How do describe the composition of an indicator function?












0














I have an indicator function:



enter image description here



I have to describe the composition in this form:



enter image description here



I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?










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    0














    I have an indicator function:



    enter image description here



    I have to describe the composition in this form:



    enter image description here



    I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?










    share|cite|improve this question



























      0












      0








      0







      I have an indicator function:



      enter image description here



      I have to describe the composition in this form:



      enter image description here



      I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?










      share|cite|improve this question















      I have an indicator function:



      enter image description here



      I have to describe the composition in this form:



      enter image description here



      I replaced the 'n' value with the function but I cannot simplify it, how can one describe and simplify the composition of an indicator function?







      linear-algebra function-and-relation-composition






      share|cite|improve this question















      share|cite|improve this question













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      share|cite|improve this question








      edited Nov 27 '18 at 21:58

























      asked Nov 27 '18 at 21:27









      user604574

      166




      166






















          1 Answer
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          Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.






          share|cite|improve this answer





















          • Thanks for your answer, is this the usual method? How did you choose those 'n' values?
            – user604574
            Nov 27 '18 at 22:27












          • It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
            – Berci
            Nov 27 '18 at 22:30











          Your Answer





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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

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          1














          Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.






          share|cite|improve this answer





















          • Thanks for your answer, is this the usual method? How did you choose those 'n' values?
            – user604574
            Nov 27 '18 at 22:27












          • It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
            – Berci
            Nov 27 '18 at 22:30
















          1














          Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.






          share|cite|improve this answer





















          • Thanks for your answer, is this the usual method? How did you choose those 'n' values?
            – user604574
            Nov 27 '18 at 22:27












          • It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
            – Berci
            Nov 27 '18 at 22:30














          1












          1








          1






          Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.






          share|cite|improve this answer












          Hint: Calculate $f(f(n))$ for $0le nle4$, for $n=5, 6$, and for $n>6$.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 27 '18 at 22:16









          Berci

          59.6k23672




          59.6k23672












          • Thanks for your answer, is this the usual method? How did you choose those 'n' values?
            – user604574
            Nov 27 '18 at 22:27












          • It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
            – Berci
            Nov 27 '18 at 22:30


















          • Thanks for your answer, is this the usual method? How did you choose those 'n' values?
            – user604574
            Nov 27 '18 at 22:27












          • It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
            – Berci
            Nov 27 '18 at 22:30
















          Thanks for your answer, is this the usual method? How did you choose those 'n' values?
          – user604574
          Nov 27 '18 at 22:27






          Thanks for your answer, is this the usual method? How did you choose those 'n' values?
          – user604574
          Nov 27 '18 at 22:27














          It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
          – Berci
          Nov 27 '18 at 22:30




          It's specific to this exercise. If you make the calculations, you might have a guess why those values of $n$ are differentiated.
          – Berci
          Nov 27 '18 at 22:30


















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