Simplify an if/else statement?
I'm trying to simplify the following:
function handleDirection(src) {
if (src === 'left') {
if (inverse) {
tracker--;
} else {
tracker++;
}
} else {
if (inverse) {
tracker++;
} else {
tracker--;
}
}
}
to reduce the number of conditionals. The src
will either be 'left'
or 'right'
always.
javascript if-statement conditional
|
show 5 more comments
I'm trying to simplify the following:
function handleDirection(src) {
if (src === 'left') {
if (inverse) {
tracker--;
} else {
tracker++;
}
} else {
if (inverse) {
tracker++;
} else {
tracker--;
}
}
}
to reduce the number of conditionals. The src
will either be 'left'
or 'right'
always.
javascript if-statement conditional
9
There's now a range of answers - one thing to bear in mind with this sort of thing is maintainability, that includes whether you yourself will understand what this code does next week. Make sure you pick a form of logic that is clear to you what it's doing at a glance - if that's the long form in your original question, stick with it.
– James Thorpe
Dec 13 '18 at 10:31
14
I'm voting to close this question as off-topic because it belongs to codereview.stackexchange.com
– Gabriele Petrioli
Dec 13 '18 at 10:33
10
Side note: your function uses 3 variables (src
,inverse
andtracker
) but it has only 1 parameter (src
) and no return value. For that reason it would not pass my code review, regardless of how you structure theif
s....
– Peter B
Dec 13 '18 at 10:34
1
@PeterB I'd generally agree, but it's worth noting that context is key. If this were a method in an object, then it might be fine. This could be manipulating some sort of cursor (tracker
) via commands ("left"
/"right"
), the object itself has a flag that it would be moved in the opposite direction (invert
). However, as a free-floating function, that's indeed bad, as you're manipulating some not necessarily related global states.
– VLAZ
Dec 13 '18 at 10:44
1
Thanks all—it is a free-floating function currently; the main purpose of me asking this question is to capture the most efficient method of writing this conditional. I often find that it's the simpler things like this that trip me up, so asking this question now before I delve further is useful. The answers below are all interesting approaches which I must test.
– Rebecca O'Sullivan
Dec 13 '18 at 11:01
|
show 5 more comments
I'm trying to simplify the following:
function handleDirection(src) {
if (src === 'left') {
if (inverse) {
tracker--;
} else {
tracker++;
}
} else {
if (inverse) {
tracker++;
} else {
tracker--;
}
}
}
to reduce the number of conditionals. The src
will either be 'left'
or 'right'
always.
javascript if-statement conditional
I'm trying to simplify the following:
function handleDirection(src) {
if (src === 'left') {
if (inverse) {
tracker--;
} else {
tracker++;
}
} else {
if (inverse) {
tracker++;
} else {
tracker--;
}
}
}
to reduce the number of conditionals. The src
will either be 'left'
or 'right'
always.
javascript if-statement conditional
javascript if-statement conditional
edited Dec 13 '18 at 17:34
Charlie Harding
361415
361415
asked Dec 13 '18 at 10:24
Rebecca O'SullivanRebecca O'Sullivan
446314
446314
9
There's now a range of answers - one thing to bear in mind with this sort of thing is maintainability, that includes whether you yourself will understand what this code does next week. Make sure you pick a form of logic that is clear to you what it's doing at a glance - if that's the long form in your original question, stick with it.
– James Thorpe
Dec 13 '18 at 10:31
14
I'm voting to close this question as off-topic because it belongs to codereview.stackexchange.com
– Gabriele Petrioli
Dec 13 '18 at 10:33
10
Side note: your function uses 3 variables (src
,inverse
andtracker
) but it has only 1 parameter (src
) and no return value. For that reason it would not pass my code review, regardless of how you structure theif
s....
– Peter B
Dec 13 '18 at 10:34
1
@PeterB I'd generally agree, but it's worth noting that context is key. If this were a method in an object, then it might be fine. This could be manipulating some sort of cursor (tracker
) via commands ("left"
/"right"
), the object itself has a flag that it would be moved in the opposite direction (invert
). However, as a free-floating function, that's indeed bad, as you're manipulating some not necessarily related global states.
– VLAZ
Dec 13 '18 at 10:44
1
Thanks all—it is a free-floating function currently; the main purpose of me asking this question is to capture the most efficient method of writing this conditional. I often find that it's the simpler things like this that trip me up, so asking this question now before I delve further is useful. The answers below are all interesting approaches which I must test.
– Rebecca O'Sullivan
Dec 13 '18 at 11:01
|
show 5 more comments
9
There's now a range of answers - one thing to bear in mind with this sort of thing is maintainability, that includes whether you yourself will understand what this code does next week. Make sure you pick a form of logic that is clear to you what it's doing at a glance - if that's the long form in your original question, stick with it.
– James Thorpe
Dec 13 '18 at 10:31
14
I'm voting to close this question as off-topic because it belongs to codereview.stackexchange.com
– Gabriele Petrioli
Dec 13 '18 at 10:33
10
Side note: your function uses 3 variables (src
,inverse
andtracker
) but it has only 1 parameter (src
) and no return value. For that reason it would not pass my code review, regardless of how you structure theif
s....
– Peter B
Dec 13 '18 at 10:34
1
@PeterB I'd generally agree, but it's worth noting that context is key. If this were a method in an object, then it might be fine. This could be manipulating some sort of cursor (tracker
) via commands ("left"
/"right"
), the object itself has a flag that it would be moved in the opposite direction (invert
). However, as a free-floating function, that's indeed bad, as you're manipulating some not necessarily related global states.
– VLAZ
Dec 13 '18 at 10:44
1
Thanks all—it is a free-floating function currently; the main purpose of me asking this question is to capture the most efficient method of writing this conditional. I often find that it's the simpler things like this that trip me up, so asking this question now before I delve further is useful. The answers below are all interesting approaches which I must test.
– Rebecca O'Sullivan
Dec 13 '18 at 11:01
9
9
There's now a range of answers - one thing to bear in mind with this sort of thing is maintainability, that includes whether you yourself will understand what this code does next week. Make sure you pick a form of logic that is clear to you what it's doing at a glance - if that's the long form in your original question, stick with it.
– James Thorpe
Dec 13 '18 at 10:31
There's now a range of answers - one thing to bear in mind with this sort of thing is maintainability, that includes whether you yourself will understand what this code does next week. Make sure you pick a form of logic that is clear to you what it's doing at a glance - if that's the long form in your original question, stick with it.
– James Thorpe
Dec 13 '18 at 10:31
14
14
I'm voting to close this question as off-topic because it belongs to codereview.stackexchange.com
– Gabriele Petrioli
Dec 13 '18 at 10:33
I'm voting to close this question as off-topic because it belongs to codereview.stackexchange.com
– Gabriele Petrioli
Dec 13 '18 at 10:33
10
10
Side note: your function uses 3 variables (
src
, inverse
and tracker
) but it has only 1 parameter (src
) and no return value. For that reason it would not pass my code review, regardless of how you structure the if
s....– Peter B
Dec 13 '18 at 10:34
Side note: your function uses 3 variables (
src
, inverse
and tracker
) but it has only 1 parameter (src
) and no return value. For that reason it would not pass my code review, regardless of how you structure the if
s....– Peter B
Dec 13 '18 at 10:34
1
1
@PeterB I'd generally agree, but it's worth noting that context is key. If this were a method in an object, then it might be fine. This could be manipulating some sort of cursor (
tracker
) via commands ("left"
/"right"
), the object itself has a flag that it would be moved in the opposite direction (invert
). However, as a free-floating function, that's indeed bad, as you're manipulating some not necessarily related global states.– VLAZ
Dec 13 '18 at 10:44
@PeterB I'd generally agree, but it's worth noting that context is key. If this were a method in an object, then it might be fine. This could be manipulating some sort of cursor (
tracker
) via commands ("left"
/"right"
), the object itself has a flag that it would be moved in the opposite direction (invert
). However, as a free-floating function, that's indeed bad, as you're manipulating some not necessarily related global states.– VLAZ
Dec 13 '18 at 10:44
1
1
Thanks all—it is a free-floating function currently; the main purpose of me asking this question is to capture the most efficient method of writing this conditional. I often find that it's the simpler things like this that trip me up, so asking this question now before I delve further is useful. The answers below are all interesting approaches which I must test.
– Rebecca O'Sullivan
Dec 13 '18 at 11:01
Thanks all—it is a free-floating function currently; the main purpose of me asking this question is to capture the most efficient method of writing this conditional. I often find that it's the simpler things like this that trip me up, so asking this question now before I delve further is useful. The answers below are all interesting approaches which I must test.
– Rebecca O'Sullivan
Dec 13 '18 at 11:01
|
show 5 more comments
12 Answers
12
active
oldest
votes
You could check with the result of the first check.
This is an exclusive OR check.
