How to rewrite $left[begin{array}{c} Aotimes B_1\ vdots\ Aotimes B_T end{array}right]$?












1












$begingroup$


We have the following matrix



$left[begin{array}{c}
Aotimes B_1\
vdots\
Aotimes B_T
end{array}right]$
, where $A$ and the $B_i$ are matrices, and $otimes$ is the Kronecker product.



Is it possible to rewrite it as a Kronecker product where we gather all the $B_i$ matrices as one big matrix?



For example something like $(cdots) otimes left[begin{array}{c}
B_1\
vdots\
B_T
end{array}right]$










share|cite|improve this question











$endgroup$

















    1












    $begingroup$


    We have the following matrix



    $left[begin{array}{c}
    Aotimes B_1\
    vdots\
    Aotimes B_T
    end{array}right]$
    , where $A$ and the $B_i$ are matrices, and $otimes$ is the Kronecker product.



    Is it possible to rewrite it as a Kronecker product where we gather all the $B_i$ matrices as one big matrix?



    For example something like $(cdots) otimes left[begin{array}{c}
    B_1\
    vdots\
    B_T
    end{array}right]$










    share|cite|improve this question











    $endgroup$















      1












      1








      1


      1



      $begingroup$


      We have the following matrix



      $left[begin{array}{c}
      Aotimes B_1\
      vdots\
      Aotimes B_T
      end{array}right]$
      , where $A$ and the $B_i$ are matrices, and $otimes$ is the Kronecker product.



      Is it possible to rewrite it as a Kronecker product where we gather all the $B_i$ matrices as one big matrix?



      For example something like $(cdots) otimes left[begin{array}{c}
      B_1\
      vdots\
      B_T
      end{array}right]$










      share|cite|improve this question











      $endgroup$




      We have the following matrix



      $left[begin{array}{c}
      Aotimes B_1\
      vdots\
      Aotimes B_T
      end{array}right]$
      , where $A$ and the $B_i$ are matrices, and $otimes$ is the Kronecker product.



      Is it possible to rewrite it as a Kronecker product where we gather all the $B_i$ matrices as one big matrix?



      For example something like $(cdots) otimes left[begin{array}{c}
      B_1\
      vdots\
      B_T
      end{array}right]$







      linear-algebra kronecker-product






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Dec 21 '18 at 13:29









      Jean-Claude Arbaut

      14.9k63464




      14.9k63464










      asked Dec 21 '18 at 12:42









      An old man in the sea.An old man in the sea.

      1,65211135




      1,65211135






















          1 Answer
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          $begingroup$

          You could use the fact that $$mathbf A otimes mathbf B = mathbf K_{M,N} cdot left( mathbf B otimes mathbf Aright) cdot mathbf K_{P,Q}^{rm T},$$ for an $mathbf A in mathbb{F}^{M times P}$, $mathbf B in mathbb{F}^{N times Q}$ and $mathbb{F}$ is the field you are considering.



          Here, $mathbf K_{M,N}$ represents the commutation matrix of size $MN times MN$, which is the permutation matrix defined via $$mathbf K_{M,N}cdot {rm vec}{mathbf X} = {rm vec}{mathbf X^{rm T}}$$ for any $mathbf X in mathbb{F}^{M times N}$. A lot is known on these and they have some fun properties. Magnus and Neudecker [1,2] would be a good source to study.



          You could apply this to each row to "turn around" all your Kronecker products, which then allows to pull out $mathbf A$ completely. This should give you something like a ${rm diag}{mathbf K_1, ldots, mathbf K_T}$ in front, which may be a bit unhandy. But at least you know that such permutation matrices exist.



          Not sure if this helps anything!



          [1] Magnus, Jan R.; Neudecker, H., The commutation matrix: Some properties and applications, Ann. Stat. 7, 381-394 (1979). ZBL0414.62040.



          [2] Magnus, Jan R.; Neudecker, Heinz, Matrix differential calculus with applications in statistics and econometrics, Wiley Series in Probability and Mathematical Statistics. Applied Probability and Statistics. Chichester etc.: John Wiley & Sons. XVII, 393 p.; £ 24.50 (1988). ZBL0651.15001.






          share|cite|improve this answer









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            1 Answer
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            1 Answer
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            $begingroup$

            You could use the fact that $$mathbf A otimes mathbf B = mathbf K_{M,N} cdot left( mathbf B otimes mathbf Aright) cdot mathbf K_{P,Q}^{rm T},$$ for an $mathbf A in mathbb{F}^{M times P}$, $mathbf B in mathbb{F}^{N times Q}$ and $mathbb{F}$ is the field you are considering.



            Here, $mathbf K_{M,N}$ represents the commutation matrix of size $MN times MN$, which is the permutation matrix defined via $$mathbf K_{M,N}cdot {rm vec}{mathbf X} = {rm vec}{mathbf X^{rm T}}$$ for any $mathbf X in mathbb{F}^{M times N}$. A lot is known on these and they have some fun properties. Magnus and Neudecker [1,2] would be a good source to study.



            You could apply this to each row to "turn around" all your Kronecker products, which then allows to pull out $mathbf A$ completely. This should give you something like a ${rm diag}{mathbf K_1, ldots, mathbf K_T}$ in front, which may be a bit unhandy. But at least you know that such permutation matrices exist.



            Not sure if this helps anything!



            [1] Magnus, Jan R.; Neudecker, H., The commutation matrix: Some properties and applications, Ann. Stat. 7, 381-394 (1979). ZBL0414.62040.



