Rewriting a logical statement












1














Only lakers are irrational people.



I believe it technically should be translated as:



All irrational people are lakers.



Is there is any way at all to rewrite the above statement to mean the following and be logically correct:



All lakers are irrational people.



How would you justify it? (If it is possible)










share|cite|improve this question



























    1














    Only lakers are irrational people.



    I believe it technically should be translated as:



    All irrational people are lakers.



    Is there is any way at all to rewrite the above statement to mean the following and be logically correct:



    All lakers are irrational people.



    How would you justify it? (If it is possible)










    share|cite|improve this question

























      1












      1








      1







      Only lakers are irrational people.



      I believe it technically should be translated as:



      All irrational people are lakers.



      Is there is any way at all to rewrite the above statement to mean the following and be logically correct:



      All lakers are irrational people.



      How would you justify it? (If it is possible)










      share|cite|improve this question













      Only lakers are irrational people.



      I believe it technically should be translated as:



      All irrational people are lakers.



      Is there is any way at all to rewrite the above statement to mean the following and be logically correct:



      All lakers are irrational people.



      How would you justify it? (If it is possible)







      logic logic-translation






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Nov 26 at 17:42









      Phillip

      112




      112






















          3 Answers
          3






          active

          oldest

          votes


















          1














          Indicating with $L$ the set of lakers $l$ and with $Pi$ the set of irrational people $pi$, the first statement is equivalent to



          $$forall piin Pi quad piin L$$



          the second one is



          $$forall lin Lquad lin Pi $$



          which is not equivalent to the first one, indeed from this last one we could also have $pi not in L$ for aome $pi$.






          share|cite|improve this answer





























            0














            All rational people are not lakers.



            The opposite converse is equally valid.



            The converse that you posit is not equally valid.






            share|cite|improve this answer





























              0














              Your initial translation is correct, though in standard form I would write



              All non-rational people are lakers.



              This is an Aristotelian A type statement, and A type statements have valid obverses and valid contrapositives. They do not have valid converses.



              Obverse: No non-rational people are non-lakers.



              Contrapositive: All non-lakers are rational people.



              So the ultimate answer to your question is no, because you are trying to get the converse of an A statement to be true, which does not happen in general.



              If you had an E or I statement, the converse would be valid.






              share|cite|improve this answer





















                Your Answer





                StackExchange.ifUsing("editor", function () {
                return StackExchange.using("mathjaxEditing", function () {
                StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
                StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
                });
                });
                }, "mathjax-editing");

                StackExchange.ready(function() {
                var channelOptions = {
                tags: "".split(" "),
                id: "69"
                };
                initTagRenderer("".split(" "), "".split(" "), channelOptions);

                StackExchange.using("externalEditor", function() {
                // Have to fire editor after snippets, if snippets enabled
                if (StackExchange.settings.snippets.snippetsEnabled) {
                StackExchange.using("snippets", function() {
                createEditor();
                });
                }
                else {
                createEditor();
                }
                });

                function createEditor() {
                StackExchange.prepareEditor({
                heartbeatType: 'answer',
                autoActivateHeartbeat: false,
                convertImagesToLinks: true,
                noModals: true,
                showLowRepImageUploadWarning: true,
                reputationToPostImages: 10,
                bindNavPrevention: true,
                postfix: "",
                imageUploader: {
                brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
                contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
                allowUrls: true
                },
                noCode: true, onDemand: true,
                discardSelector: ".discard-answer"
                ,immediatelyShowMarkdownHelp:true
                });


                }
                });














                draft saved

                draft discarded


















                StackExchange.ready(
                function () {
                StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3014649%2frewriting-a-logical-statement%23new-answer', 'question_page');
                }
                );

                Post as a guest















                Required, but never shown

























                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                1














                Indicating with $L$ the set of lakers $l$ and with $Pi$ the set of irrational people $pi$, the first statement is equivalent to



                $$forall piin Pi quad piin L$$



                the second one is



                $$forall lin Lquad lin Pi $$



                which is not equivalent to the first one, indeed from this last one we could also have $pi not in L$ for aome $pi$.






                share|cite|improve this answer


























                  1














                  Indicating with $L$ the set of lakers $l$ and with $Pi$ the set of irrational people $pi$, the first statement is equivalent to



                  $$forall piin Pi quad piin L$$



                  the second one is



                  $$forall lin Lquad lin Pi $$



                  which is not equivalent to the first one, indeed from this last one we could also have $pi not in L$ for aome $pi$.






                  share|cite|improve this answer
























                    1












                    1








                    1






                    Indicating with $L$ the set of lakers $l$ and with $Pi$ the set of irrational people $pi$, the first statement is equivalent to



                    $$forall piin Pi quad piin L$$



                    the second one is



                    $$forall lin Lquad lin Pi $$



                    which is not equivalent to the first one, indeed from this last one we could also have $pi not in L$ for aome $pi$.






                    share|cite|improve this answer












                    Indicating with $L$ the set of lakers $l$ and with $Pi$ the set of irrational people $pi$, the first statement is equivalent to



                    $$forall piin Pi quad piin L$$



                    the second one is



                    $$forall lin Lquad lin Pi $$



                    which is not equivalent to the first one, indeed from this last one we could also have $pi not in L$ for aome $pi$.







