$ using the numbers $1$,$3$,$3$, and $6$.
- You can only use each number once, except for the $3$, of which you have two.
- You can use addition ($x+y$), subtraction ($x-y$), division ($frac{x}{y}$), multiplication ($xtimes y$), exponentiation ($x^y$) and roots ($sqrt[leftroot{-2}uproot{2}x]{y}$).
- You can combine numbers like $1$ and $3$ to $13$ etc.
- You must use all numbers.
calculation-puzzle formation-of-numbers
edited 4 hours ago
Hugh
1,4861617
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
New contributor
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Create all the numbers from $1$ to $100$ using the numbers $1$,$3$,$3$, and $6$.
- You can only use each number once, except for the $3$, of which you have two.
- You can use addition ($x+y$), subtraction ($x-y$), division ($frac{x}{y}$), multiplication ($xtimes y$), exponentiation ($x^y$) and roots ($sqrt[leftroot{-2}uproot{2}x]{y}$).
- You can combine numbers like $1$ and $3$ to $13$ etc.
- You must use all numbers.
calculation-puzzle formation-of-numbers
calculation-puzzle formation-of-numbers
edited 4 hours ago
Hugh
1,4861617
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
New contributor
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 4 hours ago
Hugh
1,4861617
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
New contributor
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 4 hours ago
Hugh
1,4861617
edited 4 hours ago
Hugh
1,4861617
edited 4 hours ago
Hugh
1,4861617
1,4861617
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
New contributor
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
asked 5 hours ago
Michał UraszewskiMichał Uraszewski
112
112
New contributor
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Michał Uraszewski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
$begingroup$
Can we combine the results of operations? For example, is $(1+3) | 36 = 436$ (where | indicates concatenation)
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– Hugh
5 hours ago
1
$begingroup$
If we need to take a square root, is the two implied?
$endgroup$
– Hugh
5 hours ago
1
$begingroup$
can we use factorial?
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– Omega Krypton
4 hours ago
2
$begingroup$
Factorials are most likely out, but what about parentheses, unary minus (like starting with -1) and decimal points?
$endgroup$
– Bass
3 hours ago
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If decimal is allowed then round would probably valid too?
$endgroup$
– Mukyuu
13 mins ago
add a comment |
2
$begingroup$
Can we combine the results of operations? For example, is $(1+3) | 36 = 436$ (where | indicates concatenation)
$endgroup$
– Hugh
5 hours ago
1
$begingroup$
If we need to take a square root, is the two implied?
$endgroup$
– Hugh
5 hours ago
1
$begingroup$
can we use factorial?
$endgroup$
– Omega Krypton
4 hours ago
2
$begingroup$
Factorials are most likely out, but what about parentheses, unary minus (like starting with -1) and decimal points?
$endgroup$
– Bass
3 hours ago
$begingroup$
If decimal is allowed then round would probably valid too?
$endgroup$
– Mukyuu
13 mins ago
2
2
$begingroup$
Can we combine the results of operations? For example, is $(1+3) | 36 = 436$ (where | indicates concatenation)
$endgroup$
– Hugh
5 hours ago
$begingroup$
Can we combine the results of operations? For example, is $(1+3) | 36 = 436$ (where | indicates concatenation)
$endgroup$
– Hugh
5 hours ago
1
1
$begingroup$
If we need to take a square root, is the two implied?
$endgroup$
– Hugh
5 hours ago
$begingroup$
If we need to take a square root, is the two implied?
$endgroup$
– Hugh
5 hours ago
1
1
$begingroup$
can we use factorial?
$endgroup$
– Omega Krypton
4 hours ago
$begingroup$
can we use factorial?
$endgroup$
– Omega Krypton
4 hours ago
2
2
$begingroup$
Factorials are most likely out, but what about parentheses, unary minus (like starting with -1) and decimal points?
$endgroup$
– Bass
3 hours ago
$begingroup$
Factorials are most likely out, but what about parentheses, unary minus (like starting with -1) and decimal points?
$endgroup$
– Bass
3 hours ago
$begingroup$
If decimal is allowed then round would probably valid too?
$endgroup$
– Mukyuu
13 mins ago
$begingroup$
If decimal is allowed then round would probably valid too?
$endgroup$
– Mukyuu
13 mins ago
add a comment |
5 Answers
5
active
oldest
votes
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These get harder with larger numbers, but here are the first couple with the digits in order:
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
21: $ 1 * 3^3 - 6 $
22: $ 13 + 3 + 6$
23: $ -13+36 $
24: $ (1+3)timessqrt{36}$
25: $ 1 - 3 + sqrt3^6$
26: $ -1+33-6$
27: $ 1*33-6 $
28: $ 1+33-6$
29: $ -1 + 3 + sqrt3^6$
30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50 (getting much harder now, so I'll just press the submit button and let others continue)
41: $ $
42: $ (1+3+3)times 6$
43: $ $
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ $
49: $13+36$
50: $ $
answered 2 hours ago
BassBass
28.7k470176
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add a comment |
$begingroup$
Here are some:
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
22: (omega kyrpton did some) $3 * 6 + 3 + 1$
23: $3 ^ 3 - 6 * 1$
24: $3 ^ 3 - (6 - 1)$
I will do more later.
answered 5 hours ago
Yout RiedYout Ried
769119
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add a comment |
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Adding some more...
