Can a contract with no payable function have ether?
The question in the title says it all.
To the best of my understanding, the only way to deposit ether into a contract is by calling a payable function, and set msg.value larger than 0 (and of course, the function should complete successfully without reverting).
But if there are no payable functions to begin with, is it ever possible that the ether balance of the contract will be larger than 0?
Thank you!
solidity ether balances payable
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
add a comment |
The question in the title says it all.
To the best of my understanding, the only way to deposit ether into a contract is by calling a payable function, and set msg.value larger than 0 (and of course, the function should complete successfully without reverting).
But if there are no payable functions to begin with, is it ever possible that the ether balance of the contract will be larger than 0?
Thank you!
solidity ether balances payable
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
add a comment |
The question in the title says it all.
To the best of my understanding, the only way to deposit ether into a contract is by calling a payable function, and set msg.value larger than 0 (and of course, the function should complete successfully without reverting).
But if there are no payable functions to begin with, is it ever possible that the ether balance of the contract will be larger than 0?
Thank you!
solidity ether balances payable
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
The question in the title says it all.
To the best of my understanding, the only way to deposit ether into a contract is by calling a payable function, and set msg.value larger than 0 (and of course, the function should complete successfully without reverting).
But if there are no payable functions to begin with, is it ever possible that the ether balance of the contract will be larger than 0?
Thank you!
solidity ether balances payable
solidity ether balances payable
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
asked Dec 12 '18 at 11:57
goodvibrationgoodvibration
3,8671822
3,8671822
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Yes, a contract can have Ether balance without any payable function.
There are three ways to do it:
1) selfdestruction. Another contract self destructrs and sends its remaining Ether to your contract
2) Target of mining. Ether rewarded from mining can't be refused.
3) Ether sent to the contract before the contract exists.
More details about these alternatives can found for example here: https://medium.com/@alexsherbuck/two-ways-to-force-ether-into-a-contract-1543c1311c56
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
Great, thank you! Question on bullet #3: So this is just "a long shot in the dark"? I send ether to some public address without knowing it's private key, and at a later point in time, somebody deploys a contract which happens to "fall" on the same address - is that correct, or have I misinterpreted you intention?
– goodvibration
Dec 12 '18 at 12:56
3
@goodvibration The chance of someone generating any completely random address (either through a private key or contract deployment) is incredibly small. However, contract addresses are not random, they are deterministic. For any given address, you can know in advance the contract addresses it will generate: ethereum.stackexchange.com/questions/9776/…
– Jesse Busman
Dec 12 '18 at 14:29
3
Additionally, a trivial case: before Solidity 0.4payabledidn't exist, so all those Solidity contracts have ether without apayablefunction :)
– eth♦
Dec 13 '18 at 2:52
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Yes, a contract can have Ether balance without any payable function.
There are three ways to do it:
1) selfdestruction. Another contract self destructrs and sends its remaining Ether to your contract
2) Target of mining. Ether rewarded from mining can't be refused.
3) Ether sent to the contract before the contract exists.
More details about these alternatives can found for example here: https://medium.com/@alexsherbuck/two-ways-to-force-ether-into-a-contract-1543c1311c56
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
Great, thank you! Question on bullet #3: So this is just "a long shot in the dark"? I send ether to some public address without knowing it's private key, and at a later point in time, somebody deploys a contract which happens to "fall" on the same address - is that correct, or have I misinterpreted you intention?
– goodvibration
Dec 12 '18 at 12:56
3
@goodvibration The chance of someone generating any completely random address (either through a private key or contract deployment) is incredibly small. However, contract addresses are not random, they are deterministic. For any given address, you can know in advance the contract addresses it will generate: ethereum.stackexchange.com/questions/9776/…
– Jesse Busman
Dec 12 '18 at 14:29
3
Additionally, a trivial case: before Solidity 0.4payabledidn't exist, so all those Solidity contracts have ether without apayablefunction :)
– eth♦
Dec 13 '18 at 2:52
add a comment |
Yes, a contract can have Ether balance without any payable function.
There are three ways to do it:
1) selfdestruction. Another contract self destructrs and sends its remaining Ether to your contract
2) Target of mining. Ether rewarded from mining can't be refused.
3) Ether sent to the contract before the contract exists.
More details about these alternatives can found for example here: https://medium.com/@alexsherbuck/two-ways-to-force-ether-into-a-contract-1543c1311c56
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
Great, thank you! Question on bullet #3: So this is just "a long shot in the dark"? I send ether to some public address without knowing it's private key, and at a later point in time, somebody deploys a contract which happens to "fall" on the same address - is that correct, or have I misinterpreted you intention?
