Putting a 2D region plot under a 3D plot
3
$begingroup$
I am trying to plot this 3D function over a hexagonal region:
a1 = Sqrt[3] {1, 0};
a2 = Sqrt[3] {1/2, Sqrt[3]/2};
k = {kx, ky};
S = 1 + Exp[I k. a2] + Exp[I k.(a2 - a1)];
EE = Abs[S]
R = 4 Pi/(3 Sqrt[3]);
ep = Plot3D[{EE, -EE}, {kx, ky} [Element] RegularPolygon[R, 6], Axes -> False, Boxed -> False, AspectRatio -> 2]
This works fine, but I would also like to draw the region under the 3D graph, something like:
bz = Graphics[RegularPolygon[R, 6]];
or
bz = RegionPlot[RegularPolygon[R, 6]];
However, using
Show[ep, bz]
doesn't work. I have found a few similar questions but they mostly seem to be about contours, I didn't know how to extend this for something as simple as a regular polygon.
plotting regions
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
asked 7 hours ago
AshAsh
235
$endgroup$
add a comment |
3
$begingroup$
I am trying to plot this 3D function over a hexagonal region:
a1 = Sqrt[3] {1, 0};
a2 = Sqrt[3] {1/2, Sqrt[3]/2};
k = {kx, ky};
S = 1 + Exp[I k. a2] + Exp[I k.(a2 - a1)];
EE = Abs[S]
R = 4 Pi/(3 Sqrt[3]);
ep = Plot3D[{EE, -EE}, {kx, ky} [Element] RegularPolygon[R, 6], Axes -> False, Boxed -> False, AspectRatio -> 2]
This works fine, but I would also like to draw the region under the 3D graph, something like:
bz = Graphics[RegularPolygon[R, 6]];
or
bz = RegionPlot[RegularPolygon[R, 6]];
However, using
Show[ep, bz]
doesn't work. I have found a few similar questions but they mostly seem to be about contours, I didn't know how to extend this for something as simple as a regular polygon.
plotting regions
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
asked 7 hours ago
AshAsh
235
$endgroup$
$begingroup$
do you want you Polygon flat under the region of 3D !?
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
Try This p = Graphics3D[Polygon[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}]]
$endgroup$
– Alrubaie
6 hours ago
add a comment |
3
3
3
$begingroup$
I am trying to plot this 3D function over a hexagonal region:
a1 = Sqrt[3] {1, 0};
a2 = Sqrt[3] {1/2, Sqrt[3]/2};
k = {kx, ky};
S = 1 + Exp[I k. a2] + Exp[I k.(a2 - a1)];
EE = Abs[S]
R = 4 Pi/(3 Sqrt[3]);
ep = Plot3D[{EE, -EE}, {kx, ky} [Element] RegularPolygon[R, 6], Axes -> False, Boxed -> False, AspectRatio -> 2]
This works fine, but I would also like to draw the region under the 3D graph, something like:
bz = Graphics[RegularPolygon[R, 6]];
or
bz = RegionPlot[RegularPolygon[R, 6]];
However, using
Show[ep, bz]
doesn't work. I have found a few similar questions but they mostly seem to be about contours, I didn't know how to extend this for something as simple as a regular polygon.
plotting regions
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
asked 7 hours ago
AshAsh
235
$endgroup$
I am trying to plot this 3D function over a hexagonal region:
a1 = Sqrt[3] {1, 0};
a2 = Sqrt[3] {1/2, Sqrt[3]/2};
k = {kx, ky};
S = 1 + Exp[I k. a2] + Exp[I k.(a2 - a1)];
EE = Abs[S]
R = 4 Pi/(3 Sqrt[3]);
ep = Plot3D[{EE, -EE}, {kx, ky} [Element] RegularPolygon[R, 6], Axes -> False, Boxed -> False, AspectRatio -> 2]
This works fine, but I would also like to draw the region under the 3D graph, something like:
bz = Graphics[RegularPolygon[R, 6]];
or
bz = RegionPlot[RegularPolygon[R, 6]];
However, using
Show[ep, bz]
doesn't work. I have found a few similar questions but they mostly seem to be about contours, I didn't know how to extend this for something as simple as a regular polygon.
plotting regions
plotting regions
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
asked 7 hours ago
AshAsh
235
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
asked 7 hours ago
AshAsh
235
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
edited 1 hour ago
J. M. is slightly pensive♦
98.7k10310467
98.7k10310467
asked 7 hours ago
AshAsh
235
asked 7 hours ago
AshAsh
235
asked 7 hours ago
AshAsh
235
235
$begingroup$
do you want you Polygon flat under the region of 3D !?
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
Try This p = Graphics3D[Polygon[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}]]
$endgroup$
– Alrubaie
6 hours ago
add a comment |
$begingroup$
do you want you Polygon flat under the region of 3D !?
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
Try This p = Graphics3D[Polygon[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}]]
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
do you want you Polygon flat under the region of 3D !?
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
do you want you Polygon flat under the region of 3D !?
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
Try This p = Graphics3D[Polygon[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}]]
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
Try This p = Graphics3D[Polygon[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}]]
$endgroup$
– Alrubaie
6 hours ago
add a comment |
1 Answer
1
active
oldest
votes
5
$begingroup$
Try this:
region = Graphics3D[Polygon[CirclePoints[R, 6] /. {x_, y_} :> {x, y, -3}]];
Show[ep,region]
answered 6 hours ago
MarcoBMarcoB
38k556114
$endgroup$
$begingroup$
Works perfectly, thank you!