1-20: (Credits to @YoutRied)
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
21-29
21: $3 * 6 + 3 * 1$
22: $( 1 + 3 ) ! - ( 6 / 3 )$
23: $( 1 + 3 ) ! - ( 6 - 3 )$
24: $( 6 - 3 / 3 - 1 ) !$
25: $1 * 3 ^ 3 - floor(sqrt{6})$
26: $( 6 - 3 ) ^ 3 - 1$
27: $( 6 - 3 ) ^ 3 * 1$
28: $( 6 - 3 ) ^ 3 + 1$
29: $31 - 6 / 3$
41-50: (Credits to @Bass for 42, 45, 49)
41: $ (-1+3!)+36 $
42: $ (1+3+3)times 6$
43: $ 31 + 6 * ceil(sqrt{3})$
44: $floor( 1 * 3 * sqrt{6 ^ 3}) $
45: $ 13times3+6$
46: $ ceil(sqrt{6 ^ 3} + 31)$
47: $ floor(sqrt{sqrt{sqrt{sqrt{sqrt{31!}}}}})+36$
48: $6 * ( 3 * 3 - 1 )$
49: $13+36$
50: $ (6+1)^2 + 3 - 3$
51-60:
51: $( 3 * 6 - 1 ) * 3$
52: $( 3 + 3 + 1 ) * ceil(sqrt{6})$
53: $-1+( 3 * 3 * 6 )$
54: $ 1*3 * 3 * 6 $
55: $1+3*3*6$
56: $61-3!+floor(sqrt{3})$
57: $1*63-3!$
58: $1+63-3!$
59: $floor(sqrt{sqrt{sqrt{sqrt{sqrt{6^{(3-1)}}}}}}*3)$
60: $(1+3*3)*6$
61-70:
61: $63-3+1$
62: $63+1-ceil(sqrt{3})$
63: $63-floor(sqrt{3})+1$
64: $63+ceil(sqrt{3})-1$
65: $63+3-1$
66: $63+3*1$
67: $63+3+1$
68: $61+3!+floor(sqrt{3})$
69: $61+3!+ceil(sqrt{3})$
70: $61+3*3$
71-75
71: $(3+1)!*3-floor(sqrt{sqrt{6}})$
72: $(3+1)*3*6$
73: $(3+1)!*3+floor(sqrt{sqrt{6}})$
74: $(3+1)!*3+floor(sqrt{6})$
75: $(3+1)!*3+ceil(sqrt{6})$
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
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Who said you could use factorials?
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– Yout Ried
3 hours ago
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What are number 23 (plus you probably can't use factorials and 24? I don't get them.
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– Yout Ried
2 hours ago
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Oops forgot a ")" and maybe you're missing a factorial for number 24
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– Yout Ried
2 hours ago
add a comment |
$begingroup$
Alrighty, I'm piggybacking off of @OmegaKrypton else and adding some of my own.
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
! 21: $ 1 * 3^3 - 6 $
! 22: $ 13 + 3 + 6$
! 23: $ -13+36 $
! 24: $ (1+3)timessqrt{36}$
! 25: $ 3*6+3!-1$ or $ (6-1)^(3!/3)
>! 26: $ -1+33-6$
>! 27: $ 1*33-6 $
>! 28: $ 1+33-6$
>! 29: $ 36-3!-1$
>! 30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50
41: $ $
42: $ (1+3+3)times 6$
43: $ 3^3+16$
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ 16*(3!-3)$
49: $13+36$
50: $ 63-13$
I added a few. It's getting late here; will come back tomorrow.
answered 45 mins ago
Brandon_JBrandon_J
1,16326
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add a comment |
$begingroup$
Partial answer 1-50 (w/e 41,47):
$1= 1+3+3-6$
$2= 1 + (frac{6}{(3+3)})$
$3= 1^3+(frac{6}{3})$
$4= (frac{6}{3})+3-1$
$5= (frac{6}{3})+3^1$
$6= 6^1+3-3$
$7= 6+1-3+3$
$8= 6 + 3 - 1^3$
$9= 1^3 * (3+6)$
$10= 1^3 +3+6$
$11= 13 - (frac{6}{3})$
$12= 6+3+3^1$
$13= 6+3+3+1$
$14= 6*3 - 3 - 1$
$15= 6*3 - 3^1$
$16= 16 + 3 - 3$
$17= 16 + (frac{3}{3})$
$18= (frac{6*3}{1^3})$
$19= 6*3+1^3$
$20= 6*3+3-1$
$21= 6*3+3^1$
$22= 6*3+3+1$
$23= 36-13$
$24= 6*(3+1^3)$
$25= 16+(3*3)$
$26= 13*(frac{6}{3})$
$27= 33-6^1$
$28= 33-6+1$
$29= 31-(frac{6}{3})$
$30= 6*(3+3-1)$
$31= 13+3*6$
$32= 3^3+6-1$
$33= (frac{33}{1^6})$
$34= 33+1^6$
$35= (3+3)*6-1$
$36= (3+3)^1*6$
$37= 1+(3+3)*6$
$38= 33+6-1$
$39= 33+6^1$
$40= 1+33+6$
$41= $
$42= (1+3+3)*6$
$43= 16+3^3$
$44= round(sqrt{6^3}*3^1)$
$45= 3*3*(6-1)$
$46= ceil(sqrt{6^3}*3)+1$
$47= $
$48= ((3*3)-1)*6$
$49= 16+33$
$50= 63-13$
answered 43 mins ago
MukyuuMukyuu
340112
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add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
These get harder with larger numbers, but here are the first couple with the digits in order:
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
21: $ 1 * 3^3 - 6 $
22: $ 13 + 3 + 6$
23: $ -13+36 $