– goodvibration
Dec 12 '18 at 12:56
3
@goodvibration The chance of someone generating any completely random address (either through a private key or contract deployment) is incredibly small. However, contract addresses are not random, they are deterministic. For any given address, you can know in advance the contract addresses it will generate: ethereum.stackexchange.com/questions/9776/…
– Jesse Busman
Dec 12 '18 at 14:29
3
Additionally, a trivial case: before Solidity 0.4payabledidn't exist, so all those Solidity contracts have ether without apayablefunction :)
– eth♦
Dec 13 '18 at 2:52
add a comment |
Yes, a contract can have Ether balance without any payable function.
There are three ways to do it:
1) selfdestruction. Another contract self destructrs and sends its remaining Ether to your contract
2) Target of mining. Ether rewarded from mining can't be refused.
3) Ether sent to the contract before the contract exists.
More details about these alternatives can found for example here: https://medium.com/@alexsherbuck/two-ways-to-force-ether-into-a-contract-1543c1311c56
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
Yes, a contract can have Ether balance without any payable function.
There are three ways to do it:
1) selfdestruction. Another contract self destructrs and sends its remaining Ether to your contract
2) Target of mining. Ether rewarded from mining can't be refused.
3) Ether sent to the contract before the contract exists.
More details about these alternatives can found for example here: https://medium.com/@alexsherbuck/two-ways-to-force-ether-into-a-contract-1543c1311c56
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
answered Dec 12 '18 at 12:01
Lauri PeltonenLauri Peltonen
5,5492524
5,5492524
Great, thank you! Question on bullet #3: So this is just "a long shot in the dark"? I send ether to some public address without knowing it's private key, and at a later point in time, somebody deploys a contract which happens to "fall" on the same address - is that correct, or have I misinterpreted you intention?
– goodvibration
Dec 12 '18 at 12:56
3
@goodvibration The chance of someone generating any completely random address (either through a private key or contract deployment) is incredibly small. However, contract addresses are not random, they are deterministic. For any given address, you can know in advance the contract addresses it will generate: ethereum.stackexchange.com/questions/9776/…
– Jesse Busman
Dec 12 '18 at 14:29
3
Additionally, a trivial case: before Solidity 0.4payabledidn't exist, so all those Solidity contracts have ether without apayablefunction :)
– eth♦
Dec 13 '18 at 2:52
add a comment |
Great, thank you! Question on bullet #3: So this is just "a long shot in the dark"? I send ether to some public address without knowing it's private key, and at a later point in time, somebody deploys a contract which happens to "fall" on the same address - is that correct, or have I misinterpreted you intention?
– goodvibration
Dec 12 '18 at 12:56
3
@goodvibration The chance of someone generating any completely random address (either through a private key or contract deployment) is incredibly small. However, contract addresses are not random, they are deterministic. For any given address, you can know in advance the contract addresses it will generate: ethereum.stackexchange.com/questions/9776/…
– Jesse Busman
Dec 12 '18 at 14:29
3
Additionally, a trivial case: before Solidity 0.4payabledidn't exist, so all those Solidity contracts have ether without apayablefunction :)
– eth♦
Dec 13 '18 at 2:52
Great, thank you! Question on bullet #3: So this is just "a long shot in the dark"? I send ether to some public address without knowing it's private key, and at a later point in time, somebody deploys a contract which happens to "fall" on the same address - is that correct, or have I misinterpreted you intention?
– goodvibration
Dec 12 '18 at 12:56
Great, thank you! Question on bullet #3: So this is just "a long shot in the dark"? I send ether to some public address without knowing it's private key, and at a later point in time, somebody deploys a contract which happens to "fall" on the same address - is that correct, or have I misinterpreted you intention?
– goodvibration
Dec 12 '18 at 12:56
3
3
@goodvibration The chance of someone generating any completely random address (either through a private key or contract deployment) is incredibly small. However, contract addresses are not random, they are deterministic. For any given address, you can know in advance the contract addresses it will generate: ethereum.stackexchange.com/questions/9776/…
– Jesse Busman
Dec 12 '18 at 14:29
@goodvibration The chance of someone generating any completely random address (either through a private key or contract deployment) is incredibly small. However, contract addresses are not random, they are deterministic. For any given address, you can know in advance the contract addresses it will generate: ethereum.stackexchange.com/questions/9776/…
– Jesse Busman
Dec 12 '18 at 14:29
3
3
Additionally, a trivial case: before Solidity 0.4
payable didn't exist, so all those Solidity contracts have ether without a payable function :)– eth♦
Dec 13 '18 at 2:52
Additionally, a trivial case: before Solidity 0.4
payable didn't exist, so all those Solidity contracts have ether without a payable function :)– eth♦
Dec 13 '18 at 2:52
add a comment |
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