On $xy$ vs $ab$ where $2xy+x+y+1 = 2ab+a+b$
Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.
Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.
I was wondering what we can say about the relation between $x*y$ and $a*b$.
As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.
Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?
elementary-number-theory
add a comment |
Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.
Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.
I was wondering what we can say about the relation between $x*y$ and $a*b$.
As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.
Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?
elementary-number-theory
add a comment |
Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.
Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.
I was wondering what we can say about the relation between $x*y$ and $a*b$.
As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.
Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?
elementary-number-theory
Let us suppose that $2xy+x+y = n$, where $x,y,n$ are positive integers and $x≥2$ and $y≥2$.
Let us choose x and y, so that $n+1 = 2ab+a+b$ , where $a, b$ are also positive integer numbers.
I was wondering what we can say about the relation between $x*y$ and $a*b$.
As $n$ and $n+1$ are very close, and as $xy > x+y$, there is likely to be a maximal difference between $xy$ and $ab$.
Am I right to suppose that to fulfil the equations, $xy = ab$ or $xy + 1 = ab$ ? So this maximum difference is 1 ?
elementary-number-theory
elementary-number-theory
asked Nov 25 at 20:07
Tilsight
135
135
add a comment |
add a comment |
3 Answers
3
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oldest
votes
apparently not
a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10
Thank you, Will.
– Tilsight
Nov 25 at 20:41
Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
– Tilsight
Nov 25 at 20:43
add a comment |
Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,
so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.
add a comment |
Not bounded at all.
With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
$$ x = frac{2(a-3)(a+1)}{5} $$
With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
$$ x = frac{2a^2 -2a-5}{5} $$
a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642
Thanks guys. Respect 😀
– Tilsight
Nov 25 at 20:57
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
apparently not
a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10
Thank you, Will.
– Tilsight
Nov 25 at 20:41
Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
– Tilsight
Nov 25 at 20:43
add a comment |
apparently not
a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10
Thank you, Will.
– Tilsight
Nov 25 at 20:41
Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
– Tilsight
Nov 25 at 20:43
add a comment |
apparently not
a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10
apparently not
a: 4 b: 1 x: 2 y: 2 |a*b - x*y| : 0
a: 5 b: 3 x: 7 y: 2 |a*b - x*y| : 1
a: 5 b: 5 x: 8 y: 3 |a*b - x*y| : 1
a: 6 b: 2 x: 4 y: 3 |a*b - x*y| : 0
a: 6 b: 4 x: 11 y: 2 |a*b - x*y| : 2
a: 7 b: 4 x: 9 y: 3 |a*b - x*y| : 1
a: 8 b: 1 x: 3 y: 3 |a*b - x*y| : 1
a: 8 b: 3 x: 6 y: 4 |a*b - x*y| : 0
a: 8 b: 5 x: 18 y: 2 |a*b - x*y| : 4
a: 8 b: 7 x: 11 y: 5 |a*b - x*y| : 1
a: 8 b: 8 x: 20 y: 3 |a*b - x*y| : 4
a: 9 b: 1 x: 5 y: 2 |a*b - x*y| : 1
a: 9 b: 4 x: 6 y: 6 |a*b - x*y| : 0
a: 9 b: 5 x: 11 y: 4 |a*b - x*y| : 1
a: 9 b: 6 x: 24 y: 2 |a*b - x*y| : 6
a: 9 b: 6 x: 17 y: 3 |a*b - x*y| : 3
a: 10 b: 3 x: 14 y: 2 |a*b - x*y| : 2
a: 10 b: 4 x: 8 y: 5 |a*b - x*y| : 0
a: 10 b: 8 x: 35 y: 2 |a*b - x*y| : 10
answered Nov 25 at 20:24
Will Jagy
101k598198
101k598198
Thank you, Will.
– Tilsight
Nov 25 at 20:41
Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
– Tilsight
Nov 25 at 20:43
add a comment |
Thank you, Will.
– Tilsight
Nov 25 at 20:41
Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
– Tilsight
Nov 25 at 20:43
Thank you, Will.
– Tilsight
Nov 25 at 20:41
Thank you, Will.