24: $ (1+3)timessqrt{36}$
25: $ 1 - 3 + sqrt3^6$
26: $ -1+33-6$
27: $ 1*33-6 $
28: $ 1+33-6$
29: $ -1 + 3 + sqrt3^6$
30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50 (getting much harder now, so I'll just press the submit button and let others continue)
41: $ $
42: $ (1+3+3)times 6$
43: $ $
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ $
49: $13+36$
50: $ $
answered 2 hours ago
BassBass
28.7k470176
$endgroup$
add a comment |
$begingroup$
These get harder with larger numbers, but here are the first couple with the digits in order:
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
21: $ 1 * 3^3 - 6 $
22: $ 13 + 3 + 6$
23: $ -13+36 $
24: $ (1+3)timessqrt{36}$
25: $ 1 - 3 + sqrt3^6$
26: $ -1+33-6$
27: $ 1*33-6 $
28: $ 1+33-6$
29: $ -1 + 3 + sqrt3^6$
30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50 (getting much harder now, so I'll just press the submit button and let others continue)
41: $ $
42: $ (1+3+3)times 6$
43: $ $
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ $
49: $13+36$
50: $ $
answered 2 hours ago
BassBass
28.7k470176
$endgroup$
add a comment |
$begingroup$
These get harder with larger numbers, but here are the first couple with the digits in order:
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
21: $ 1 * 3^3 - 6 $
22: $ 13 + 3 + 6$
23: $ -13+36 $
24: $ (1+3)timessqrt{36}$
25: $ 1 - 3 + sqrt3^6$
26: $ -1+33-6$
27: $ 1*33-6 $
28: $ 1+33-6$
29: $ -1 + 3 + sqrt3^6$
30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50 (getting much harder now, so I'll just press the submit button and let others continue)
41: $ $
42: $ (1+3+3)times 6$
43: $ $
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ $
49: $13+36$
50: $ $
answered 2 hours ago
BassBass
28.7k470176
$endgroup$
These get harder with larger numbers, but here are the first couple with the digits in order:
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
21: $ 1 * 3^3 - 6 $
22: $ 13 + 3 + 6$
23: $ -13+36 $
24: $ (1+3)timessqrt{36}$
25: $ 1 - 3 + sqrt3^6$
26: $ -1+33-6$
27: $ 1*33-6 $
28: $ 1+33-6$
29: $ -1 + 3 + sqrt3^6$
30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50 (getting much harder now, so I'll just press the submit button and let others continue)
41: $ $
42: $ (1+3+3)times 6$
43: $ $
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ $
49: $13+36$
50: $ $
answered 2 hours ago
BassBass
28.7k470176
edited 37 mins ago
answered 2 hours ago
BassBass
28.7k470176
answered 2 hours ago
BassBass
28.7k470176
answered 2 hours ago
BassBass
28.7k470176
28.7k470176
add a comment |
add a comment |
$begingroup$
Here are some:
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
22: (omega kyrpton did some) $3 * 6 + 3 + 1$
23: $3 ^ 3 - 6 * 1$
24: $3 ^ 3 - (6 - 1)$
I will do more later.
answered 5 hours ago
Yout RiedYout Ried
769119
$endgroup$
add a comment |
$begingroup$
Here are some:
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
22: (omega kyrpton did some) $3 * 6 + 3 + 1$
23: $3 ^ 3 - 6 * 1$
24: $3 ^ 3 - (6 - 1)$
I will do more later.
answered 5 hours ago
Yout RiedYout Ried
769119
$endgroup$
add a comment |
$begingroup$
Here are some:
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
22: (omega kyrpton did some) $3 * 6 + 3 + 1$
23: $3 ^ 3 - 6 * 1$
24: $3 ^ 3 - (6 - 1)$
I will do more later.
answered 5 hours ago
Yout RiedYout Ried
769119
$endgroup$
Here are some:
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
22: (omega kyrpton did some) $3 * 6 + 3 + 1$
23: $3 ^ 3 - 6 * 1$
24: $3 ^ 3 - (6 - 1)$
I will do more later.
answered 5 hours ago
Yout RiedYout Ried
769119
edited 2 hours ago
answered 5 hours ago
Yout RiedYout Ried
769119
answered 5 hours ago
Yout RiedYout Ried
769119
answered 5 hours ago
Yout RiedYout Ried
769119
769119
add a comment |
add a comment |
$begingroup$
Adding some more...
