homeomorphic to [-1,1]
It's written that one point compactification of $[−1,1]setminus{0}$ is homeomorphic to $[-1,1]$ in my topology book. I want to know why they are homeomorphic.
general-topology
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It's written that one point compactification of $[−1,1]setminus{0}$ is homeomorphic to $[-1,1]$ in my topology book. I want to know why they are homeomorphic.
general-topology
add a comment |
It's written that one point compactification of $[−1,1]setminus{0}$ is homeomorphic to $[-1,1]$ in my topology book. I want to know why they are homeomorphic.
general-topology
It's written that one point compactification of $[−1,1]setminus{0}$ is homeomorphic to $[-1,1]$ in my topology book. I want to know why they are homeomorphic.
general-topology
general-topology
edited Nov 25 at 9:39
asked Nov 25 at 7:45
dlfjsemf
968
968
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2 Answers
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Fact:
If $X$ is locally compact Hausdorff and we have a compact Hausdorff space $Y$ such
that $X subseteq Y$ and $Ysetminus X$ consists of a single point $p$, then $Y$ is homeomorphic to the one-point compactification $alpha X$ of $X$.
Apply this to $X=[-1,1]setminus{0}$ and $Y=[-1,1]$.
To prove the fact, let $alpha X = X cup {infty}$ in its usual topology.
Check that $f: Y to alpha X$ defined by $f(x)=x$ for $x in X$ and $f(infty) = p$ is a continuous bijection and then compactness (and Hausdorffness) makes this a homeomorphism.
A slight generalisation of the fact: if $Y$ is compact Hausdorff and for some point $p in Y$ we have that $Ysetminus{p}$ is homeomorphic to $X$, then $Y$ is homeomorphic to the one-point compactifcation of $X$. I.e. if $Y$ is compact and one point larger than something homeomorphic to $X$, it must be its one-point compactification. It shows this compactification is essentially unique.
add a comment |
No, they are not homeomorphic, the second set is connected, but not the first.
It's written that one compactification of $[-1,1]setminus{0}$ is homeomorphic to [-1,1] in my topology book. Is it wrong?
– dlfjsemf
Nov 25 at 8:01
@dlfjsemf no it's correct.
– Henno Brandsma
Nov 25 at 8:35
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Fact:
If $X$ is locally compact Hausdorff and we have a compact Hausdorff space $Y$ such
that $X subseteq Y$ and $Ysetminus X$ consists of a single point $p$, then $Y$ is homeomorphic to the one-point compactification $alpha X$ of $X$.
Apply this to $X=[-1,1]setminus{0}$ and $Y=[-1,1]$.
To prove the fact, let $alpha X = X cup {infty}$ in its usual topology.
Check that $f: Y to alpha X$ defined by $f(x)=x$ for $x in X$ and $f(infty) = p$ is a continuous bijection and then compactness (and Hausdorffness) makes this a homeomorphism.
A slight generalisation of the fact: if $Y$ is compact Hausdorff and for some point $p in Y$ we have that $Ysetminus{p}$ is homeomorphic to $X$, then $Y$ is homeomorphic to the one-point compactifcation of $X$. I.e. if $Y$ is compact and one point larger than something homeomorphic to $X$, it must be its one-point compactification. It shows this compactification is essentially unique.
add a comment |
Fact:
If $X$ is locally compact Hausdorff and we have a compact Hausdorff space $Y$ such
that $X subseteq Y$ and $Ysetminus X$ consists of a single point $p$, then $Y$ is homeomorphic to the one-point compactification $alpha X$ of $X$.
Apply this to $X=[-1,1]setminus{0}$ and $Y=[-1,1]$.
To prove the fact, let $alpha X = X cup {infty}$ in its usual topology.
Check that $f: Y to alpha X$ defined by $f(x)=x$ for $x in X$ and $f(infty) = p$ is a continuous bijection and then compactness (and Hausdorffness) makes this a homeomorphism.
A slight generalisation of the fact: if $Y$ is compact Hausdorff and for some point $p in Y$ we have that $Ysetminus{p}$ is homeomorphic to $X$, then $Y$ is homeomorphic to the one-point compactifcation of $X$. I.e. if $Y$ is compact and one point larger than something homeomorphic to $X$, it must be its one-point compactification. It shows this compactification is essentially unique.
add a comment |
Fact:
If $X$ is locally compact Hausdorff and we have a compact Hausdorff space $Y$ such
that $X subseteq Y$ and $Ysetminus X$ consists of a single point $p$, then $Y$ is homeomorphic to the one-point compactification $alpha X$ of $X$.