// typeof inverse === 'boolean'
function handleDirection(src) {
if (src === 'left' === inverse) {
tracker--;
} else {
tracker++;
}
}
The check evaluates the expression in this order (src === 'left') === inverse
:
src === 'left' === inverse
---- first --- returns a boolean value
--------- second --------- take result of former check & compairs it with another boolean
2
^^ only in this special case
– Nina Scholz
Dec 13 '18 at 10:33
1
Ah, makes sense I suppose (bool) == (condition_met) .. +2 skill points to efficiency! thank you :)
– treyBake
Dec 13 '18 at 10:40
7
I definitely agree with @marcelm. As wonderful as this answer looks, it is not immediately obvious what is happening.
– Marie
Dec 13 '18 at 16:18
5
I'd use this only if you really need the performance boost and/or only work with people who'd be able to intuitively read this and come up with this. The other approach maybe longer, but it's much more readable to the average developer.
– Frank Hopkins
Dec 13 '18 at 16:21
1
@afe If you're doing it with the ternary operator, I think an increment (tracker += (src == 'left') == inverse ? -1 : +1;
) is a little clearer
– Charlie Harding
Dec 13 '18 at 17:05
|
show 8 more comments
function handleDirection(src) {
var movement = 1;
if(src === 'left')
movement = -1;
if(inverse)
tracker += movement;
else
tracker -= movement;
}
2
This creates an unnecessary extra variable imo... Usingtracker--
andtracker++
is the correct way to increase and decrease the variable in this case. If it were desired to increase or lower the variable with more than one this might be a good guideline.
– MagicLegend
Dec 13 '18 at 11:01
3
@MagicLegend Actually, I think the variable helps bring "real world" parity to the solution. The other answers focus on "efficiency" which is probably irrelevant in such a simple case. The interpreter doesn't need help reading, but humans do. Although I upvoted, I would go further and give the variable a more meaningful name likeadjustment
ormovement
.
– TheRubberDuck
Dec 13 '18 at 16:41
add a comment |
You can even do it with just one line of Code:
function getDirectionOffset(src) {
tracker += (src === 'left' ? 1 : -1) * (inverse ? -1 : 1);
}
1
Very nice solution!
– Julius Naeumann
Dec 14 '18 at 12:52
add a comment |
This could be simplified to a ternary expression which returns 1
or -1
depending on the state. Then you can just add that to the tracker
.
function handleDirection(src) {
var delta = (src === 'left' && inverse) || (src !== 'left' && !inverse) ? -1 : 1;
tracker += delta;
}
This could then be simplified further using the logic which @NinaScholz pointed out in her answer:
function handleDirection(src) {
var delta = (src === 'left') === inverse ? -1 : 1;
tracker += delta;
}
add a comment |
Assuming inverse
is a flag you'd set once, then you don't need to take it into account every time, you can calculate its impact once and just use it as it is, which will cut down your code branches and logic. If you want to change it as you go along, then you might need to separate the logic for the calculation, in order to re-use it.
You can also then extract the movement direction into a self-contained function and your handleDirection
becomes very simple - you calculate the direction you want to go based on src
and the invert
.
let tracker = 0;
//extract logic for the movement offset based on direction
function getDirectionOffset(src) {
return src === 'left' ? 1 : -1;
}
//have a setter for the invert property
function setInverse(isInverse) {
movementModifier = isInverse ? -1 : 1
}
//declare the variable dependent on the inverse property
let movementModifier;
//initialise movementModifier variable
setInverse(false);
function handleDirection(src) {
const offset = getDirectionOffset(src) * movementModifier;
tracker += offset;
}
// usage
setInverse(true);
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
With that said, all this suggests you shouldn't be using a function, or you should be using it differently. You can collect all that functionality in a class or instead have all the information passed around functions, so you don't have globals. Here is a sample object oriented implementation of the concept:
class TrackerMover {
constructor(inverse) {
this.tracker = 0;
this.movementModifier = inverse ? 1 : -1
}
handleDirection(src) {
const offset = this.getDirectionOffset(src) * this.movementModifier;
this.tracker += offset;
}
getDirectionOffset(src) {
return src === 'left' ? -1 : 1;
}
getPosition() {
return this.tracker;
}
}
//usage
const mover = new TrackerMover(true);
mover.handleDirection("left");
mover.handleDirection("left");
mover.handleDirection("right");
console.log(mover.getPosition())
By the way, another alternative is to NOT compute the movement every time. You actually know what is happening every time - in effect, you have a truth table where your inputs are src === left
and inverse
and the outputs are how you modify your tracking.
+--------+------------+--------+
| isLeft | isInverted | Offset |
+--------+------------+--------+
| true | true | -1 |
| true | false | 1 |
| false | true | 1 |
| false | false | -1 |
+--------+------------+--------+
So, you can just put that table in.
let tracker = 0;
let invert = false;
const movementLookupTable = {
"true": { },
"false": { },
}
//it can be initialised as part of the above expression but this is more readable
movementLookupTable[true ][true ] = -1;
movementLookupTable[true ][false] = 1;
movementLookupTable[false][true ] = 1;
movementLookupTable[false][false] = -1;
function handleDirection(src) {
const offset = movementLookupTable[src === "left"][invert];
tracker += offset;
}
// usage
invert = true;
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
In this case it might be an overkill but this approach might be useful if there are more flags (including more values for the flags) and/or end states. For example, maybe you want to introduce four directions, but you don't modify the tracker
value if it's up
or down
.
+-----------+------------+--------+
| direction | isInverted | Offset |
+-----------+------------+--------+
| left | true | -1 |
| left | false | 1 |
| right | true | 1 |
| right | false | -1 |
| up | false | 0 |
| up | true | 0 |
| down | false | 0 |
| down | true | 0 |
+-----------+------------+--------+
As you can see, now it's not just booleans, you can handle any value. Using a table, you also then change invert
to be something like windDirection
, so if the movement is left
and the windDirection
is right
, the result is like what it is now, but you could have direction of left
and wind going left
, so you move further. Or you can move up
and the wind direction is left
so tracker
(at this point the X coordinates) is going to actually be modified.
+-----------+---------------+---------+
| direction | windDirection | OffsetX |
+-----------+---------------+---------+
| left | right | -1 |
| left | up | 1 |
| left | down | 1 |
| left | left | 2 |
| right | up | -1 |
| right | down | -1 |
| right | right | -2 |
| right | left | 1 |
| up | up | 0 |
| up | down | 0 |
| up | left | 1 |
| up | right | -1 |
| down | up | 0 |
| down | down | 0 |
| down | left | 1 |
| down | right | -1 |
+-----------+---------------+---------+
With four directions and four wind directions to take into account the logic can be quite annoying to both read and maintain in the future, while if you only have a lookup table, it's easy and you can easily extend this to even handle diagonals (let's assume they change the value by 0.5
instead of 1
) and your algorithm would not really care as long as you just fetch the values from the table.
add a comment |
This has only one conditional, and I find it reads more intuitively than the other answers:
function handleDirection(src) {
if (
((src === 'left') && !inverse) ||
((src === 'right') && inverse)
) {
tracker++;
}
else {
tracker--;
}
}
add a comment |
You want to increase the tracker if one of src == left
or inverse
is true but not the other, and decrease it otherwise, which is what the "XOR" ^
operator does :
function handleDirection(src) {
if (src === 'left' ^ inverse) {
tracker++;
} else {
tracker--;
}
}
You can reduce that further by using a ternary expression :
function handleDirection(src) {
tracker += src === 'left' ^ inverse ? 1 : -1;
}
Or if you want to avoid any kind of conditionnal, with implicit casts and "clever" arithmetics :
function handleDirection(src) {
tracker += 1 - 2 * (src === 'right' ^ inverse); // either 1-0=1 or 1-2=-1
}
1
You got the logic backwards, and I hate the third example, but +1 for actually using the operator built for this.
– Jacob Raihle
Dec 13 '18 at 17:08
2
@JacobRaihle thanks, I fixed the backward logic. The quotes around "clever" for the third example are sarcasm quotes, I wouldn't recommend using it unless the only point is to play the smartass.
– Aaron
Dec 13 '18 at 17:18
add a comment |
You don't need any if
sentence at all. The same operation can be performed by
calculating a positive or negative increment depending on src and inverse
with just the help of ternary operator.
function handleDirection(src) {
tracker += (src == "left" ? 1 : -1) * (inverse ? -1 : 1);
};
Btw. For the sake of efficiency, I would recommend directly use numeric
increments / decrements instead of strings that requires extra processing to be
decoded. You can use constants to achieve the same readability:
Also inverse can be optimised as a numeric value switching between 1 (not
inverted) and -1 (inverted).
const left = 1;
const right = -1;
var direction = 1;
function handleDirection(src) {
tracker += src * direction;
}
function reverse() { // (Example)
direction = direction * -1;
}
...even if "right" and "left" keywords comes from some sort of textual user
input, you can simply translate them from a dictionary:
const steps = {
left = 1;
right = -1;
};
function handleDirection(src) {
tracker += steps[src] * direction;
}
add a comment |
You can use short circuiting syntax or ternary operators
// by using short circuiting
function handleDirection(src) {
if (src == 'left') tracker = inverse && tracker-1 || tracker +1
else tracker = inverse && tracker+1 || tracker -1
}
// by using ternary operator
function handleDirection(src) {
if (src == 'left') tracker = inverse ? tracker-1 : tracker +1
else tracker = inverse ? tracker+1 : tracker -1
}
add a comment |
I dislike elses and try to avoid nesting if possible. I think this conveys the idea of inverse
in a more natural way:
function handleDirection(src)
{
let change = 1;
if ('right' == src)
change = -1;
if (inverse)
change = -change;
tracker += change;
}
add a comment |
Right now you are comparing on strings, which I wouldn't advise. If for example you use 'Left' instead of 'left' it will fail the first if statement. Perhaps a boolean could be of use here, since you can guarantee it only has two states.