1-20: (Credits to @YoutRied)
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
21-29
21: $3 * 6 + 3 * 1$
22: $( 1 + 3 ) ! - ( 6 / 3 )$
23: $( 1 + 3 ) ! - ( 6 - 3 )$
24: $( 6 - 3 / 3 - 1 ) !$
25: $1 * 3 ^ 3 - floor(sqrt{6})$
26: $( 6 - 3 ) ^ 3 - 1$
27: $( 6 - 3 ) ^ 3 * 1$
28: $( 6 - 3 ) ^ 3 + 1$
29: $31 - 6 / 3$
41-50: (Credits to @Bass for 42, 45, 49)
41: $ (-1+3!)+36 $
42: $ (1+3+3)times 6$
43: $ 31 + 6 * ceil(sqrt{3})$
44: $floor( 1 * 3 * sqrt{6 ^ 3}) $
45: $ 13times3+6$
46: $ ceil(sqrt{6 ^ 3} + 31)$
47: $ floor(sqrt{sqrt{sqrt{sqrt{sqrt{31!}}}}})+36$
48: $6 * ( 3 * 3 - 1 )$
49: $13+36$
50: $ (6+1)^2 + 3 - 3$
51-60:
51: $( 3 * 6 - 1 ) * 3$
52: $( 3 + 3 + 1 ) * ceil(sqrt{6})$
53: $-1+( 3 * 3 * 6 )$
54: $ 1*3 * 3 * 6 $
55: $1+3*3*6$
56: $61-3!+floor(sqrt{3})$
57: $1*63-3!$
58: $1+63-3!$
59: $floor(sqrt{sqrt{sqrt{sqrt{sqrt{6^{(3-1)}}}}}}*3)$
60: $(1+3*3)*6$
61-70:
61: $63-3+1$
62: $63+1-ceil(sqrt{3})$
63: $63-floor(sqrt{3})+1$
64: $63+ceil(sqrt{3})-1$
65: $63+3-1$
66: $63+3*1$
67: $63+3+1$
68: $61+3!+floor(sqrt{3})$
69: $61+3!+ceil(sqrt{3})$
70: $61+3*3$
71-75
71: $(3+1)!*3-floor(sqrt{sqrt{6}})$
72: $(3+1)*3*6$
73: $(3+1)!*3+floor(sqrt{sqrt{6}})$
74: $(3+1)!*3+floor(sqrt{6})$
75: $(3+1)!*3+ceil(sqrt{6})$
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
$endgroup$
$begingroup$
Who said you could use factorials?
$endgroup$
– Yout Ried
3 hours ago
$begingroup$
What are number 23 (plus you probably can't use factorials and 24? I don't get them.
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
Oops forgot a ")" and maybe you're missing a factorial for number 24
$endgroup$
– Yout Ried
2 hours ago
add a comment |
$begingroup$
Adding some more...
1-20: (Credits to @YoutRied)
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
21-29
21: $3 * 6 + 3 * 1$
22: $( 1 + 3 ) ! - ( 6 / 3 )$
23: $( 1 + 3 ) ! - ( 6 - 3 )$
24: $( 6 - 3 / 3 - 1 ) !$
25: $1 * 3 ^ 3 - floor(sqrt{6})$
26: $( 6 - 3 ) ^ 3 - 1$
27: $( 6 - 3 ) ^ 3 * 1$
28: $( 6 - 3 ) ^ 3 + 1$
29: $31 - 6 / 3$
41-50: (Credits to @Bass for 42, 45, 49)
41: $ (-1+3!)+36 $
42: $ (1+3+3)times 6$
43: $ 31 + 6 * ceil(sqrt{3})$
44: $floor( 1 * 3 * sqrt{6 ^ 3}) $
45: $ 13times3+6$
46: $ ceil(sqrt{6 ^ 3} + 31)$
47: $ floor(sqrt{sqrt{sqrt{sqrt{sqrt{31!}}}}})+36$
48: $6 * ( 3 * 3 - 1 )$
49: $13+36$
50: $ (6+1)^2 + 3 - 3$
51-60:
51: $( 3 * 6 - 1 ) * 3$
52: $( 3 + 3 + 1 ) * ceil(sqrt{6})$
53: $-1+( 3 * 3 * 6 )$
54: $ 1*3 * 3 * 6 $
55: $1+3*3*6$
56: $61-3!+floor(sqrt{3})$
57: $1*63-3!$
58: $1+63-3!$
59: $floor(sqrt{sqrt{sqrt{sqrt{sqrt{6^{(3-1)}}}}}}*3)$
60: $(1+3*3)*6$
61-70:
61: $63-3+1$
62: $63+1-ceil(sqrt{3})$
63: $63-floor(sqrt{3})+1$
64: $63+ceil(sqrt{3})-1$
65: $63+3-1$
66: $63+3*1$
67: $63+3+1$
68: $61+3!+floor(sqrt{3})$
69: $61+3!+ceil(sqrt{3})$
70: $61+3*3$
71-75
71: $(3+1)!*3-floor(sqrt{sqrt{6}})$
72: $(3+1)*3*6$
73: $(3+1)!*3+floor(sqrt{sqrt{6}})$
74: $(3+1)!*3+floor(sqrt{6})$
75: $(3+1)!*3+ceil(sqrt{6})$
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
$endgroup$
$begingroup$
Who said you could use factorials?
$endgroup$
– Yout Ried
3 hours ago
$begingroup$
What are number 23 (plus you probably can't use factorials and 24? I don't get them.
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
Oops forgot a ")" and maybe you're missing a factorial for number 24
$endgroup$
– Yout Ried
2 hours ago
add a comment |
$begingroup$
Adding some more...