Apply this to $X=[-1,1]setminus{0}$ and $Y=[-1,1]$.
To prove the fact, let $alpha X = X cup {infty}$ in its usual topology.
Check that $f: Y to alpha X$ defined by $f(x)=x$ for $x in X$ and $f(infty) = p$ is a continuous bijection and then compactness (and Hausdorffness) makes this a homeomorphism.
A slight generalisation of the fact: if $Y$ is compact Hausdorff and for some point $p in Y$ we have that $Ysetminus{p}$ is homeomorphic to $X$, then $Y$ is homeomorphic to the one-point compactifcation of $X$. I.e. if $Y$ is compact and one point larger than something homeomorphic to $X$, it must be its one-point compactification. It shows this compactification is essentially unique.
Fact:
If $X$ is locally compact Hausdorff and we have a compact Hausdorff space $Y$ such
that $X subseteq Y$ and $Ysetminus X$ consists of a single point $p$, then $Y$ is homeomorphic to the one-point compactification $alpha X$ of $X$.
Apply this to $X=[-1,1]setminus{0}$ and $Y=[-1,1]$.
To prove the fact, let $alpha X = X cup {infty}$ in its usual topology.
Check that $f: Y to alpha X$ defined by $f(x)=x$ for $x in X$ and $f(infty) = p$ is a continuous bijection and then compactness (and Hausdorffness) makes this a homeomorphism.
A slight generalisation of the fact: if $Y$ is compact Hausdorff and for some point $p in Y$ we have that $Ysetminus{p}$ is homeomorphic to $X$, then $Y$ is homeomorphic to the one-point compactifcation of $X$. I.e. if $Y$ is compact and one point larger than something homeomorphic to $X$, it must be its one-point compactification. It shows this compactification is essentially unique.
answered Nov 25 at 8:41
Henno Brandsma
104k346113
104k346113
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add a comment |
No, they are not homeomorphic, the second set is connected, but not the first.
It's written that one compactification of $[-1,1]setminus{0}$ is homeomorphic to [-1,1] in my topology book. Is it wrong?
– dlfjsemf
Nov 25 at 8:01
@dlfjsemf no it's correct.
– Henno Brandsma
Nov 25 at 8:35
add a comment |
No, they are not homeomorphic, the second set is connected, but not the first.
It's written that one compactification of $[-1,1]setminus{0}$ is homeomorphic to [-1,1] in my topology book. Is it wrong?
– dlfjsemf
Nov 25 at 8:01
@dlfjsemf no it's correct.
– Henno Brandsma
Nov 25 at 8:35
add a comment |
No, they are not homeomorphic, the second set is connected, but not the first.
No, they are not homeomorphic, the second set is connected, but not the first.
answered Nov 25 at 7:48
Tsemo Aristide
55.4k11444
55.4k11444
It's written that one compactification of $[-1,1]setminus{0}$ is homeomorphic to [-1,1] in my topology book. Is it wrong?
– dlfjsemf
Nov 25 at 8:01
@dlfjsemf no it's correct.
– Henno Brandsma
Nov 25 at 8:35
add a comment |
It's written that one compactification of $[-1,1]setminus{0}$ is homeomorphic to [-1,1] in my topology book. Is it wrong?
– dlfjsemf
Nov 25 at 8:01
@dlfjsemf no it's correct.
– Henno Brandsma
Nov 25 at 8:35
It's written that one compactification of $[-1,1]setminus{0}$ is homeomorphic to [-1,1] in my topology book. Is it wrong?
– dlfjsemf
Nov 25 at 8:01
It's written that one compactification of $[-1,1]setminus{0}$ is homeomorphic to [-1,1] in my topology book. Is it wrong?
– dlfjsemf
Nov 25 at 8:01
@dlfjsemf no it's correct.
– Henno Brandsma
Nov 25 at 8:35
@dlfjsemf no it's correct.
– Henno Brandsma
Nov 25 at 8:35
add a comment |
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