How to differentiate the function $f(x,y)=(y,x)$ at $ a=(a_1,a_2)$?











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How to differentiate the function $f(x,y)=(y,x)$ at $ a=(a_1,a_2)$?




$$begin{align}
limlimits_{h to 0}frac{Vert f(a+h)-f(a)-Df(a)hVert}{Vert hVert}
&=limlimits_{h to 0}frac{Vert (h_2+a_2,h_1+a_1)
-(a_2,a_1)-(0,a_1h_1)-(a_2h_2,0)Vert}{Vert hVert}\
&=limlimits_{h to 0}frac{Vert (h_2,h_1)-(a_2h_2,a_1h_1)Vert}{Vert hVert}\
&=limlimits_{h to 0}frac{Vert (h_2(1-a_2),h_1(1-a_1))vertvert}{Vert hVert}
end{align}
$$



At this point I don't think I can do anything because I don't know what $a_1$ and $a_2$ are. If I knew they were between $[-1,1]$, I could use squeeze theorem but I'm not sure what to do.










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    How to differentiate the function $f(x,y)=(y,x)$ at $ a=(a_1,a_2)$?




    $$begin{align}
    limlimits_{h to 0}frac{Vert f(a+h)-f(a)-Df(a)hVert}{Vert hVert}
    &=limlimits_{h to 0}frac{Vert (h_2+a_2,h_1+a_1)
    -(a_2,a_1)-(0,a_1h_1)-(a_2h_2,0)Vert}{Vert hVert}\
    &=limlimits_{h to 0}frac{Vert (h_2,h_1)-(a_2h_2,a_1h_1)Vert}{Vert hVert}\
    &=limlimits_{h to 0}frac{Vert (h_2(1-a_2),h_1(1-a_1))vertvert}{Vert hVert}
    end{align}
    $$



    At this point I don't think I can do anything because I don't know what $a_1$ and $a_2$ are. If I knew they were between $[-1,1]$, I could use squeeze theorem but I'm not sure what to do.










    share|cite|improve this question


























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      How to differentiate the function $f(x,y)=(y,x)$ at $ a=(a_1,a_2)$?




      $$begin{align}
      limlimits_{h to 0}frac{Vert f(a+h)-f(a)-Df(a)hVert}{Vert hVert}
      &=limlimits_{h to 0}frac{Vert (h_2+a_2,h_1+a_1)
      -(a_2,a_1)-(0,a_1h_1)-(a_2h_2,0)Vert}{Vert hVert}\
      &=limlimits_{h to 0}frac{Vert (h_2,h_1)-(a_2h_2,a_1h_1)Vert}{Vert hVert}\
      &=limlimits_{h to 0}frac{Vert (h_2(1-a_2),h_1(1-a_1))vertvert}{Vert hVert}
      end{align}
      $$



      At this point I don't think I can do anything because I don't know what $a_1$ and $a_2$ are. If I knew they were between $[-1,1]$, I could use squeeze theorem but I'm not sure what to do.










      share|cite|improve this question
















      How to differentiate the function $f(x,y)=(y,x)$ at $ a=(a_1,a_2)$?




      $$begin{align}
      limlimits_{h to 0}frac{Vert f(a+h)-f(a)-Df(a)hVert}{Vert hVert}
      &=limlimits_{h to 0}frac{Vert (h_2+a_2,h_1+a_1)
      -(a_2,a_1)-(0,a_1h_1)-(a_2h_2,0)Vert}{Vert hVert}\
      &=limlimits_{h to 0}frac{Vert (h_2,h_1)-(a_2h_2,a_1h_1)Vert}{Vert hVert}\
      &=limlimits_{h to 0}frac{Vert (h_2(1-a_2),h_1(1-a_1))vertvert}{Vert hVert}
      end{align}
      $$



      At this point I don't think I can do anything because I don't know what $a_1$ and $a_2$ are. If I knew they were between $[-1,1]$, I could use squeeze theorem but I'm not sure what to do.