1-20: (Credits to @YoutRied)
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
21-29
21: $3 * 6 + 3 * 1$
22: $( 1 + 3 ) ! - ( 6 / 3 )$
23: $( 1 + 3 ) ! - ( 6 - 3 )$
24: $( 6 - 3 / 3 - 1 ) !$
25: $1 * 3 ^ 3 - floor(sqrt{6})$
26: $( 6 - 3 ) ^ 3 - 1$
27: $( 6 - 3 ) ^ 3 * 1$
28: $( 6 - 3 ) ^ 3 + 1$
29: $31 - 6 / 3$
41-50: (Credits to @Bass for 42, 45, 49)
41: $ (-1+3!)+36 $
42: $ (1+3+3)times 6$
43: $ 31 + 6 * ceil(sqrt{3})$
44: $floor( 1 * 3 * sqrt{6 ^ 3}) $
45: $ 13times3+6$
46: $ ceil(sqrt{6 ^ 3} + 31)$
47: $ floor(sqrt{sqrt{sqrt{sqrt{sqrt{31!}}}}})+36$
48: $6 * ( 3 * 3 - 1 )$
49: $13+36$
50: $ (6+1)^2 + 3 - 3$
51-60:
51: $( 3 * 6 - 1 ) * 3$
52: $( 3 + 3 + 1 ) * ceil(sqrt{6})$
53: $-1+( 3 * 3 * 6 )$
54: $ 1*3 * 3 * 6 $
55: $1+3*3*6$
56: $61-3!+floor(sqrt{3})$
57: $1*63-3!$
58: $1+63-3!$
59: $floor(sqrt{sqrt{sqrt{sqrt{sqrt{6^{(3-1)}}}}}}*3)$
60: $(1+3*3)*6$
61-70:
61: $63-3+1$
62: $63+1-ceil(sqrt{3})$
63: $63-floor(sqrt{3})+1$
64: $63+ceil(sqrt{3})-1$
65: $63+3-1$
66: $63+3*1$
67: $63+3+1$
68: $61+3!+floor(sqrt{3})$
69: $61+3!+ceil(sqrt{3})$
70: $61+3*3$
71-75
71: $(3+1)!*3-floor(sqrt{sqrt{6}})$
72: $(3+1)*3*6$
73: $(3+1)!*3+floor(sqrt{sqrt{6}})$
74: $(3+1)!*3+floor(sqrt{6})$
75: $(3+1)!*3+ceil(sqrt{6})$
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
$endgroup$
Adding some more...
1-20: (Credits to @YoutRied)
1: $3 + 3 - 6 + 1$
2: $3 * 3 - (6 + 1)$
3: $3 * 3 * 1 - 6$
4: $3 * 3 - 6 + 1$
5: $(3 * 6) / 3 - 1$
6: $(3 * 6) / 3 * 1$
7: $(3 * 6) / 3 + 1$
8: $3 * 3 - 1 ^ 6$
9: $(3 * 6) / (3 - 1)$
10: $3 * 3 + 1 ^ 6$
11: $36 / 3 - 1$
12: $36 / 3 * 1$
13: $36 / 3 + 1$
14: $3 * 6 - (3 + 1)$
15: $3 * 6 - (3 * 1)$
16: $3 * 6 - (3 - 1)$
17: $3 * 6 - 1 ^ 3$
18: $3 * 6 * 1 ^ 3$
19: $3 * 6 + 1 ^ 3$
20: $3 * 6 + 3 - 1$
21-29
21: $3 * 6 + 3 * 1$
22: $( 1 + 3 ) ! - ( 6 / 3 )$
23: $( 1 + 3 ) ! - ( 6 - 3 )$
24: $( 6 - 3 / 3 - 1 ) !$
25: $1 * 3 ^ 3 - floor(sqrt{6})$
26: $( 6 - 3 ) ^ 3 - 1$
27: $( 6 - 3 ) ^ 3 * 1$
28: $( 6 - 3 ) ^ 3 + 1$
29: $31 - 6 / 3$
41-50: (Credits to @Bass for 42, 45, 49)
41: $ (-1+3!)+36 $
42: $ (1+3+3)times 6$
43: $ 31 + 6 * ceil(sqrt{3})$
44: $floor( 1 * 3 * sqrt{6 ^ 3}) $
45: $ 13times3+6$
46: $ ceil(sqrt{6 ^ 3} + 31)$
47: $ floor(sqrt{sqrt{sqrt{sqrt{sqrt{31!}}}}})+36$
48: $6 * ( 3 * 3 - 1 )$
49: $13+36$
50: $ (6+1)^2 + 3 - 3$
51-60:
51: $( 3 * 6 - 1 ) * 3$
52: $( 3 + 3 + 1 ) * ceil(sqrt{6})$
53: $-1+( 3 * 3 * 6 )$
54: $ 1*3 * 3 * 6 $
55: $1+3*3*6$
56: $61-3!+floor(sqrt{3})$
57: $1*63-3!$
58: $1+63-3!$
59: $floor(sqrt{sqrt{sqrt{sqrt{sqrt{6^{(3-1)}}}}}}*3)$
60: $(1+3*3)*6$
61-70:
61: $63-3+1$
62: $63+1-ceil(sqrt{3})$
63: $63-floor(sqrt{3})+1$
64: $63+ceil(sqrt{3})-1$
65: $63+3-1$
66: $63+3*1$
67: $63+3+1$
68: $61+3!+floor(sqrt{3})$
69: $61+3!+ceil(sqrt{3})$
70: $61+3*3$
71-75
71: $(3+1)!*3-floor(sqrt{sqrt{6}})$
72: $(3+1)*3*6$
73: $(3+1)!*3+floor(sqrt{sqrt{6}})$
74: $(3+1)!*3+floor(sqrt{6})$
75: $(3+1)!*3+ceil(sqrt{6})$
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
edited 14 mins ago
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
answered 4 hours ago
Omega KryptonOmega Krypton
2,9851232
2,9851232
$begingroup$
Who said you could use factorials?