The if statements inside can be compressed via conditional operators.
Perhaps something like this is what you are looking for:
function handleDirection(src) {
if (src) {
inverse ? tracker-- : tracker++;
} else {
inverse ? tracker++ : tracker--;
}
}
See: https://jsfiddle.net/9zr4f3nv/
3
Your two branches of the if statement are identical: one of them needs to be reversed
– Charlie Harding
Dec 13 '18 at 17:03
Oopsie! You're right hehe. Corrected!
– MagicLegend
Dec 14 '18 at 17:06
add a comment |
You could use an 2 dimensional array type data structure from js and store the desired outcomes at index sec and inverse. Or JSON.
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53759675%2fsimplify-an-if-else-statement%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
12 Answers
12
active
oldest
votes
12 Answers
12
active
oldest
votes
active
oldest
votes
active
oldest
votes
You could check with the result of the first check.
This is an exclusive OR check.
// typeof inverse === 'boolean'
function handleDirection(src) {
if (src === 'left' === inverse) {
tracker--;
} else {
tracker++;
}
}
The check evaluates the expression in this order (src === 'left') === inverse
:
src === 'left' === inverse
---- first --- returns a boolean value
--------- second --------- take result of former check & compairs it with another boolean
2
^^ only in this special case
– Nina Scholz
Dec 13 '18 at 10:33
1
Ah, makes sense I suppose (bool) == (condition_met) .. +2 skill points to efficiency! thank you :)
– treyBake
Dec 13 '18 at 10:40
7
I definitely agree with @marcelm. As wonderful as this answer looks, it is not immediately obvious what is happening.
– Marie
Dec 13 '18 at 16:18
5
I'd use this only if you really need the performance boost and/or only work with people who'd be able to intuitively read this and come up with this. The other approach maybe longer, but it's much more readable to the average developer.
– Frank Hopkins
Dec 13 '18 at 16:21
1
@afe If you're doing it with the ternary operator, I think an increment (tracker += (src == 'left') == inverse ? -1 : +1;
) is a little clearer
– Charlie Harding
Dec 13 '18 at 17:05
|
show 8 more comments
You could check with the result of the first check.
This is an exclusive OR check.
// typeof inverse === 'boolean'
function handleDirection(src) {
if (src === 'left' === inverse) {
tracker--;
} else {
tracker++;
}
}
The check evaluates the expression in this order (src === 'left') === inverse
:
src === 'left' === inverse
---- first --- returns a boolean value
--------- second --------- take result of former check & compairs it with another boolean
2
^^ only in this special case
– Nina Scholz
Dec 13 '18 at 10:33
1
Ah, makes sense I suppose (bool) == (condition_met) .. +2 skill points to efficiency! thank you :)
– treyBake
Dec 13 '18 at 10:40
7
I definitely agree with @marcelm. As wonderful as this answer looks, it is not immediately obvious what is happening.
– Marie
Dec 13 '18 at 16:18
5
I'd use this only if you really need the performance boost and/or only work with people who'd be able to intuitively read this and come up with this. The other approach maybe longer, but it's much more readable to the average developer.
– Frank Hopkins
Dec 13 '18 at 16:21
1
@afe If you're doing it with the ternary operator, I think an increment (tracker += (src == 'left') == inverse ? -1 : +1;
) is a little clearer
– Charlie Harding
Dec 13 '18 at 17:05
|
show 8 more comments
You could check with the result of the first check.
This is an exclusive OR check.
// typeof inverse === 'boolean'
function handleDirection(src) {
if (src === 'left' === inverse) {
tracker--;
} else {
tracker++;
}
}
The check evaluates the expression in this order (src === 'left') === inverse
:
src === 'left' === inverse
---- first --- returns a boolean value
--------- second --------- take result of former check & compairs it with another boolean
You could check with the result of the first check.
This is an exclusive OR check.
// typeof inverse === 'boolean'
function handleDirection(src) {
if (src === 'left' === inverse) {
tracker--;
} else {
tracker++;
}
}
The check evaluates the expression in this order (src === 'left') === inverse
:
src === 'left' === inverse
---- first --- returns a boolean value
--------- second --------- take result of former check & compairs it with another boolean
edited Dec 17 '18 at 8:44
answered Dec 13 '18 at 10:29
Nina ScholzNina Scholz
187k1596172
187k1596172
2
^^ only in this special case
– Nina Scholz
Dec 13 '18 at 10:33
1
Ah, makes sense I suppose (bool) == (condition_met) .. +2 skill points to efficiency! thank you :)
– treyBake
Dec 13 '18 at 10:40
7
I definitely agree with @marcelm. As wonderful as this answer looks, it is not immediately obvious what is happening.
– Marie
Dec 13 '18 at 16:18
5
I'd use this only if you really need the performance boost and/or only work with people who'd be able to intuitively read this and come up with this. The other approach maybe longer, but it's much more readable to the average developer.
– Frank Hopkins
Dec 13 '18 at 16:21
1
@afe If you're doing it with the ternary operator, I think an increment (tracker += (src == 'left') == inverse ? -1 : +1;
) is a little clearer
– Charlie Harding
Dec 13 '18 at 17:05
|
show 8 more comments
2
^^ only in this special case
– Nina Scholz
Dec 13 '18 at 10:33
1
Ah, makes sense I suppose (bool) == (condition_met) .. +2 skill points to efficiency! thank you :)
– treyBake
Dec 13 '18 at 10:40
7
I definitely agree with @marcelm. As wonderful as this answer looks, it is not immediately obvious what is happening.
– Marie
Dec 13 '18 at 16:18
5
I'd use this only if you really need the performance boost and/or only work with people who'd be able to intuitively read this and come up with this. The other approach maybe longer, but it's much more readable to the average developer.
– Frank Hopkins
Dec 13 '18 at 16:21
1
@afe If you're doing it with the ternary operator, I think an increment (tracker += (src == 'left') == inverse ? -1 : +1;
) is a little clearer
– Charlie Harding
Dec 13 '18 at 17:05
2
2
^^ only in this special case
– Nina Scholz
Dec 13 '18 at 10:33
^^ only in this special case
– Nina Scholz
Dec 13 '18 at 10:33
1
1
Ah, makes sense I suppose (bool) == (condition_met) .. +2 skill points to efficiency! thank you :)
– treyBake
Dec 13 '18 at 10:40
Ah, makes sense I suppose (bool) == (condition_met) .. +2 skill points to efficiency! thank you :)
– treyBake
Dec 13 '18 at 10:40
7
7
I definitely agree with @marcelm. As wonderful as this answer looks, it is not immediately obvious what is happening.
– Marie
Dec 13 '18 at 16:18
I definitely agree with @marcelm. As wonderful as this answer looks, it is not immediately obvious what is happening.
– Marie
Dec 13 '18 at 16:18
5
5
I'd use this only if you really need the performance boost and/or only work with people who'd be able to intuitively read this and come up with this. The other approach maybe longer, but it's much more readable to the average developer.
– Frank Hopkins
Dec 13 '18 at 16:21
I'd use this only if you really need the performance boost and/or only work with people who'd be able to intuitively read this and come up with this. The other approach maybe longer, but it's much more readable to the average developer.
– Frank Hopkins
Dec 13 '18 at 16:21
1
1
@afe If you're doing it with the ternary operator, I think an increment (
tracker += (src == 'left') == inverse ? -1 : +1;
) is a little clearer– Charlie Harding
Dec 13 '18 at 17:05
@afe If you're doing it with the ternary operator, I think an increment (
tracker += (src == 'left') == inverse ? -1 : +1;
) is a little clearer– Charlie Harding
Dec 13 '18 at 17:05
|
show 8 more comments
function handleDirection(src) {
var movement = 1;
if(src === 'left')
movement = -1;
if(inverse)
tracker += movement;
else
tracker -= movement;
}
2
This creates an unnecessary extra variable imo... Usingtracker--
andtracker++
is the correct way to increase and decrease the variable in this case. If it were desired to increase or lower the variable with more than one this might be a good guideline.
– MagicLegend
Dec 13 '18 at 11:01
3
@MagicLegend Actually, I think the variable helps bring "real world" parity to the solution. The other answers focus on "efficiency" which is probably irrelevant in such a simple case. The interpreter doesn't need help reading, but humans do. Although I upvoted, I would go further and give the variable a more meaningful name likeadjustment
ormovement
.
