How much there exists operators of $ain End(mathbb{F}_p^3)$
How much there exists operators of $ain End(mathbb{F}_p^3)$ such that a((2, -1, 3)) = (1, 1, -1), a((1, 2, 3)) = (1, 0, 1), a((3, 1, -1)) = (2, 1, 0). I know how to solve such tasks for $ain(mathbb R^3)$, but I really get stucked with finite field. How to solve tasks of such type?
linear-algebra matrices operator-algebras
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How much there exists operators of $ain End(mathbb{F}_p^3)$ such that a((2, -1, 3)) = (1, 1, -1), a((1, 2, 3)) = (1, 0, 1), a((3, 1, -1)) = (2, 1, 0). I know how to solve such tasks for $ain(mathbb R^3)$, but I really get stucked with finite field. How to solve tasks of such type?
linear-algebra matrices operator-algebras
Do you mean 'how many'?
– Seewoo Lee
Nov 27 '18 at 20:51
Sorry, it was a misprint.
– user596269
Nov 27 '18 at 20:57
add a comment |
How much there exists operators of $ain End(mathbb{F}_p^3)$ such that a((2, -1, 3)) = (1, 1, -1), a((1, 2, 3)) = (1, 0, 1), a((3, 1, -1)) = (2, 1, 0). I know how to solve such tasks for $ain(mathbb R^3)$, but I really get stucked with finite field. How to solve tasks of such type?
linear-algebra matrices operator-algebras
How much there exists operators of $ain End(mathbb{F}_p^3)$ such that a((2, -1, 3)) = (1, 1, -1), a((1, 2, 3)) = (1, 0, 1), a((3, 1, -1)) = (2, 1, 0). I know how to solve such tasks for $ain(mathbb R^3)$, but I really get stucked with finite field. How to solve tasks of such type?
linear-algebra matrices operator-algebras
linear-algebra matrices operator-algebras
edited Nov 27 '18 at 21:06
asked Nov 27 '18 at 20:48
user596269
Do you mean 'how many'?
– Seewoo Lee
Nov 27 '18 at 20:51
Sorry, it was a misprint.
– user596269
Nov 27 '18 at 20:57
add a comment |
Do you mean 'how many'?
– Seewoo Lee
Nov 27 '18 at 20:51
Sorry, it was a misprint.
– user596269
Nov 27 '18 at 20:57
Do you mean 'how many'?
– Seewoo Lee
Nov 27 '18 at 20:51
Do you mean 'how many'?
– Seewoo Lee
Nov 27 '18 at 20:51
Sorry, it was a misprint.
– user596269
Nov 27 '18 at 20:57
Sorry, it was a misprint.
– user596269
Nov 27 '18 at 20:57
add a comment |
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Do you mean 'how many'?
– Seewoo Lee
Nov 27 '18 at 20:51
Sorry, it was a misprint.
– user596269
Nov 27 '18 at 20:57