$endgroup$
– Yout Ried
3 hours ago
$begingroup$
What are number 23 (plus you probably can't use factorials and 24? I don't get them.
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
Oops forgot a ")" and maybe you're missing a factorial for number 24
$endgroup$
– Yout Ried
2 hours ago
add a comment |
$begingroup$
Who said you could use factorials?
$endgroup$
– Yout Ried
3 hours ago
$begingroup$
What are number 23 (plus you probably can't use factorials and 24? I don't get them.
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
Oops forgot a ")" and maybe you're missing a factorial for number 24
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
Who said you could use factorials?
$endgroup$
– Yout Ried
3 hours ago
$begingroup$
Who said you could use factorials?
$endgroup$
– Yout Ried
3 hours ago
$begingroup$
What are number 23 (plus you probably can't use factorials and 24? I don't get them.
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
What are number 23 (plus you probably can't use factorials and 24? I don't get them.
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
Oops forgot a ")" and maybe you're missing a factorial for number 24
$endgroup$
– Yout Ried
2 hours ago
$begingroup$
Oops forgot a ")" and maybe you're missing a factorial for number 24
$endgroup$
– Yout Ried
2 hours ago
add a comment |
$begingroup$
Alrighty, I'm piggybacking off of @OmegaKrypton else and adding some of my own.
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
! 21: $ 1 * 3^3 - 6 $
! 22: $ 13 + 3 + 6$
! 23: $ -13+36 $
! 24: $ (1+3)timessqrt{36}$
! 25: $ 3*6+3!-1$ or $ (6-1)^(3!/3)
>! 26: $ -1+33-6$
>! 27: $ 1*33-6 $
>! 28: $ 1+33-6$
>! 29: $ 36-3!-1$
>! 30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50
41: $ $
42: $ (1+3+3)times 6$
43: $ 3^3+16$
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ 16*(3!-3)$
49: $13+36$
50: $ 63-13$
I added a few. It's getting late here; will come back tomorrow.
answered 45 mins ago
Brandon_JBrandon_J
1,16326
$endgroup$
add a comment |
$begingroup$
Alrighty, I'm piggybacking off of @OmegaKrypton else and adding some of my own.
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
! 21: $ 1 * 3^3 - 6 $
! 22: $ 13 + 3 + 6$
! 23: $ -13+36 $
! 24: $ (1+3)timessqrt{36}$
! 25: $ 3*6+3!-1$ or $ (6-1)^(3!/3)
>! 26: $ -1+33-6$
>! 27: $ 1*33-6 $
>! 28: $ 1+33-6$
>! 29: $ 36-3!-1$
>! 30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50
41: $ $
42: $ (1+3+3)times 6$
43: $ 3^3+16$
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ 16*(3!-3)$
49: $13+36$
50: $ 63-13$
I added a few. It's getting late here; will come back tomorrow.
answered 45 mins ago
Brandon_JBrandon_J
1,16326
$endgroup$
add a comment |
$begingroup$
Alrighty, I'm piggybacking off of @OmegaKrypton else and adding some of my own.
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
! 21: $ 1 * 3^3 - 6 $
! 22: $ 13 + 3 + 6$
! 23: $ -13+36 $
! 24: $ (1+3)timessqrt{36}$
! 25: $ 3*6+3!-1$ or $ (6-1)^(3!/3)
>! 26: $ -1+33-6$
>! 27: $ 1*33-6 $
>! 28: $ 1+33-6$
>! 29: $ 36-3!-1$
>! 30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50
41: $ $
42: $ (1+3+3)times 6$
43: $ 3^3+16$
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ 16*(3!-3)$
49: $13+36$
50: $ 63-13$
I added a few. It's getting late here; will come back tomorrow.
answered 45 mins ago
Brandon_JBrandon_J
1,16326
$endgroup$
Alrighty, I'm piggybacking off of @OmegaKrypton else and adding some of my own.