      multivariable-calculus derivatives






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      edited Nov 20 at 2:52









      user587192

      1,295110




      1,295110










      asked Nov 20 at 2:09









      AColoredReptile

      1678




      1678






















          1 Answer
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          up vote
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          accepted










          Hint: You are trying to linearly approximate the function
          $$
          f(x,y)=(y,x)=begin{pmatrix} 0&1\1&0 end{pmatrix}begin{pmatrix}x\y end{pmatrix}
          $$






          share|cite|improve this answer





















          • Should $Df(a)h=begin{pmatrix} 0&ah_1\bh_2&0 end{pmatrix}$?
            – AColoredReptile
            Nov 20 at 2:26








          • 1




            Why does your candidate for the derivative depend on the variable in the limit?
            – qbert
            Nov 20 at 2:28










          • Sorry I mean $Df(a)h$
            – AColoredReptile
            Nov 20 at 2:29










          • still no, I think you should check your computation of $Df$
            – qbert
            Nov 20 at 2:41






          • 2




            Oh $Df=begin{pmatrix} D_1f_1&D_2f_1\D_1f_2&D_1f_2 end{pmatrix}=begin{pmatrix} 0&1\1&0 end{pmatrix}$? and $Df(a)h=begin{pmatrix} h_2\h_1 end{pmatrix}$
            – AColoredReptile
            Nov 20 at 2:46













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          1 Answer
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          active

          oldest

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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

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          up vote
          1
          down vote



          accepted










          Hint: You are trying to linearly approximate the function
          $$
          f(x,y)=(y,x)=begin{pmatrix} 0&1\1&0 end{pmatrix}begin{pmatrix}x\y end{pmatrix}
          $$






          share|cite|improve this answer





















          • Should $Df(a)h=begin{pmatrix} 0&ah_1\bh_2&0 end{pmatrix}$?
            – AColoredReptile
            Nov 20 at 2:26








          • 1




            Why does your candidate for the derivative depend on the variable in the limit?
            – qbert
            Nov 20 at 2:28










          • Sorry I mean $Df(a)h$
            – AColoredReptile
            Nov 20 at 2:29










          • still no, I think you should check your computation of $Df$
            – qbert
            Nov 20 at 2:41






          • 2




            Oh $Df=begin{pmatrix} D_1f_1&D_2f_1\D_1f_2&D_1f_2 end{pmatrix}=begin{pmatrix} 0&1\1&0 end{pmatrix}$? and $Df(a)h=begin{pmatrix} h_2\h_1 end{pmatrix}$
            – AColoredReptile
            Nov 20 at 2:46

















          up vote
          1
          down vote



          accepted










          Hint: You are trying to linearly approximate the function
          $$
          f(x,y)=(y,x)=begin{pmatrix} 0&1\1&0 end{pmatrix}begin{pmatrix}x\y end{pmatrix}
          $$






          share|cite|improve this answer





















          • Should $Df(a)h=begin{pmatrix} 0&ah_1\bh_2&0 end{pmatrix}$?
            – AColoredReptile
            Nov 20 at 2:26








          • 1




            Why does your candidate for the derivative depend on the variable in the limit?
            – qbert
            Nov 20 at 2:28










          • Sorry I mean $Df(a)h$
            – AColoredReptile
            Nov 20 at 2:29










          • still no, I think you should check your computation of $Df$
            – qbert
            Nov 20 at 2:41






          • 2




            Oh $Df=begin{pmatrix} D_1f_1&D_2f_1\D_1f_2&D_1f_2 end{pmatrix}=begin{pmatrix} 0&1\1&0 end{pmatrix}$? and $Df(a)h=begin{pmatrix} h_2\h_1 end{pmatrix}$
            – AColoredReptile
            Nov 20 at 2:46















