How to solve $int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$ [on hold]
up vote
-1
down vote
favorite
I don't know how to proceed this problem..
$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$
calculus
put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
up vote
-1
down vote
favorite
I don't know how to proceed this problem..
$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$
calculus
put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
1
I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01
add a comment |
up vote
-1
down vote
favorite
up vote
-1
down vote
favorite
I don't know how to proceed this problem..
$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$
calculus
I don't know how to proceed this problem..
$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$
calculus
calculus
edited Nov 19 at 4:38
PradyumanDixit
827214
827214
asked Nov 19 at 3:46
Devayani Sasi Kumar
21
21
put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138
If this question can be reworded to fit the rules in the help center, please edit the question.
1
I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01
add a comment |
1
I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01
1
1
I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01
I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01