1 to 10
1: $1 + 3 + 3 - 6$
2: $(1 + 3) times 3 / 6$
3: $1^3 +3/6$
4: $13 - 3 - 6$
5: $-1^{33} +6$
6: $1times3-3+6$
7: $ 1 + 3 -3 +6$
8: $ 1+3/3 + 6$
9: $ 1^3 times (3+6)$
10: $ 1^3 + 3+6$
11 to 20
11: $ sqrt{1+3}+3+6$
12: $1times 3 + 3 + 6$
13: $1 + 3+3+6$
14: $-1 + 3times 3+6$
15: $-1times3 + 3times 6$
16: $1 - 3 + 3 times 6$
17: $ -1^3 +3times 6$
18: $ (1+3)*3+6 $
19: $13 + sqrt{36}$
20: $-1 + 3^3 - 6$
21 to 30
! 21: $ 1 * 3^3 - 6 $
! 22: $ 13 + 3 + 6$
! 23: $ -13+36 $
! 24: $ (1+3)timessqrt{36}$
! 25: $ 3*6+3!-1$ or $ (6-1)^(3!/3)
>! 26: $ -1+33-6$
>! 27: $ 1*33-6 $
>! 28: $ 1+33-6$
>! 29: $ 36-3!-1$
>! 30: $ (-1+3+3)times 6$
31 to 40
31: $ 13+3*6 $
32: $ -1+3^3+6$
33: $ 13*3-6 $
34: $ 1+3^3+6$
35: $ -1+(3+3)times6 $
36: $ 1times(3+3)times 6$
37: $ 1^3+36$
38: $ sqrt{1+3}+36$
39: $ 1times3 + 36$
40: $ 1+33+6$
41 to 50
41: $ $
42: $ (1+3+3)times 6$
43: $ 3^3+16$
44: $ $
45: $ 13times3+6$
46: $ $
47: $ $
48: $ 16*(3!-3)$
49: $13+36$
50: $ 63-13$
I added a few. It's getting late here; will come back tomorrow.
answered 45 mins ago
Brandon_JBrandon_J
1,16326
answered 45 mins ago
Brandon_JBrandon_J
1,16326
answered 45 mins ago
Brandon_JBrandon_J
1,16326
answered 45 mins ago
Brandon_JBrandon_J
1,16326
1,16326
add a comment |
add a comment |
$begingroup$
Partial answer 1-50 (w/e 41,47):
$1= 1+3+3-6$
$2= 1 + (frac{6}{(3+3)})$
$3= 1^3+(frac{6}{3})$
$4= (frac{6}{3})+3-1$
$5= (frac{6}{3})+3^1$
$6= 6^1+3-3$
$7= 6+1-3+3$
$8= 6 + 3 - 1^3$
$9= 1^3 * (3+6)$
$10= 1^3 +3+6$
$11= 13 - (frac{6}{3})$
$12= 6+3+3^1$
$13= 6+3+3+1$
$14= 6*3 - 3 - 1$
$15= 6*3 - 3^1$
$16= 16 + 3 - 3$
$17= 16 + (frac{3}{3})$
$18= (frac{6*3}{1^3})$
$19= 6*3+1^3$
$20= 6*3+3-1$
$21= 6*3+3^1$
$22= 6*3+3+1$
$23= 36-13$
$24= 6*(3+1^3)$
$25= 16+(3*3)$
$26= 13*(frac{6}{3})$
$27= 33-6^1$
$28= 33-6+1$
$29= 31-(frac{6}{3})$
$30= 6*(3+3-1)$
$31= 13+3*6$
$32= 3^3+6-1$
$33= (frac{33}{1^6})$
$34= 33+1^6$
$35= (3+3)*6-1$
$36= (3+3)^1*6$
$37= 1+(3+3)*6$
$38= 33+6-1$
$39= 33+6^1$
$40= 1+33+6$
$41= $
$42= (1+3+3)*6$
$43= 16+3^3$
$44= round(sqrt{6^3}*3^1)$
$45= 3*3*(6-1)$
$46= ceil(sqrt{6^3}*3)+1$
$47= $
$48= ((3*3)-1)*6$
$49= 16+33$
$50= 63-13$
answered 43 mins ago
MukyuuMukyuu
340112
$endgroup$
add a comment |
$begingroup$
Partial answer 1-50 (w/e 41,47):
$1= 1+3+3-6$
$2= 1 + (frac{6}{(3+3)})$
$3= 1^3+(frac{6}{3})$
$4= (frac{6}{3})+3-1$
$5= (frac{6}{3})+3^1$
$6= 6^1+3-3$
$7= 6+1-3+3$
$8= 6 + 3 - 1^3$
$9= 1^3 * (3+6)$
$10= 1^3 +3+6$
$11= 13 - (frac{6}{3})$
$12= 6+3+3^1$
$13= 6+3+3+1$
$14= 6*3 - 3 - 1$
$15= 6*3 - 3^1$
$16= 16 + 3 - 3$
$17= 16 + (frac{3}{3})$
$18= (frac{6*3}{1^3})$
$19= 6*3+1^3$
$20= 6*3+3-1$
$21= 6*3+3^1$
$22= 6*3+3+1$
$23= 36-13$
$24= 6*(3+1^3)$
$25= 16+(3*3)$
$26= 13*(frac{6}{3})$
$27= 33-6^1$
$28= 33-6+1$
$29= 31-(frac{6}{3})$
$30= 6*(3+3-1)$
$31= 13+3*6$
$32= 3^3+6-1$
$33= (frac{33}{1^6})$
$34= 33+1^6$
$35= (3+3)*6-1$
$36= (3+3)^1*6$
$37= 1+(3+3)*6$
$38= 33+6-1$
$39= 33+6^1$
$40= 1+33+6$
$41= $
$42= (1+3+3)*6$
$43= 16+3^3$
$44= round(sqrt{6^3}*3^1)$
$45= 3*3*(6-1)$
$46= ceil(sqrt{6^3}*3)+1$
$47= $
$48= ((3*3)-1)*6$
$49= 16+33$