– TheRubberDuck
Dec 13 '18 at 16:41
add a comment |
function handleDirection(src) {
var movement = 1;
if(src === 'left')
movement = -1;
if(inverse)
tracker += movement;
else
tracker -= movement;
}
2
This creates an unnecessary extra variable imo... Usingtracker--
andtracker++
is the correct way to increase and decrease the variable in this case. If it were desired to increase or lower the variable with more than one this might be a good guideline.
– MagicLegend
Dec 13 '18 at 11:01
3
@MagicLegend Actually, I think the variable helps bring "real world" parity to the solution. The other answers focus on "efficiency" which is probably irrelevant in such a simple case. The interpreter doesn't need help reading, but humans do. Although I upvoted, I would go further and give the variable a more meaningful name likeadjustment
ormovement
.
– TheRubberDuck
Dec 13 '18 at 16:41
add a comment |
function handleDirection(src) {
var movement = 1;
if(src === 'left')
movement = -1;
if(inverse)
tracker += movement;
else
tracker -= movement;
}
function handleDirection(src) {
var movement = 1;
if(src === 'left')
movement = -1;
if(inverse)
tracker += movement;
else
tracker -= movement;
}
edited Dec 14 '18 at 15:26
answered Dec 13 '18 at 10:30
AlaysAlays
36610
36610
2
This creates an unnecessary extra variable imo... Usingtracker--
andtracker++
is the correct way to increase and decrease the variable in this case. If it were desired to increase or lower the variable with more than one this might be a good guideline.
– MagicLegend
Dec 13 '18 at 11:01
3
@MagicLegend Actually, I think the variable helps bring "real world" parity to the solution. The other answers focus on "efficiency" which is probably irrelevant in such a simple case. The interpreter doesn't need help reading, but humans do. Although I upvoted, I would go further and give the variable a more meaningful name likeadjustment
ormovement
.
– TheRubberDuck
Dec 13 '18 at 16:41
add a comment |
2
This creates an unnecessary extra variable imo... Usingtracker--
andtracker++
is the correct way to increase and decrease the variable in this case. If it were desired to increase or lower the variable with more than one this might be a good guideline.
– MagicLegend
Dec 13 '18 at 11:01
3
@MagicLegend Actually, I think the variable helps bring "real world" parity to the solution. The other answers focus on "efficiency" which is probably irrelevant in such a simple case. The interpreter doesn't need help reading, but humans do. Although I upvoted, I would go further and give the variable a more meaningful name likeadjustment
ormovement
.
– TheRubberDuck
Dec 13 '18 at 16:41
2
2
This creates an unnecessary extra variable imo... Using
tracker--
and tracker++
is the correct way to increase and decrease the variable in this case. If it were desired to increase or lower the variable with more than one this might be a good guideline.– MagicLegend
Dec 13 '18 at 11:01
This creates an unnecessary extra variable imo... Using
tracker--
and tracker++
is the correct way to increase and decrease the variable in this case. If it were desired to increase or lower the variable with more than one this might be a good guideline.– MagicLegend
Dec 13 '18 at 11:01
3
3
@MagicLegend Actually, I think the variable helps bring "real world" parity to the solution. The other answers focus on "efficiency" which is probably irrelevant in such a simple case. The interpreter doesn't need help reading, but humans do. Although I upvoted, I would go further and give the variable a more meaningful name like
adjustment
or movement
.– TheRubberDuck
Dec 13 '18 at 16:41
@MagicLegend Actually, I think the variable helps bring "real world" parity to the solution. The other answers focus on "efficiency" which is probably irrelevant in such a simple case. The interpreter doesn't need help reading, but humans do. Although I upvoted, I would go further and give the variable a more meaningful name like
adjustment
or movement
.– TheRubberDuck
Dec 13 '18 at 16:41
add a comment |
You can even do it with just one line of Code:
function getDirectionOffset(src) {
tracker += (src === 'left' ? 1 : -1) * (inverse ? -1 : 1);
}
1
Very nice solution!
– Julius Naeumann
Dec 14 '18 at 12:52
add a comment |
You can even do it with just one line of Code:
function getDirectionOffset(src) {
tracker += (src === 'left' ? 1 : -1) * (inverse ? -1 : 1);
}
1
Very nice solution!
– Julius Naeumann
Dec 14 '18 at 12:52
add a comment |
You can even do it with just one line of Code:
function getDirectionOffset(src) {
tracker += (src === 'left' ? 1 : -1) * (inverse ? -1 : 1);
}
You can even do it with just one line of Code:
function getDirectionOffset(src) {
tracker += (src === 'left' ? 1 : -1) * (inverse ? -1 : 1);
}
answered Dec 13 '18 at 12:20
LeuronicsLeuronics
1113
1113
1
Very nice solution!
– Julius Naeumann
Dec 14 '18 at 12:52
add a comment |
1
Very nice solution!
– Julius Naeumann
Dec 14 '18 at 12:52
1
1
Very nice solution!
– Julius Naeumann
Dec 14 '18 at 12:52
Very nice solution!
– Julius Naeumann
Dec 14 '18 at 12:52
add a comment |
This could be simplified to a ternary expression which returns 1
or -1
depending on the state. Then you can just add that to the tracker
.
function handleDirection(src) {
var delta = (src === 'left' && inverse) || (src !== 'left' && !inverse) ? -1 : 1;
tracker += delta;
}
This could then be simplified further using the logic which @NinaScholz pointed out in her answer:
function handleDirection(src) {
var delta = (src === 'left') === inverse ? -1 : 1;
tracker += delta;
}
add a comment |
This could be simplified to a ternary expression which returns 1
or -1
depending on the state. Then you can just add that to the tracker
.
function handleDirection(src) {
var delta = (src === 'left' && inverse) || (src !== 'left' && !inverse) ? -1 : 1;
tracker += delta;
}
This could then be simplified further using the logic which @NinaScholz pointed out in her answer:
function handleDirection(src) {
var delta = (src === 'left') === inverse ? -1 : 1;
tracker += delta;
}
add a comment |
This could be simplified to a ternary expression which returns 1
or -1
depending on the state. Then you can just add that to the tracker
.
function handleDirection(src) {
var delta = (src === 'left' && inverse) || (src !== 'left' && !inverse) ? -1 : 1;
tracker += delta;
}
This could then be simplified further using the logic which @NinaScholz pointed out in her answer:
function handleDirection(src) {
var delta = (src === 'left') === inverse ? -1 : 1;
tracker += delta;
}
This could be simplified to a ternary expression which returns 1
or -1
depending on the state. Then you can just add that to the tracker
.
function handleDirection(src) {
var delta = (src === 'left' && inverse) || (src !== 'left' && !inverse) ? -1 : 1;
tracker += delta;
}
This could then be simplified further using the logic which @NinaScholz pointed out in her answer:
function handleDirection(src) {
var delta = (src === 'left') === inverse ? -1 : 1;
tracker += delta;
}
edited Dec 13 '18 at 10:34
answered Dec 13 '18 at 10:29
Rory McCrossanRory McCrossan
247k29213252
247k29213252
add a comment |
add a comment |
Assuming inverse
is a flag you'd set once, then you don't need to take it into account every time, you can calculate its impact once and just use it as it is, which will cut down your code branches and logic. If you want to change it as you go along, then you might need to separate the logic for the calculation, in order to re-use it.
You can also then extract the movement direction into a self-contained function and your handleDirection
becomes very simple - you calculate the direction you want to go based on src
and the invert
.
let tracker = 0;
//extract logic for the movement offset based on direction
function getDirectionOffset(src) {
return src === 'left' ? 1 : -1;
}
//have a setter for the invert property
function setInverse(isInverse) {
movementModifier = isInverse ? -1 : 1
}
//declare the variable dependent on the inverse property
let movementModifier;
//initialise movementModifier variable
setInverse(false);
function handleDirection(src) {
const offset = getDirectionOffset(src) * movementModifier;
tracker += offset;
}
// usage
setInverse(true);
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
With that said, all this suggests you shouldn't be using a function, or you should be using it differently. You can collect all that functionality in a class or instead have all the information passed around functions, so you don't have globals. Here is a sample object oriented implementation of the concept:
class TrackerMover {
constructor(inverse) {
this.tracker = 0;
this.movementModifier = inverse ? 1 : -1
}
handleDirection(src) {
const offset = this.getDirectionOffset(src) * this.movementModifier;
this.tracker += offset;
}
getDirectionOffset(src) {
return src === 'left' ? -1 : 1;
}
getPosition() {
return this.tracker;
}
}
//usage
const mover = new TrackerMover(true);
mover.handleDirection("left");
mover.handleDirection("left");
mover.handleDirection("right");
console.log(mover.getPosition())
By the way, another alternative is to NOT compute the movement every time. You actually know what is happening every time - in effect, you have a truth table where your inputs are src === left
and inverse
and the outputs are how you modify your tracking.
