Approximation around steady state:












0














All equations here are direct copies from a textbook.



In steady state, we have $$i = rho + pi + sigma y.$$



The goal is then to do a first-order Taylor approximation around this steady state of the function $$f(i_t) = expleft( i_t - sigma Delta c_{t+1} - pi_{t+1} + Delta x_{t+1}right)$$



Doing this, my textbook gets the approximation $$f(i_t) approx 1 + (i_t - i) - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1}.$$



But how does it do this?
Note that evaluation at the steady state gives $$f(i) = exp( - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1})$$ which is the first term in the Taylor approximation, yet this term doesn't appear anywhere?










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    0














    All equations here are direct copies from a textbook.



    In steady state, we have $$i = rho + pi + sigma y.$$



    The goal is then to do a first-order Taylor approximation around this steady state of the function $$f(i_t) = expleft( i_t - sigma Delta c_{t+1} - pi_{t+1} + Delta x_{t+1}right)$$



    Doing this, my textbook gets the approximation $$f(i_t) approx 1 + (i_t - i) - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1}.$$



    But how does it do this?
    Note that evaluation at the steady state gives $$f(i) = exp( - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1})$$ which is the first term in the Taylor approximation, yet this term doesn't appear anywhere?










    share|cite|improve this question

























      0












      0








      0







      All equations here are direct copies from a textbook.



      In steady state, we have $$i = rho + pi + sigma y.$$



      The goal is then to do a first-order Taylor approximation around this steady state of the function $$f(i_t) = expleft( i_t - sigma Delta c_{t+1} - pi_{t+1} + Delta x_{t+1}right)$$



      Doing this, my textbook gets the approximation $$f(i_t) approx 1 + (i_t - i) - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1}.$$



      But how does it do this?
      Note that evaluation at the steady state gives $$f(i) = exp( - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1})$$ which is the first term in the Taylor approximation, yet this term doesn't appear anywhere?










      share|cite|improve this question













      All equations here are direct copies from a textbook.



      In steady state, we have $$i = rho + pi + sigma y.$$



      The goal is then to do a first-order Taylor approximation around this steady state of the function $$f(i_t) = expleft( i_t - sigma Delta c_{t+1} - pi_{t+1} + Delta x_{t+1}right)$$



      Doing this, my textbook gets the approximation $$f(i_t) approx 1 + (i_t - i) - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1}.$$



      But how does it do this?
      Note that evaluation at the steady state gives $$f(i) = exp( - sigma(Delta c_{t+1} - y) - (pi_{t+1} - pi_t) + Delta x_{t+1})$$ which is the first term in the Taylor approximation, yet this term doesn't appear anywhere?







      taylor-expansion






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      asked Nov 27 '18 at 21:17









      SAK

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