            [2] Magnus, Jan R.; Neudecker, Heinz, Matrix differential calculus with applications in statistics and econometrics, Wiley Series in Probability and Mathematical Statistics. Applied Probability and Statistics. Chichester etc.: John Wiley & Sons. XVII, 393 p.; £ 24.50 (1988). ZBL0651.15001.






            share|cite|improve this answer









            $endgroup$


















              0












              $begingroup$

              You could use the fact that $$mathbf A otimes mathbf B = mathbf K_{M,N} cdot left( mathbf B otimes mathbf Aright) cdot mathbf K_{P,Q}^{rm T},$$ for an $mathbf A in mathbb{F}^{M times P}$, $mathbf B in mathbb{F}^{N times Q}$ and $mathbb{F}$ is the field you are considering.



              Here, $mathbf K_{M,N}$ represents the commutation matrix of size $MN times MN$, which is the permutation matrix defined via $$mathbf K_{M,N}cdot {rm vec}{mathbf X} = {rm vec}{mathbf X^{rm T}}$$ for any $mathbf X in mathbb{F}^{M times N}$. A lot is known on these and they have some fun properties. Magnus and Neudecker [1,2] would be a good source to study.



              You could apply this to each row to "turn around" all your Kronecker products, which then allows to pull out $mathbf A$ completely. This should give you something like a ${rm diag}{mathbf K_1, ldots, mathbf K_T}$ in front, which may be a bit unhandy. But at least you know that such permutation matrices exist.



              Not sure if this helps anything!



              [1] Magnus, Jan R.; Neudecker, H., The commutation matrix: Some properties and applications, Ann. Stat. 7, 381-394 (1979). ZBL0414.62040.



              [2] Magnus, Jan R.; Neudecker, Heinz, Matrix differential calculus with applications in statistics and econometrics, Wiley Series in Probability and Mathematical Statistics. Applied Probability and Statistics. Chichester etc.: John Wiley & Sons. XVII, 393 p.; £ 24.50 (1988). ZBL0651.15001.






              share|cite|improve this answer









              $endgroup$
















                0












                0








                0





                $begingroup$

                You could use the fact that $$mathbf A otimes mathbf B = mathbf K_{M,N} cdot left( mathbf B otimes mathbf Aright) cdot mathbf K_{P,Q}^{rm T},$$ for an $mathbf A in mathbb{F}^{M times P}$, $mathbf B in mathbb{F}^{N times Q}$ and $mathbb{F}$ is the field you are considering.



                Here, $mathbf K_{M,N}$ represents the commutation matrix of size $MN times MN$, which is the permutation matrix defined via $$mathbf K_{M,N}cdot {rm vec}{mathbf X} = {rm vec}{mathbf X^{rm T}}$$ for any $mathbf X in mathbb{F}^{M times N}$. A lot is known on these and they have some fun properties. Magnus and Neudecker [1,2] would be a good source to study.



                You could apply this to each row to "turn around" all your Kronecker products, which then allows to pull out $mathbf A$ completely. This should give you something like a ${rm diag}{mathbf K_1, ldots, mathbf K_T}$ in front, which may be a bit unhandy. But at least you know that such permutation matrices exist.



                Not sure if this helps anything!



                [1] Magnus, Jan R.; Neudecker, H., The commutation matrix: Some properties and applications, Ann. Stat. 7, 381-394 (1979). ZBL0414.62040.



                [2] Magnus, Jan R.; Neudecker, Heinz, Matrix differential calculus with applications in statistics and econometrics, Wiley Series in Probability and Mathematical Statistics. Applied Probability and Statistics. Chichester etc.: John Wiley & Sons. XVII, 393 p.; £ 24.50 (1988). ZBL0651.15001.






                share|cite|improve this answer









                $endgroup$



                You could use the fact that $$mathbf A otimes mathbf B = mathbf K_{M,N} cdot left( mathbf B otimes mathbf Aright) cdot mathbf K_{P,Q}^{rm T},$$ for an $mathbf A in mathbb{F}^{M times P}$, $mathbf B in mathbb{F}^{N times Q}$ and $mathbb{F}$ is the field you are considering.



                Here, $mathbf K_{M,N}$ represents the commutation matrix of size $MN times MN$, which is the permutation matrix defined via $$mathbf K_{M,N}cdot {rm vec}{mathbf X} = {rm vec}{mathbf X^{rm T}}$$ for any $mathbf X in mathbb{F}^{M times N}$. A lot is known on these and they have some fun properties. Magnus and Neudecker [1,2] would be a good source to study.



                You could apply this to each row to "turn around" all your Kronecker products, which then allows to pull out $mathbf A$ completely. This should give you something like a ${rm diag}{mathbf K_1, ldots, mathbf K_T}$ in front, which may be a bit unhandy. But at least you know that such permutation matrices exist.



                Not sure if this helps anything!



                [1] Magnus, Jan R.; Neudecker, H., The commutation matrix: Some properties and applications, Ann. Stat. 7, 381-394 (1979). ZBL0414.62040.



                [2] Magnus, Jan R.; Neudecker, Heinz, Matrix differential calculus with applications in statistics and econometrics, Wiley Series in Probability and Mathematical Statistics. Applied Probability and Statistics. Chichester etc.: John Wiley & Sons. XVII, 393 p.; £ 24.50 (1988). ZBL0651.15001.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Feb 15 at 12:04









                FlorianFlorian

                1,5172721




                1,5172721






























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