+--------+------------+--------+
| isLeft | isInverted | Offset |
+--------+------------+--------+
| true | true | -1 |
| true | false | 1 |
| false | true | 1 |
| false | false | -1 |
+--------+------------+--------+
So, you can just put that table in.
let tracker = 0;
let invert = false;
const movementLookupTable = {
"true": { },
"false": { },
}
//it can be initialised as part of the above expression but this is more readable
movementLookupTable[true ][true ] = -1;
movementLookupTable[true ][false] = 1;
movementLookupTable[false][true ] = 1;
movementLookupTable[false][false] = -1;
function handleDirection(src) {
const offset = movementLookupTable[src === "left"][invert];
tracker += offset;
}
// usage
invert = true;
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
In this case it might be an overkill but this approach might be useful if there are more flags (including more values for the flags) and/or end states. For example, maybe you want to introduce four directions, but you don't modify the tracker
value if it's up
or down
.
+-----------+------------+--------+
| direction | isInverted | Offset |
+-----------+------------+--------+
| left | true | -1 |
| left | false | 1 |
| right | true | 1 |
| right | false | -1 |
| up | false | 0 |
| up | true | 0 |
| down | false | 0 |
| down | true | 0 |
+-----------+------------+--------+
As you can see, now it's not just booleans, you can handle any value. Using a table, you also then change invert
to be something like windDirection
, so if the movement is left
and the windDirection
is right
, the result is like what it is now, but you could have direction of left
and wind going left
, so you move further. Or you can move up
and the wind direction is left
so tracker
(at this point the X coordinates) is going to actually be modified.
+-----------+---------------+---------+
| direction | windDirection | OffsetX |
+-----------+---------------+---------+
| left | right | -1 |
| left | up | 1 |
| left | down | 1 |
| left | left | 2 |
| right | up | -1 |
| right | down | -1 |
| right | right | -2 |
| right | left | 1 |
| up | up | 0 |
| up | down | 0 |
| up | left | 1 |
| up | right | -1 |
| down | up | 0 |
| down | down | 0 |
| down | left | 1 |
| down | right | -1 |
+-----------+---------------+---------+
With four directions and four wind directions to take into account the logic can be quite annoying to both read and maintain in the future, while if you only have a lookup table, it's easy and you can easily extend this to even handle diagonals (let's assume they change the value by 0.5
instead of 1
) and your algorithm would not really care as long as you just fetch the values from the table.
add a comment |
Assuming inverse
is a flag you'd set once, then you don't need to take it into account every time, you can calculate its impact once and just use it as it is, which will cut down your code branches and logic. If you want to change it as you go along, then you might need to separate the logic for the calculation, in order to re-use it.
You can also then extract the movement direction into a self-contained function and your handleDirection
becomes very simple - you calculate the direction you want to go based on src
and the invert
.
let tracker = 0;
//extract logic for the movement offset based on direction
function getDirectionOffset(src) {
return src === 'left' ? 1 : -1;
}
//have a setter for the invert property
function setInverse(isInverse) {
movementModifier = isInverse ? -1 : 1
}
//declare the variable dependent on the inverse property
let movementModifier;
//initialise movementModifier variable
setInverse(false);
function handleDirection(src) {
const offset = getDirectionOffset(src) * movementModifier;
tracker += offset;
}
// usage
setInverse(true);
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
With that said, all this suggests you shouldn't be using a function, or you should be using it differently. You can collect all that functionality in a class or instead have all the information passed around functions, so you don't have globals. Here is a sample object oriented implementation of the concept:
class TrackerMover {
constructor(inverse) {
this.tracker = 0;
this.movementModifier = inverse ? 1 : -1
}
handleDirection(src) {
const offset = this.getDirectionOffset(src) * this.movementModifier;
this.tracker += offset;
}
getDirectionOffset(src) {
return src === 'left' ? -1 : 1;
}
getPosition() {
return this.tracker;
}
}
//usage
const mover = new TrackerMover(true);
mover.handleDirection("left");
mover.handleDirection("left");
mover.handleDirection("right");
console.log(mover.getPosition())
By the way, another alternative is to NOT compute the movement every time. You actually know what is happening every time - in effect, you have a truth table where your inputs are src === left
and inverse
and the outputs are how you modify your tracking.
+--------+------------+--------+
| isLeft | isInverted | Offset |
+--------+------------+--------+
| true | true | -1 |
| true | false | 1 |
| false | true | 1 |
| false | false | -1 |
+--------+------------+--------+
So, you can just put that table in.
let tracker = 0;
let invert = false;
const movementLookupTable = {
"true": { },
"false": { },
}
//it can be initialised as part of the above expression but this is more readable
movementLookupTable[true ][true ] = -1;
movementLookupTable[true ][false] = 1;
movementLookupTable[false][true ] = 1;
movementLookupTable[false][false] = -1;
function handleDirection(src) {
const offset = movementLookupTable[src === "left"][invert];
tracker += offset;
}
// usage
invert = true;
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
In this case it might be an overkill but this approach might be useful if there are more flags (including more values for the flags) and/or end states. For example, maybe you want to introduce four directions, but you don't modify the tracker
value if it's up
or down
.
+-----------+------------+--------+
| direction | isInverted | Offset |
+-----------+------------+--------+
| left | true | -1 |
| left | false | 1 |
| right | true | 1 |
| right | false | -1 |
| up | false | 0 |
| up | true | 0 |
| down | false | 0 |
| down | true | 0 |
+-----------+------------+--------+
As you can see, now it's not just booleans, you can handle any value. Using a table, you also then change invert
to be something like windDirection
, so if the movement is left
and the windDirection
is right
, the result is like what it is now, but you could have direction of left
and wind going left
, so you move further. Or you can move up
and the wind direction is left
so tracker
(at this point the X coordinates) is going to actually be modified.
+-----------+---------------+---------+
| direction | windDirection | OffsetX |
+-----------+---------------+---------+
| left | right | -1 |
| left | up | 1 |
| left | down | 1 |
| left | left | 2 |
| right | up | -1 |
| right | down | -1 |
| right | right | -2 |
| right | left | 1 |
| up | up | 0 |
| up | down | 0 |
| up | left | 1 |
| up | right | -1 |
| down | up | 0 |
| down | down | 0 |
| down | left | 1 |
| down | right | -1 |
+-----------+---------------+---------+
With four directions and four wind directions to take into account the logic can be quite annoying to both read and maintain in the future, while if you only have a lookup table, it's easy and you can easily extend this to even handle diagonals (let's assume they change the value by 0.5
instead of 1
) and your algorithm would not really care as long as you just fetch the values from the table.
add a comment |
Assuming inverse
is a flag you'd set once, then you don't need to take it into account every time, you can calculate its impact once and just use it as it is, which will cut down your code branches and logic. If you want to change it as you go along, then you might need to separate the logic for the calculation, in order to re-use it.
You can also then extract the movement direction into a self-contained function and your handleDirection
becomes very simple - you calculate the direction you want to go based on src
and the invert
.
let tracker = 0;
//extract logic for the movement offset based on direction
function getDirectionOffset(src) {
return src === 'left' ? 1 : -1;
}
//have a setter for the invert property
function setInverse(isInverse) {
movementModifier = isInverse ? -1 : 1
}
//declare the variable dependent on the inverse property
let movementModifier;
//initialise movementModifier variable
setInverse(false);
function handleDirection(src) {
const offset = getDirectionOffset(src) * movementModifier;
tracker += offset;
}
// usage
setInverse(true);
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
With that said, all this suggests you shouldn't be using a function, or you should be using it differently. You can collect all that functionality in a class or instead have all the information passed around functions, so you don't have globals. Here is a sample object oriented implementation of the concept:
class TrackerMover {
constructor(inverse) {
this.tracker = 0;
this.movementModifier = inverse ? 1 : -1
}
handleDirection(src) {
const offset = this.getDirectionOffset(src) * this.movementModifier;
this.tracker += offset;
}
getDirectionOffset(src) {
return src === 'left' ? -1 : 1;
}
getPosition() {
return this.tracker;
}
}
//usage
const mover = new TrackerMover(true);
mover.handleDirection("left");
mover.handleDirection("left");
mover.handleDirection("right");
console.log(mover.getPosition())
By the way, another alternative is to NOT compute the movement every time. You actually know what is happening every time - in effect, you have a truth table where your inputs are src === left
and inverse
and the outputs are how you modify your tracking.
+--------+------------+--------+
| isLeft | isInverted | Offset |
+--------+------------+--------+
| true | true | -1 |
| true | false | 1 |
| false | true | 1 |
| false | false | -1 |
+--------+------------+--------+
So, you can just put that table in.
let tracker = 0;
let invert = false;
const movementLookupTable = {
"true": { },
"false": { },
}
//it can be initialised as part of the above expression but this is more readable
movementLookupTable[true ][true ] = -1;
movementLookupTable[true ][false] = 1;
movementLookupTable[false][true ] = 1;
movementLookupTable[false][false] = -1;
function handleDirection(src) {
const offset = movementLookupTable[src === "left"][invert];
tracker += offset;
}
// usage
invert = true;
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
In this case it might be an overkill but this approach might be useful if there are more flags (including more values for the flags) and/or end states. For example, maybe you want to introduce four directions, but you don't modify the tracker
value if it's up
or down
.