– Tilsight
Nov 25 at 20:41
Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
– Tilsight
Nov 25 at 20:43
Just a question, you gave a very quick answer with a lot of examples. How did you do it so effectively? U wrote a script in C?
– Tilsight
Nov 25 at 20:43
add a comment |
Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,
so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.
add a comment |
Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,
so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.
add a comment |
Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,
so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.
Let for instance $a=1$ so we get that $3 b =n$ , and assume that $x =y$ so we get that $2 x^2 +2 x =n = 3b $ which leads to $x = frac{-2+sqrt{4+24b}}{4}$,
so for instance : for $b=28$ gives that $x = y = 6$ and $a=1$, so $| x y -a b| = 8$ , and you can get the maximum difference as large as you want.
answered Nov 25 at 20:42
Ahmad
2,5241625
2,5241625
add a comment |
add a comment |
Not bounded at all.
With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
$$ x = frac{2(a-3)(a+1)}{5} $$
With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
$$ x = frac{2a^2 -2a-5}{5} $$
a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642
Thanks guys. Respect 😀
– Tilsight
Nov 25 at 20:57
add a comment |
Not bounded at all.
With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
$$ x = frac{2(a-3)(a+1)}{5} $$
With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
$$ x = frac{2a^2 -2a-5}{5} $$
a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642
Thanks guys. Respect 😀
– Tilsight
Nov 25 at 20:57
add a comment |
Not bounded at all.
With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
$$ x = frac{2(a-3)(a+1)}{5} $$
With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
$$ x = frac{2a^2 -2a-5}{5} $$
a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642
Not bounded at all.
With $a equiv 3,4 pmod 5,$ we can take $b = a-3,$ then $y=2$ and
$$ x = frac{2(a-3)(a+1)}{5} $$
With $a equiv 0,1 pmod 5,$ we can take $b = a-2,$ then $y=2$ and
$$ x = frac{2a^2 -2a-5}{5} $$
a: 275 b: 273 x: 30139 y: 2 |a*b - x*y| : 14797
a: 276 b: 274 x: 30359 y: 2 |a*b - x*y| : 14906
a: 278 b: 275 x: 30690 y: 2 |a*b - x*y| : 15070
a: 279 b: 276 x: 30912 y: 2 |a*b - x*y| : 15180
a: 280 b: 278 x: 31247 y: 2 |a*b - x*y| : 15346
a: 281 b: 279 x: 31471 y: 2 |a*b - x*y| : 15457
a: 283 b: 280 x: 31808 y: 2 |a*b - x*y| : 15624
a: 284 b: 281 x: 32034 y: 2 |a*b - x*y| : 15736
a: 285 b: 283 x: 32375 y: 2 |a*b - x*y| : 15905
a: 286 b: 284 x: 32603 y: 2 |a*b - x*y| : 16018
a: 288 b: 285 x: 32946 y: 2 |a*b - x*y| : 16188
a: 289 b: 286 x: 33176 y: 2 |a*b - x*y| : 16302
a: 290 b: 288 x: 33523 y: 2 |a*b - x*y| : 16474
a: 291 b: 289 x: 33755 y: 2 |a*b - x*y| : 16589
a: 293 b: 290 x: 34104 y: 2 |a*b - x*y| : 16762
a: 294 b: 291 x: 34338 y: 2 |a*b - x*y| : 16878
a: 295 b: 293 x: 34691 y: 2 |a*b - x*y| : 17053
a: 296 b: 294 x: 34927 y: 2 |a*b - x*y| : 17170
a: 298 b: 295 x: 35282 y: 2 |a*b - x*y| : 17346
a: 299 b: 296 x: 35520 y: 2 |a*b - x*y| : 17464
a: 300 b: 298 x: 35879 y: 2 |a*b - x*y| : 17642
answered Nov 25 at 20:44
Will Jagy
101k598198
101k598198
Thanks guys. Respect 😀
– Tilsight
Nov 25 at 20:57
add a comment |
Thanks guys. Respect 😀
– Tilsight
Nov 25 at 20:57
Thanks guys. Respect 😀
– Tilsight
Nov 25 at 20:57
Thanks guys. Respect 😀
– Tilsight
Nov 25 at 20:57
add a comment |
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