How to solve $int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$ [on hold]











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I don't know how to proceed this problem..



$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$










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put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02


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  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138

If this question can be reworded to fit the rules in the help center, please edit the question.









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    I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
    – B. Goddard
    Nov 19 at 12:01

















up vote
-1
down vote

favorite












I don't know how to proceed this problem..



$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$










share|cite|improve this question















put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138

If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
    – B. Goddard
    Nov 19 at 12:01















up vote
-1
down vote

favorite









up vote
-1
down vote

favorite











I don't know how to proceed this problem..



$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$










share|cite|improve this question















I don't know how to proceed this problem..



$$int^{pi/2}_{0} frac {cos^{2m-1}x.sin^{2n-1}x .dx} {(a cos^2x+ b sin^2x)^{m+n}}$$







calculus






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share|cite|improve this question













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edited Nov 19 at 4:38









PradyumanDixit

827214




827214










asked Nov 19 at 3:46









Devayani Sasi Kumar

21




21




put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138

If this question can be reworded to fit the rules in the help center, please edit the question.




put on hold as off-topic by Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138 Nov 23 at 8:02


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Nosrati, Claude Leibovici, Paramanand Singh, user302797, user10354138

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 1




    I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
    – B. Goddard
    Nov 19 at 12:01
















  • 1




    I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
    – B. Goddard
    Nov 19 at 12:01










1




1




I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01






I think I would start with the substitution $u=sin x$ and replace all $cos^2 x$'s with $1-sin^2 x$.
– B. Goddard
Nov 19 at 12:01

















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