$50= 63-13$
answered 43 mins ago
MukyuuMukyuu
340112
$endgroup$
add a comment |
$begingroup$
Partial answer 1-50 (w/e 41,47):
$1= 1+3+3-6$
$2= 1 + (frac{6}{(3+3)})$
$3= 1^3+(frac{6}{3})$
$4= (frac{6}{3})+3-1$
$5= (frac{6}{3})+3^1$
$6= 6^1+3-3$
$7= 6+1-3+3$
$8= 6 + 3 - 1^3$
$9= 1^3 * (3+6)$
$10= 1^3 +3+6$
$11= 13 - (frac{6}{3})$
$12= 6+3+3^1$
$13= 6+3+3+1$
$14= 6*3 - 3 - 1$
$15= 6*3 - 3^1$
$16= 16 + 3 - 3$
$17= 16 + (frac{3}{3})$
$18= (frac{6*3}{1^3})$
$19= 6*3+1^3$
$20= 6*3+3-1$
$21= 6*3+3^1$
$22= 6*3+3+1$
$23= 36-13$
$24= 6*(3+1^3)$
$25= 16+(3*3)$
$26= 13*(frac{6}{3})$
$27= 33-6^1$
$28= 33-6+1$
$29= 31-(frac{6}{3})$
$30= 6*(3+3-1)$
$31= 13+3*6$
$32= 3^3+6-1$
$33= (frac{33}{1^6})$
$34= 33+1^6$
$35= (3+3)*6-1$
$36= (3+3)^1*6$
$37= 1+(3+3)*6$
$38= 33+6-1$
$39= 33+6^1$
$40= 1+33+6$
$41= $
$42= (1+3+3)*6$
$43= 16+3^3$
$44= round(sqrt{6^3}*3^1)$
$45= 3*3*(6-1)$
$46= ceil(sqrt{6^3}*3)+1$
$47= $
$48= ((3*3)-1)*6$
$49= 16+33$
$50= 63-13$
answered 43 mins ago
MukyuuMukyuu
340112
$endgroup$
Partial answer 1-50 (w/e 41,47):
$1= 1+3+3-6$
$2= 1 + (frac{6}{(3+3)})$
$3= 1^3+(frac{6}{3})$
$4= (frac{6}{3})+3-1$
$5= (frac{6}{3})+3^1$
$6= 6^1+3-3$
$7= 6+1-3+3$
$8= 6 + 3 - 1^3$
$9= 1^3 * (3+6)$
$10= 1^3 +3+6$
$11= 13 - (frac{6}{3})$
$12= 6+3+3^1$
$13= 6+3+3+1$
$14= 6*3 - 3 - 1$
$15= 6*3 - 3^1$
$16= 16 + 3 - 3$
$17= 16 + (frac{3}{3})$
$18= (frac{6*3}{1^3})$
$19= 6*3+1^3$
$20= 6*3+3-1$
$21= 6*3+3^1$
$22= 6*3+3+1$
$23= 36-13$
$24= 6*(3+1^3)$
$25= 16+(3*3)$
$26= 13*(frac{6}{3})$
$27= 33-6^1$
$28= 33-6+1$
$29= 31-(frac{6}{3})$
$30= 6*(3+3-1)$
$31= 13+3*6$
$32= 3^3+6-1$
$33= (frac{33}{1^6})$
$34= 33+1^6$
$35= (3+3)*6-1$
$36= (3+3)^1*6$
$37= 1+(3+3)*6$
$38= 33+6-1$
$39= 33+6^1$
$40= 1+33+6$
$41= $
$42= (1+3+3)*6$
$43= 16+3^3$
$44= round(sqrt{6^3}*3^1)$
$45= 3*3*(6-1)$
$46= ceil(sqrt{6^3}*3)+1$
$47= $
$48= ((3*3)-1)*6$
$49= 16+33$
$50= 63-13$
answered 43 mins ago
MukyuuMukyuu
340112
edited 5 mins ago
answered 43 mins ago
MukyuuMukyuu
340112
answered 43 mins ago
MukyuuMukyuu
340112
answered 43 mins ago
MukyuuMukyuu
340112
340112
add a comment |
add a comment |
Michał Uraszewski is a new contributor. Be nice, and check out our Code of Conduct.
Michał Uraszewski is a new contributor. Be nice, and check out our Code of Conduct.
Michał Uraszewski is a new contributor. Be nice, and check out our Code of Conduct.
Michał Uraszewski is a new contributor. Be nice, and check out our Code of Conduct.
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2
$begingroup$
Can we combine the results of operations? For example, is $(1+3) | 36 = 436$ (where | indicates concatenation)
$endgroup$
– Hugh
5 hours ago
1
$begingroup$
If we need to take a square root, is the two implied?
$endgroup$
– Hugh
5 hours ago
1
$begingroup$
can we use factorial?
$endgroup$
– Omega Krypton
4 hours ago
2
$begingroup$
Factorials are most likely out, but what about parentheses, unary minus (like starting with -1) and decimal points?
$endgroup$
– Bass
3 hours ago
$begingroup$
If decimal is allowed then round would probably valid too?
$endgroup$
– Mukyuu
13 mins ago