$endgroup$
– Ash
6 hours ago
$begingroup$
@Ash You are very welcome! Thank you for the accept as well!
$endgroup$
– MarcoB
6 hours ago
$begingroup$
That's nice! WhatAspectRatiodid you use?
$endgroup$
– mjw
5 hours ago
$begingroup$
@mjw Thank you! The aspect ratio is inherited fromep, which was in the OP's original code; they had set it to $2$.
$endgroup$
– MarcoB
4 hours ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "387"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194130%2fputting-a-2d-region-plot-under-a-3d-plot%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
5
$begingroup$
Try this:
region = Graphics3D[Polygon[CirclePoints[R, 6] /. {x_, y_} :> {x, y, -3}]];
Show[ep,region]
answered 6 hours ago
MarcoBMarcoB
38k556114
$endgroup$
$begingroup$
Works perfectly, thank you!
$endgroup$
– Ash
6 hours ago
$begingroup$
@Ash You are very welcome! Thank you for the accept as well!
$endgroup$
– MarcoB
6 hours ago
$begingroup$
That's nice! WhatAspectRatiodid you use?
$endgroup$
– mjw
5 hours ago
$begingroup$
@mjw Thank you! The aspect ratio is inherited fromep, which was in the OP's original code; they had set it to $2$.
$endgroup$
– MarcoB
4 hours ago
add a comment |
5
$begingroup$
Try this:
region = Graphics3D[Polygon[CirclePoints[R, 6] /. {x_, y_} :> {x, y, -3}]];
Show[ep,region]
answered 6 hours ago
MarcoBMarcoB
38k556114
$endgroup$
$begingroup$
Works perfectly, thank you!
$endgroup$
– Ash
6 hours ago
$begingroup$
@Ash You are very welcome! Thank you for the accept as well!
$endgroup$
– MarcoB
6 hours ago
$begingroup$
That's nice! WhatAspectRatiodid you use?
$endgroup$
– mjw
5 hours ago
$begingroup$
@mjw Thank you! The aspect ratio is inherited fromep, which was in the OP's original code; they had set it to $2$.
$endgroup$
– MarcoB
4 hours ago
add a comment |
5
5
5
$begingroup$
Try this:
region = Graphics3D[Polygon[CirclePoints[R, 6] /. {x_, y_} :> {x, y, -3}]];
Show[ep,region]
answered 6 hours ago
MarcoBMarcoB
38k556114
$endgroup$
Try this:
region = Graphics3D[Polygon[CirclePoints[R, 6] /. {x_, y_} :> {x, y, -3}]];
Show[ep,region]
answered 6 hours ago
MarcoBMarcoB
38k556114
answered 6 hours ago
MarcoBMarcoB
38k556114
answered 6 hours ago
MarcoBMarcoB
38k556114
answered 6 hours ago
MarcoBMarcoB
38k556114
38k556114
$begingroup$
Works perfectly, thank you!
$endgroup$
– Ash
6 hours ago
$begingroup$
@Ash You are very welcome! Thank you for the accept as well!
$endgroup$
– MarcoB
6 hours ago
$begingroup$
That's nice! WhatAspectRatiodid you use?
$endgroup$
– mjw
5 hours ago
$begingroup$
@mjw Thank you! The aspect ratio is inherited fromep, which was in the OP's original code; they had set it to $2$.
$endgroup$
– MarcoB
4 hours ago
add a comment |
$begingroup$
Works perfectly, thank you!
$endgroup$
– Ash
6 hours ago
$begingroup$
@Ash You are very welcome! Thank you for the accept as well!
$endgroup$
– MarcoB
6 hours ago
$begingroup$
That's nice! WhatAspectRatiodid you use?
$endgroup$
– mjw
5 hours ago
$begingroup$
@mjw Thank you! The aspect ratio is inherited fromep, which was in the OP's original code; they had set it to $2$.
$endgroup$
– MarcoB
4 hours ago
$begingroup$
Works perfectly, thank you!
$endgroup$
– Ash
6 hours ago
$begingroup$
Works perfectly, thank you!
$endgroup$
– Ash
6 hours ago
$begingroup$
@Ash You are very welcome! Thank you for the accept as well!
$endgroup$
– MarcoB
6 hours ago
$begingroup$
@Ash You are very welcome! Thank you for the accept as well!
$endgroup$
– MarcoB
6 hours ago
$begingroup$
That's nice! What
AspectRatio did you use?$endgroup$
– mjw
5 hours ago
$begingroup$
That's nice! What
AspectRatio did you use?$endgroup$
– mjw
5 hours ago
$begingroup$
@mjw Thank you! The aspect ratio is inherited from
ep, which was in the OP's original code; they had set it to $2$.$endgroup$
– MarcoB
4 hours ago
$begingroup$
@mjw Thank you! The aspect ratio is inherited from
ep, which was in the OP's original code; they had set it to $2$.$endgroup$
– MarcoB
4 hours ago
add a comment |
draft saved
draft discarded
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194130%2fputting-a-2d-region-plot-under-a-3d-plot%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
do you want you Polygon flat under the region of 3D !?
$endgroup$
– Alrubaie
6 hours ago
$begingroup$
Try This p = Graphics3D[Polygon[{{1, 0, 0}, {0, 1, 0}, {0, 0, 1}}]]
$endgroup$
– Alrubaie
6 hours ago