          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          Hint: You are trying to linearly approximate the function
          $$
          f(x,y)=(y,x)=begin{pmatrix} 0&1\1&0 end{pmatrix}begin{pmatrix}x\y end{pmatrix}
          $$






          share|cite|improve this answer












          Hint: You are trying to linearly approximate the function
          $$
          f(x,y)=(y,x)=begin{pmatrix} 0&1\1&0 end{pmatrix}begin{pmatrix}x\y end{pmatrix}
          $$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Nov 20 at 2:16









          qbert

          21.6k32459




          21.6k32459












          • Should $Df(a)h=begin{pmatrix} 0&ah_1\bh_2&0 end{pmatrix}$?
            – AColoredReptile
            Nov 20 at 2:26








          • 1




            Why does your candidate for the derivative depend on the variable in the limit?
            – qbert
            Nov 20 at 2:28










          • Sorry I mean $Df(a)h$
            – AColoredReptile
            Nov 20 at 2:29










          • still no, I think you should check your computation of $Df$
            – qbert
            Nov 20 at 2:41






          • 2




            Oh $Df=begin{pmatrix} D_1f_1&D_2f_1\D_1f_2&D_1f_2 end{pmatrix}=begin{pmatrix} 0&1\1&0 end{pmatrix}$? and $Df(a)h=begin{pmatrix} h_2\h_1 end{pmatrix}$
            – AColoredReptile
            Nov 20 at 2:46




















          • Should $Df(a)h=begin{pmatrix} 0&ah_1\bh_2&0 end{pmatrix}$?
            – AColoredReptile
            Nov 20 at 2:26








          • 1




            Why does your candidate for the derivative depend on the variable in the limit?
            – qbert
            Nov 20 at 2:28










          • Sorry I mean $Df(a)h$
            – AColoredReptile
            Nov 20 at 2:29










          • still no, I think you should check your computation of $Df$
            – qbert
            Nov 20 at 2:41






          • 2




            Oh $Df=begin{pmatrix} D_1f_1&D_2f_1\D_1f_2&D_1f_2 end{pmatrix}=begin{pmatrix} 0&1\1&0 end{pmatrix}$? and $Df(a)h=begin{pmatrix} h_2\h_1 end{pmatrix}$
            – AColoredReptile
            Nov 20 at 2:46


















          Should $Df(a)h=begin{pmatrix} 0&ah_1\bh_2&0 end{pmatrix}$?
          – AColoredReptile
          Nov 20 at 2:26






          Should $Df(a)h=begin{pmatrix} 0&ah_1\bh_2&0 end{pmatrix}$?
          – AColoredReptile
          Nov 20 at 2:26






          1




          1




          Why does your candidate for the derivative depend on the variable in the limit?
          – qbert
          Nov 20 at 2:28




          Why does your candidate for the derivative depend on the variable in the limit?
          – qbert
          Nov 20 at 2:28












          Sorry I mean $Df(a)h$
          – AColoredReptile
          Nov 20 at 2:29




          Sorry I mean $Df(a)h$
          – AColoredReptile
          Nov 20 at 2:29












          still no, I think you should check your computation of $Df$
          – qbert
          Nov 20 at 2:41




          still no, I think you should check your computation of $Df$
          – qbert
          Nov 20 at 2:41




          2




          2




          Oh $Df=begin{pmatrix} D_1f_1&D_2f_1\D_1f_2&D_1f_2 end{pmatrix}=begin{pmatrix} 0&1\1&0 end{pmatrix}$? and $Df(a)h=begin{pmatrix} h_2\h_1 end{pmatrix}$
          – AColoredReptile
          Nov 20 at 2:46






          Oh $Df=begin{pmatrix} D_1f_1&D_2f_1\D_1f_2&D_1f_2 end{pmatrix}=begin{pmatrix} 0&1\1&0 end{pmatrix}$? and $Df(a)h=begin{pmatrix} h_2\h_1 end{pmatrix}$
          – AColoredReptile
          Nov 20 at 2:46




















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