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered Nov 26 at 17:49









                    gimusi

                    1




                    1























                        0














                        All rational people are not lakers.



                        The opposite converse is equally valid.



                        The converse that you posit is not equally valid.






                        share|cite|improve this answer


























                          0














                          All rational people are not lakers.



                          The opposite converse is equally valid.



                          The converse that you posit is not equally valid.






                          share|cite|improve this answer
























                            0












                            0








                            0






                            All rational people are not lakers.



                            The opposite converse is equally valid.



                            The converse that you posit is not equally valid.






                            share|cite|improve this answer












                            All rational people are not lakers.



                            The opposite converse is equally valid.



                            The converse that you posit is not equally valid.







                            share|cite|improve this answer












                            share|cite|improve this answer



                            share|cite|improve this answer










                            answered Nov 26 at 17:46









                            John L Winters

                            829




                            829























                                0














                                Your initial translation is correct, though in standard form I would write



                                All non-rational people are lakers.



                                This is an Aristotelian A type statement, and A type statements have valid obverses and valid contrapositives. They do not have valid converses.



                                Obverse: No non-rational people are non-lakers.



                                Contrapositive: All non-lakers are rational people.



                                So the ultimate answer to your question is no, because you are trying to get the converse of an A statement to be true, which does not happen in general.



                                If you had an E or I statement, the converse would be valid.






                                share|cite|improve this answer


























                                  0














                                  Your initial translation is correct, though in standard form I would write



                                  All non-rational people are lakers.



                                  This is an Aristotelian A type statement, and A type statements have valid obverses and valid contrapositives. They do not have valid converses.



                                  Obverse: No non-rational people are non-lakers.



                                  Contrapositive: All non-lakers are rational people.



                                  So the ultimate answer to your question is no, because you are trying to get the converse of an A statement to be true, which does not happen in general.



                                  If you had an E or I statement, the converse would be valid.






                                  share|cite|improve this answer
























                                    0












                                    0








                                    0






                                    Your initial translation is correct, though in standard form I would write



                                    All non-rational people are lakers.



                                    This is an Aristotelian A type statement, and A type statements have valid obverses and valid contrapositives. They do not have valid converses.



                                    Obverse: No non-rational people are non-lakers.



                                    Contrapositive: All non-lakers are rational people.



                                    So the ultimate answer to your question is no, because you are trying to get the converse of an A statement to be true, which does not happen in general.



                                    If you had an E or I statement, the converse would be valid.






                                    share|cite|improve this answer












                                    Your initial translation is correct, though in standard form I would write



                                    All non-rational people are lakers.



                                    This is an Aristotelian A type statement, and A type statements have valid obverses and valid contrapositives. They do not have valid converses.



                                    Obverse: No non-rational people are non-lakers.



                                    Contrapositive: All non-lakers are rational people.



                                    So the ultimate answer to your question is no, because you are trying to get the converse of an A statement to be true, which does not happen in general.



                                    If you had an E or I statement, the converse would be valid.







                                    share|cite|improve this answer












                                    share|cite|improve this answer



                                    share|cite|improve this answer










                                    answered Nov 26 at 17:51









                                    Adrian Keister

                                    4,77351933




                                    4,77351933






























                                        draft saved

                                        draft discarded




















































                                        Thanks for contributing an answer to Mathematics Stack Exchange!


                                        • Please be sure to answer the question. Provide details and share your research!

                                        But avoid



                                        • Asking for help, clarification, or responding to other answers.

                                        • Making statements based on opinion; back them up with references or personal experience.


                                        Use MathJax to format equations. MathJax reference.


                                        To learn more, see our tips on writing great answers.





                                        Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                                        Please pay close attention to the following guidance:


                                        • Please be sure to answer the question. Provide details and share your research!

                                        But avoid



                                        • Asking for help, clarification, or responding to other answers.

                                        • Making statements based on opinion; back them up with references or personal experience.


                                        To learn more, see our tips on writing great answers.




                                        draft saved


                                        draft discarded














                                        StackExchange.ready(
                                        function () {
                                        StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3014649%2frewriting-a-logical-statement%23new-answer', 'question_page');
                                        }
                                        );

                                        Post as a guest















                                        Required, but never shown





















































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown

































                                        Required, but never shown














                                        Required, but never shown












                                        Required, but never shown







                                        Required, but never shown







                                        Popular posts from this blog

                                        Bundesstraße 106

                                        Verónica Boquete

                                        Ida-Boy-Ed-Garten