+-----------+------------+--------+
| direction | isInverted | Offset |
+-----------+------------+--------+
| left | true | -1 |
| left | false | 1 |
| right | true | 1 |
| right | false | -1 |
| up | false | 0 |
| up | true | 0 |
| down | false | 0 |
| down | true | 0 |
+-----------+------------+--------+
As you can see, now it's not just booleans, you can handle any value. Using a table, you also then change invert
to be something like windDirection
, so if the movement is left
and the windDirection
is right
, the result is like what it is now, but you could have direction of left
and wind going left
, so you move further. Or you can move up
and the wind direction is left
so tracker
(at this point the X coordinates) is going to actually be modified.
+-----------+---------------+---------+
| direction | windDirection | OffsetX |
+-----------+---------------+---------+
| left | right | -1 |
| left | up | 1 |
| left | down | 1 |
| left | left | 2 |
| right | up | -1 |
| right | down | -1 |
| right | right | -2 |
| right | left | 1 |
| up | up | 0 |
| up | down | 0 |
| up | left | 1 |
| up | right | -1 |
| down | up | 0 |
| down | down | 0 |
| down | left | 1 |
| down | right | -1 |
+-----------+---------------+---------+
With four directions and four wind directions to take into account the logic can be quite annoying to both read and maintain in the future, while if you only have a lookup table, it's easy and you can easily extend this to even handle diagonals (let's assume they change the value by 0.5
instead of 1
) and your algorithm would not really care as long as you just fetch the values from the table.
Assuming inverse
is a flag you'd set once, then you don't need to take it into account every time, you can calculate its impact once and just use it as it is, which will cut down your code branches and logic. If you want to change it as you go along, then you might need to separate the logic for the calculation, in order to re-use it.
You can also then extract the movement direction into a self-contained function and your handleDirection
becomes very simple - you calculate the direction you want to go based on src
and the invert
.
let tracker = 0;
//extract logic for the movement offset based on direction
function getDirectionOffset(src) {
return src === 'left' ? 1 : -1;
}
//have a setter for the invert property
function setInverse(isInverse) {
movementModifier = isInverse ? -1 : 1
}
//declare the variable dependent on the inverse property
let movementModifier;
//initialise movementModifier variable
setInverse(false);
function handleDirection(src) {
const offset = getDirectionOffset(src) * movementModifier;
tracker += offset;
}
// usage
setInverse(true);
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
With that said, all this suggests you shouldn't be using a function, or you should be using it differently. You can collect all that functionality in a class or instead have all the information passed around functions, so you don't have globals. Here is a sample object oriented implementation of the concept:
class TrackerMover {
constructor(inverse) {
this.tracker = 0;
this.movementModifier = inverse ? 1 : -1
}
handleDirection(src) {
const offset = this.getDirectionOffset(src) * this.movementModifier;
this.tracker += offset;
}
getDirectionOffset(src) {
return src === 'left' ? -1 : 1;
}
getPosition() {
return this.tracker;
}
}
//usage
const mover = new TrackerMover(true);
mover.handleDirection("left");
mover.handleDirection("left");
mover.handleDirection("right");
console.log(mover.getPosition())
By the way, another alternative is to NOT compute the movement every time. You actually know what is happening every time - in effect, you have a truth table where your inputs are src === left
and inverse
and the outputs are how you modify your tracking.
+--------+------------+--------+
| isLeft | isInverted | Offset |
+--------+------------+--------+
| true | true | -1 |
| true | false | 1 |
| false | true | 1 |
| false | false | -1 |
+--------+------------+--------+
So, you can just put that table in.
let tracker = 0;
let invert = false;
const movementLookupTable = {
"true": { },
"false": { },
}
//it can be initialised as part of the above expression but this is more readable
movementLookupTable[true ][true ] = -1;
movementLookupTable[true ][false] = 1;
movementLookupTable[false][true ] = 1;
movementLookupTable[false][false] = -1;
function handleDirection(src) {
const offset = movementLookupTable[src === "left"][invert];
tracker += offset;
}
// usage
invert = true;
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
In this case it might be an overkill but this approach might be useful if there are more flags (including more values for the flags) and/or end states. For example, maybe you want to introduce four directions, but you don't modify the tracker
value if it's up
or down
.
+-----------+------------+--------+
| direction | isInverted | Offset |
+-----------+------------+--------+
| left | true | -1 |
| left | false | 1 |
| right | true | 1 |
| right | false | -1 |
| up | false | 0 |
| up | true | 0 |
| down | false | 0 |
| down | true | 0 |
+-----------+------------+--------+
As you can see, now it's not just booleans, you can handle any value. Using a table, you also then change invert
to be something like windDirection
, so if the movement is left
and the windDirection
is right
, the result is like what it is now, but you could have direction of left
and wind going left
, so you move further. Or you can move up
and the wind direction is left
so tracker
(at this point the X coordinates) is going to actually be modified.
+-----------+---------------+---------+
| direction | windDirection | OffsetX |
+-----------+---------------+---------+
| left | right | -1 |
| left | up | 1 |
| left | down | 1 |
| left | left | 2 |
| right | up | -1 |
| right | down | -1 |
| right | right | -2 |
| right | left | 1 |
| up | up | 0 |
| up | down | 0 |
| up | left | 1 |
| up | right | -1 |
| down | up | 0 |
| down | down | 0 |
| down | left | 1 |
| down | right | -1 |
+-----------+---------------+---------+
With four directions and four wind directions to take into account the logic can be quite annoying to both read and maintain in the future, while if you only have a lookup table, it's easy and you can easily extend this to even handle diagonals (let's assume they change the value by 0.5
instead of 1
) and your algorithm would not really care as long as you just fetch the values from the table.
let tracker = 0;
//extract logic for the movement offset based on direction
function getDirectionOffset(src) {
return src === 'left' ? 1 : -1;
}
//have a setter for the invert property
function setInverse(isInverse) {
movementModifier = isInverse ? -1 : 1
}
//declare the variable dependent on the inverse property
let movementModifier;
//initialise movementModifier variable
setInverse(false);
function handleDirection(src) {
const offset = getDirectionOffset(src) * movementModifier;
tracker += offset;
}
// usage
setInverse(true);
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
let tracker = 0;
//extract logic for the movement offset based on direction
function getDirectionOffset(src) {
return src === 'left' ? 1 : -1;
}
//have a setter for the invert property
function setInverse(isInverse) {
movementModifier = isInverse ? -1 : 1
}
//declare the variable dependent on the inverse property
let movementModifier;
//initialise movementModifier variable
setInverse(false);
function handleDirection(src) {
const offset = getDirectionOffset(src) * movementModifier;
tracker += offset;
}
// usage
setInverse(true);
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
class TrackerMover {
constructor(inverse) {
this.tracker = 0;
this.movementModifier = inverse ? 1 : -1
}
handleDirection(src) {
const offset = this.getDirectionOffset(src) * this.movementModifier;
this.tracker += offset;
}
getDirectionOffset(src) {
return src === 'left' ? -1 : 1;
}
getPosition() {
return this.tracker;
}
}
//usage
const mover = new TrackerMover(true);
mover.handleDirection("left");
mover.handleDirection("left");
mover.handleDirection("right");
console.log(mover.getPosition())
class TrackerMover {
constructor(inverse) {
this.tracker = 0;
this.movementModifier = inverse ? 1 : -1
}
handleDirection(src) {
const offset = this.getDirectionOffset(src) * this.movementModifier;
this.tracker += offset;
}
getDirectionOffset(src) {
return src === 'left' ? -1 : 1;
}
getPosition() {
return this.tracker;
}
}
//usage
const mover = new TrackerMover(true);
mover.handleDirection("left");
mover.handleDirection("left");
mover.handleDirection("right");
console.log(mover.getPosition())
let tracker = 0;
let invert = false;
const movementLookupTable = {
"true": { },
"false": { },
}
//it can be initialised as part of the above expression but this is more readable
movementLookupTable[true ][true ] = -1;
movementLookupTable[true ][false] = 1;
movementLookupTable[false][true ] = 1;
movementLookupTable[false][false] = -1;
function handleDirection(src) {
const offset = movementLookupTable[src === "left"][invert];
tracker += offset;
}
// usage
invert = true;
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
let tracker = 0;
let invert = false;
const movementLookupTable = {
"true": { },
"false": { },
}
//it can be initialised as part of the above expression but this is more readable
movementLookupTable[true ][true ] = -1;
movementLookupTable[true ][false] = 1;
movementLookupTable[false][true ] = 1;
movementLookupTable[false][false] = -1;
function handleDirection(src) {
const offset = movementLookupTable[src === "left"][invert];
tracker += offset;
}
// usage
invert = true;
handleDirection("left");
handleDirection("left");
handleDirection("right");
console.log(tracker);
edited Dec 13 '18 at 13:20
answered Dec 13 '18 at 11:16
VLAZVLAZ
4,31332134
4,31332134
add a comment |
add a comment |
This has only one conditional, and I find it reads more intuitively than the other answers:
function handleDirection(src) {
if (
((src === 'left') && !inverse) ||
((src === 'right') && inverse)
) {
tracker++;
}
else {
tracker--;
}
}
add a comment |
This has only one conditional, and I find it reads more intuitively than the other answers:
function handleDirection(src) {
if (
((src === 'left') && !inverse) ||
((src === 'right') && inverse)
) {
tracker++;
}
else {
tracker--;
}
}
add a comment |
This has only one conditional, and I find it reads more intuitively than the other answers:
function handleDirection(src) {
if (
((src === 'left') && !inverse) ||
((src === 'right') && inverse)
) {
tracker++;
}
else {
tracker--;
}
}
This has only one conditional, and I find it reads more intuitively than the other answers:
function handleDirection(src) {
if (
((src === 'left') && !inverse) ||
((src === 'right') && inverse)
) {
tracker++;
}
else {
tracker--;
}
}
answered Dec 13 '18 at 16:06
Paul SPaul S
1677
1677
add a comment |
add a comment |
You want to increase the tracker if one of src == left
or inverse
is true but not the other, and decrease it otherwise, which is what the "XOR" ^
operator does :
function handleDirection(src) {
if (src === 'left' ^ inverse) {
tracker++;
} else {
tracker--;
}
}
You can reduce that further by using a ternary expression :
function handleDirection(src) {
tracker += src === 'left' ^ inverse ? 1 : -1;
}
Or if you want to avoid any kind of conditionnal, with implicit casts and "clever" arithmetics :
function handleDirection(src) {
tracker += 1 - 2 * (src === 'right' ^ inverse); // either 1-0=1 or 1-2=-1
}
1
You got the logic backwards, and I hate the third example, but +1 for actually using the operator built for this.
