Alternatives of lists vs Alternatives of strings
Obviously I am missing something obvious.
I have:
lis = {"a"}|{"b"}|{"c"}
but I want:
lis2 = "a"|"b"|"c"
Thanks as always for suggestions...
list-manipulation
asked Nov 24 at 20:03
Suite401
981312
add a comment |
Obviously I am missing something obvious.
I have:
lis = {"a"}|{"b"}|{"c"}
but I want:
lis2 = "a"|"b"|"c"
Thanks as always for suggestions...
list-manipulation
asked Nov 24 at 20:03
Suite401
981312
add a comment |
Obviously I am missing something obvious.
I have:
lis = {"a"}|{"b"}|{"c"}
but I want:
lis2 = "a"|"b"|"c"
Thanks as always for suggestions...
list-manipulation
asked Nov 24 at 20:03
Suite401
981312
Obviously I am missing something obvious.
I have:
lis = {"a"}|{"b"}|{"c"}
but I want:
lis2 = "a"|"b"|"c"
Thanks as always for suggestions...
list-manipulation
list-manipulation
asked Nov 24 at 20:03
Suite401
981312
asked Nov 24 at 20:03
Suite401
981312
asked Nov 24 at 20:03
Suite401
981312
asked Nov 24 at 20:03
Suite401
981312
asked Nov 24 at 20:03
Suite401
981312
981312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Use lis[[All, 1]] or First /@ list. See Part and First.
answered Nov 24 at 20:06
Szabolcs
158k13432926
add a comment |
You can also Apply (@@@) Sequence at level 1:
Sequence @@@ lis
"a" | "b" | "c"
Also
## & @@@ lis
"a" | "b" | "c"
Alternatively, use ReplaceAll to replace List with Sequence:
lis /. List -> Sequence
"a" | "b" | "c"
Additional methods:
MapAt[Sequence &, lis, {All, 0}]
ReplacePart[lis, {_, 0} :> Sequence]
lis[[All, 0]] = Sequence; lis
all give "a" | "b" | "c".
answered Nov 24 at 20:22
kglr
176k9197402
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use lis[[All, 1]] or First /@ list. See Part and First.
answered Nov 24 at 20:06
Szabolcs
158k13432926
add a comment |
Use lis[[All, 1]] or First /@ list. See Part and First.
answered Nov 24 at 20:06
Szabolcs
158k13432926
add a comment |
Use lis[[All, 1]] or First /@ list. See Part and First.
answered Nov 24 at 20:06
Szabolcs
158k13432926
Use lis[[All, 1]] or First /@ list. See Part and First.
answered Nov 24 at 20:06
Szabolcs
158k13432926
answered Nov 24 at 20:06
Szabolcs
158k13432926
answered Nov 24 at 20:06
Szabolcs
158k13432926
answered Nov 24 at 20:06
Szabolcs
158k13432926
158k13432926
add a comment |
add a comment |
You can also Apply (@@@) Sequence at level 1:
Sequence @@@ lis
"a" | "b" | "c"
Also
## & @@@ lis
"a" | "b" | "c"
Alternatively, use ReplaceAll to replace List with Sequence:
lis /. List -> Sequence
"a" | "b" | "c"
Additional methods:
MapAt[Sequence &, lis, {All, 0}]
ReplacePart[lis, {_, 0} :> Sequence]
lis[[All, 0]] = Sequence; lis
all give "a" | "b" | "c".
answered Nov 24 at 20:22
kglr
176k9197402
add a comment |
You can also Apply (@@@) Sequence at level 1:
Sequence @@@ lis
"a" | "b" | "c"
Also
## & @@@ lis
"a" | "b" | "c"
Alternatively, use ReplaceAll to replace List with Sequence:
lis /. List -> Sequence
"a" | "b" | "c"
Additional methods:
MapAt[Sequence &, lis, {All, 0}]
ReplacePart[lis, {_, 0} :> Sequence]
lis[[All, 0]] = Sequence; lis
all give "a" | "b" | "c".
answered Nov 24 at 20:22
kglr
176k9197402
add a comment |
You can also Apply (@@@) Sequence at level 1:
Sequence @@@ lis
"a" | "b" | "c"
Also
## & @@@ lis
"a" | "b" | "c"
Alternatively, use ReplaceAll to replace List with Sequence:
lis /. List -> Sequence
"a" | "b" | "c"
Additional methods:
MapAt[Sequence &, lis, {All, 0}]
ReplacePart[lis, {_, 0} :> Sequence]
lis[[All, 0]] = Sequence; lis
all give "a" | "b" | "c".
answered Nov 24 at 20:22
kglr
176k9197402
You can also Apply (@@@) Sequence at level 1:
Sequence @@@ lis
"a" | "b" | "c"
Also
## & @@@ lis
"a" | "b" | "c"
Alternatively, use ReplaceAll to replace List with Sequence:
lis /. List -> Sequence
"a" | "b" | "c"
Additional methods:
MapAt[Sequence &, lis, {All, 0}]
ReplacePart[lis, {_, 0} :> Sequence]
lis[[All, 0]] = Sequence; lis
all give "a" | "b" | "c".
answered Nov 24 at 20:22
kglr
176k9197402
edited Nov 25 at 8:20
answered Nov 24 at 20:22
kglr
176k9197402
answered Nov 24 at 20:22
kglr
176k9197402
answered Nov 24 at 20:22
kglr
176k9197402
176k9197402
add a comment |
add a comment |
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