– Jacob Raihle
Dec 13 '18 at 17:08
2
@JacobRaihle thanks, I fixed the backward logic. The quotes around "clever" for the third example are sarcasm quotes, I wouldn't recommend using it unless the only point is to play the smartass.
– Aaron
Dec 13 '18 at 17:18
add a comment |
You want to increase the tracker if one of src == left
or inverse
is true but not the other, and decrease it otherwise, which is what the "XOR" ^
operator does :
function handleDirection(src) {
if (src === 'left' ^ inverse) {
tracker++;
} else {
tracker--;
}
}
You can reduce that further by using a ternary expression :
function handleDirection(src) {
tracker += src === 'left' ^ inverse ? 1 : -1;
}
Or if you want to avoid any kind of conditionnal, with implicit casts and "clever" arithmetics :
function handleDirection(src) {
tracker += 1 - 2 * (src === 'right' ^ inverse); // either 1-0=1 or 1-2=-1
}
1
You got the logic backwards, and I hate the third example, but +1 for actually using the operator built for this.
– Jacob Raihle
Dec 13 '18 at 17:08
2
@JacobRaihle thanks, I fixed the backward logic. The quotes around "clever" for the third example are sarcasm quotes, I wouldn't recommend using it unless the only point is to play the smartass.
– Aaron
Dec 13 '18 at 17:18
add a comment |
You want to increase the tracker if one of src == left
or inverse
is true but not the other, and decrease it otherwise, which is what the "XOR" ^
operator does :
function handleDirection(src) {
if (src === 'left' ^ inverse) {
tracker++;
} else {
tracker--;
}
}
You can reduce that further by using a ternary expression :
function handleDirection(src) {
tracker += src === 'left' ^ inverse ? 1 : -1;
}
Or if you want to avoid any kind of conditionnal, with implicit casts and "clever" arithmetics :
function handleDirection(src) {
tracker += 1 - 2 * (src === 'right' ^ inverse); // either 1-0=1 or 1-2=-1
}
You want to increase the tracker if one of src == left
or inverse
is true but not the other, and decrease it otherwise, which is what the "XOR" ^
operator does :
function handleDirection(src) {
if (src === 'left' ^ inverse) {
tracker++;
} else {
tracker--;
}
}
You can reduce that further by using a ternary expression :
function handleDirection(src) {
tracker += src === 'left' ^ inverse ? 1 : -1;
}
Or if you want to avoid any kind of conditionnal, with implicit casts and "clever" arithmetics :
function handleDirection(src) {
tracker += 1 - 2 * (src === 'right' ^ inverse); // either 1-0=1 or 1-2=-1
}
edited Dec 18 '18 at 13:14
answered Dec 13 '18 at 16:17
AaronAaron
15.9k11636
15.9k11636
1
You got the logic backwards, and I hate the third example, but +1 for actually using the operator built for this.
– Jacob Raihle
Dec 13 '18 at 17:08
2
@JacobRaihle thanks, I fixed the backward logic. The quotes around "clever" for the third example are sarcasm quotes, I wouldn't recommend using it unless the only point is to play the smartass.
– Aaron
Dec 13 '18 at 17:18
add a comment |
1
You got the logic backwards, and I hate the third example, but +1 for actually using the operator built for this.
– Jacob Raihle
Dec 13 '18 at 17:08
2
@JacobRaihle thanks, I fixed the backward logic. The quotes around "clever" for the third example are sarcasm quotes, I wouldn't recommend using it unless the only point is to play the smartass.
– Aaron
Dec 13 '18 at 17:18
1
1
You got the logic backwards, and I hate the third example, but +1 for actually using the operator built for this.
– Jacob Raihle
Dec 13 '18 at 17:08
You got the logic backwards, and I hate the third example, but +1 for actually using the operator built for this.
– Jacob Raihle
Dec 13 '18 at 17:08
2
2
@JacobRaihle thanks, I fixed the backward logic. The quotes around "clever" for the third example are sarcasm quotes, I wouldn't recommend using it unless the only point is to play the smartass.
– Aaron
Dec 13 '18 at 17:18
@JacobRaihle thanks, I fixed the backward logic. The quotes around "clever" for the third example are sarcasm quotes, I wouldn't recommend using it unless the only point is to play the smartass.
– Aaron
Dec 13 '18 at 17:18
add a comment |
You don't need any if
sentence at all. The same operation can be performed by
calculating a positive or negative increment depending on src and inverse
with just the help of ternary operator.
function handleDirection(src) {
tracker += (src == "left" ? 1 : -1) * (inverse ? -1 : 1);
};
Btw. For the sake of efficiency, I would recommend directly use numeric
increments / decrements instead of strings that requires extra processing to be
decoded. You can use constants to achieve the same readability:
Also inverse can be optimised as a numeric value switching between 1 (not
inverted) and -1 (inverted).
const left = 1;
const right = -1;
var direction = 1;
function handleDirection(src) {
tracker += src * direction;
}
function reverse() { // (Example)
direction = direction * -1;
}
...even if "right" and "left" keywords comes from some sort of textual user
input, you can simply translate them from a dictionary:
const steps = {
left = 1;
right = -1;
};
function handleDirection(src) {
tracker += steps[src] * direction;
}
add a comment |
You don't need any if
sentence at all. The same operation can be performed by
calculating a positive or negative increment depending on src and inverse
with just the help of ternary operator.
function handleDirection(src) {
tracker += (src == "left" ? 1 : -1) * (inverse ? -1 : 1);
};
Btw. For the sake of efficiency, I would recommend directly use numeric
increments / decrements instead of strings that requires extra processing to be
decoded. You can use constants to achieve the same readability:
Also inverse can be optimised as a numeric value switching between 1 (not
inverted) and -1 (inverted).
const left = 1;
const right = -1;
var direction = 1;
function handleDirection(src) {
tracker += src * direction;
}
function reverse() { // (Example)
direction = direction * -1;
}
...even if "right" and "left" keywords comes from some sort of textual user
input, you can simply translate them from a dictionary:
const steps = {
left = 1;
right = -1;
};
function handleDirection(src) {
tracker += steps[src] * direction;
}
add a comment |
You don't need any if
sentence at all. The same operation can be performed by
calculating a positive or negative increment depending on src and inverse
with just the help of ternary operator.
function handleDirection(src) {
tracker += (src == "left" ? 1 : -1) * (inverse ? -1 : 1);
};
Btw. For the sake of efficiency, I would recommend directly use numeric
increments / decrements instead of strings that requires extra processing to be
decoded. You can use constants to achieve the same readability:
Also inverse can be optimised as a numeric value switching between 1 (not
inverted) and -1 (inverted).
const left = 1;
const right = -1;
var direction = 1;
function handleDirection(src) {
tracker += src * direction;
}
function reverse() { // (Example)
direction = direction * -1;
}
...even if "right" and "left" keywords comes from some sort of textual user
input, you can simply translate them from a dictionary:
const steps = {
left = 1;
right = -1;
};
function handleDirection(src) {
tracker += steps[src] * direction;
}
You don't need any if
sentence at all. The same operation can be performed by
calculating a positive or negative increment depending on src and inverse
with just the help of ternary operator.
function handleDirection(src) {
tracker += (src == "left" ? 1 : -1) * (inverse ? -1 : 1);
};
Btw. For the sake of efficiency, I would recommend directly use numeric
increments / decrements instead of strings that requires extra processing to be
decoded. You can use constants to achieve the same readability:
Also inverse can be optimised as a numeric value switching between 1 (not
inverted) and -1 (inverted).
const left = 1;
const right = -1;
var direction = 1;
function handleDirection(src) {
tracker += src * direction;
}
function reverse() { // (Example)
direction = direction * -1;
}
...even if "right" and "left" keywords comes from some sort of textual user
input, you can simply translate them from a dictionary:
const steps = {
left = 1;
right = -1;
};
function handleDirection(src) {
tracker += steps[src] * direction;
}
answered Dec 28 '18 at 13:37
bitifetbitifet
2,538723
2,538723
add a comment |
add a comment |
You can use short circuiting syntax or ternary operators
// by using short circuiting
function handleDirection(src) {
if (src == 'left') tracker = inverse && tracker-1 || tracker +1
else tracker = inverse && tracker+1 || tracker -1
}
// by using ternary operator
function handleDirection(src) {
if (src == 'left') tracker = inverse ? tracker-1 : tracker +1
else tracker = inverse ? tracker+1 : tracker -1
}
add a comment |
You can use short circuiting syntax or ternary operators
// by using short circuiting
function handleDirection(src) {
if (src == 'left') tracker = inverse && tracker-1 || tracker +1
else tracker = inverse && tracker+1 || tracker -1
}
// by using ternary operator
function handleDirection(src) {
if (src == 'left') tracker = inverse ? tracker-1 : tracker +1
else tracker = inverse ? tracker+1 : tracker -1
}
add a comment |
You can use short circuiting syntax or ternary operators
// by using short circuiting
function handleDirection(src) {
if (src == 'left') tracker = inverse && tracker-1 || tracker +1
else tracker = inverse && tracker+1 || tracker -1
}
// by using ternary operator
function handleDirection(src) {
if (src == 'left') tracker = inverse ? tracker-1 : tracker +1
else tracker = inverse ? tracker+1 : tracker -1
}
You can use short circuiting syntax or ternary operators
// by using short circuiting
function handleDirection(src) {
if (src == 'left') tracker = inverse && tracker-1 || tracker +1
else tracker = inverse && tracker+1 || tracker -1
}
// by using ternary operator
function handleDirection(src) {
if (src == 'left') tracker = inverse ? tracker-1 : tracker +1
else tracker = inverse ? tracker+1 : tracker -1
}
answered Dec 13 '18 at 10:34
Komal BansalKomal Bansal
27813
27813
add a comment |
add a comment |
I dislike elses and try to avoid nesting if possible. I think this conveys the idea of inverse
in a more natural way:
function handleDirection(src)
{
let change = 1;
if ('right' == src)
change = -1;
if (inverse)
change = -change;
tracker += change;
}
add a comment |
I dislike elses and try to avoid nesting if possible. I think this conveys the idea of inverse
in a more natural way:
function handleDirection(src)
{
let change = 1;
if ('right' == src)
change = -1;
if (inverse)
change = -change;
tracker += change;
}
add a comment |
I dislike elses and try to avoid nesting if possible. I think this conveys the idea of inverse
in a more natural way:
function handleDirection(src)
{
let change = 1;
if ('right' == src)
change = -1;
if (inverse)
change = -change;
tracker += change;
}
I dislike elses and try to avoid nesting if possible. I think this conveys the idea of inverse
in a more natural way:
function handleDirection(src)
{
let change = 1;
if ('right' == src)
change = -1;
if (inverse)
change = -change;
tracker += change;
}
answered Dec 13 '18 at 16:29
DžurisDžuris
4011127
4011127
add a comment |
add a comment |
Right now you are comparing on strings, which I wouldn't advise. If for example you use 'Left' instead of 'left' it will fail the first if statement. Perhaps a boolean could be of use here, since you can guarantee it only has two states.
The if statements inside can be compressed via conditional operators.
Perhaps something like this is what you are looking for:
function handleDirection(src) {
if (src) {
inverse ? tracker-- : tracker++;
} else {
inverse ? tracker++ : tracker--;
}
}
See: https://jsfiddle.net/9zr4f3nv/
3
Your two branches of the if statement are identical: one of them needs to be reversed
– Charlie Harding
Dec 13 '18 at 17:03
Oopsie! You're right hehe. Corrected!
– MagicLegend
Dec 14 '18 at 17:06
add a comment |
Right now you are comparing on strings, which I wouldn't advise. If for example you use 'Left' instead of 'left' it will fail the first if statement. Perhaps a boolean could be of use here, since you can guarantee it only has two states.
The if statements inside can be compressed via conditional operators.
Perhaps something like this is what you are looking for:
function handleDirection(src) {
if (src) {
inverse ? tracker-- : tracker++;
} else {
inverse ? tracker++ : tracker--;
}
}
See: https://jsfiddle.net/9zr4f3nv/
3
Your two branches of the if statement are identical: one of them needs to be reversed
– Charlie Harding
Dec 13 '18 at 17:03
Oopsie! You're right hehe. Corrected!
– MagicLegend
Dec 14 '18 at 17:06
add a comment |
Right now you are comparing on strings, which I wouldn't advise. If for example you use 'Left' instead of 'left' it will fail the first if statement. Perhaps a boolean could be of use here, since you can guarantee it only has two states.
The if statements inside can be compressed via conditional operators.
Perhaps something like this is what you are looking for:
function handleDirection(src) {
if (src) {
inverse ? tracker-- : tracker++;
} else {
inverse ? tracker++ : tracker--;
}
}
See: https://jsfiddle.net/9zr4f3nv/
Right now you are comparing on strings, which I wouldn't advise. If for example you use 'Left' instead of 'left' it will fail the first if statement. Perhaps a boolean could be of use here, since you can guarantee it only has two states.
The if statements inside can be compressed via conditional operators.
Perhaps something like this is what you are looking for:
function handleDirection(src) {
if (src) {
inverse ? tracker-- : tracker++;
} else {
inverse ? tracker++ : tracker--;
}
}
See: https://jsfiddle.net/9zr4f3nv/
edited Dec 14 '18 at 17:06
answered Dec 13 '18 at 10:32
MagicLegendMagicLegend
104212
104212
3
Your two branches of the if statement are identical: one of them needs to be reversed
– Charlie Harding
Dec 13 '18 at 17:03
Oopsie! You're right hehe. Corrected!
– MagicLegend
Dec 14 '18 at 17:06
add a comment |
3
Your two branches of the if statement are identical: one of them needs to be reversed
– Charlie Harding
Dec 13 '18 at 17:03
Oopsie! You're right hehe. Corrected!
– MagicLegend
Dec 14 '18 at 17:06
3
3
Your two branches of the if statement are identical: one of them needs to be reversed
– Charlie Harding
Dec 13 '18 at 17:03
Your two branches of the if statement are identical: one of them needs to be reversed
– Charlie Harding
Dec 13 '18 at 17:03
Oopsie! You're right hehe. Corrected!
– MagicLegend
Dec 14 '18 at 17:06
Oopsie! You're right hehe. Corrected!
– MagicLegend
Dec 14 '18 at 17:06
add a comment |
You could use an 2 dimensional array type data structure from js and store the desired outcomes at index sec and inverse. Or JSON.
add a comment |
You could use an 2 dimensional array type data structure from js and store the desired outcomes at index sec and inverse. Or JSON.
add a comment |
You could use an 2 dimensional array type data structure from js and store the desired outcomes at index sec and inverse. Or JSON.
You could use an 2 dimensional array type data structure from js and store the desired outcomes at index sec and inverse. Or JSON.
answered Dec 13 '18 at 16:58
marshal craftmarshal craft
303314
303314
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53759675%2fsimplify-an-if-else-statement%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
9
There's now a range of answers - one thing to bear in mind with this sort of thing is maintainability, that includes whether you yourself will understand what this code does next week. Make sure you pick a form of logic that is clear to you what it's doing at a glance - if that's the long form in your original question, stick with it.
– James Thorpe
Dec 13 '18 at 10:31
14
I'm voting to close this question as off-topic because it belongs to codereview.stackexchange.com
– Gabriele Petrioli
Dec 13 '18 at 10:33
10
Side note: your function uses 3 variables (
src
,inverse
andtracker
) but it has only 1 parameter (src
) and no return value. For that reason it would not pass my code review, regardless of how you structure theif
s....– Peter B
Dec 13 '18 at 10:34
1
@PeterB I'd generally agree, but it's worth noting that context is key. If this were a method in an object, then it might be fine. This could be manipulating some sort of cursor (
tracker
) via commands ("left"
/"right"
), the object itself has a flag that it would be moved in the opposite direction (invert
). However, as a free-floating function, that's indeed bad, as you're manipulating some not necessarily related global states.– VLAZ
Dec 13 '18 at 10:44
1
Thanks all—it is a free-floating function currently; the main purpose of me asking this question is to capture the most efficient method of writing this conditional. I often find that it's the simpler things like this that trip me up, so asking this question now before I delve further is useful. The answers below are all interesting approaches which I must test.
– Rebecca O'Sullivan
Dec 13 '18 at 11:01