multichoose but limit the duplicates












1












$begingroup$


"n choose k" is how many combinations of: k-sized elements from n unique choices.



"n multichoose k" is how many k-sized elements from n choices, where full multiplicity is allowed (that is, {a, b, c} choose 3 can have {a, a, a}).



How do we calculate "n choose k by m" where we allow only m duplicates?










share|cite|improve this question









$endgroup$












  • $begingroup$
    What do you mean by $n$ choose $k$ by $m$?
    $endgroup$
    – Prakhar Nagpal
    Dec 21 '18 at 4:23
















1












$begingroup$


"n choose k" is how many combinations of: k-sized elements from n unique choices.



"n multichoose k" is how many k-sized elements from n choices, where full multiplicity is allowed (that is, {a, b, c} choose 3 can have {a, a, a}).



How do we calculate "n choose k by m" where we allow only m duplicates?










share|cite|improve this question









$endgroup$












  • $begingroup$
    What do you mean by $n$ choose $k$ by $m$?
    $endgroup$
    – Prakhar Nagpal
    Dec 21 '18 at 4:23














1












1








1





$begingroup$


"n choose k" is how many combinations of: k-sized elements from n unique choices.



"n multichoose k" is how many k-sized elements from n choices, where full multiplicity is allowed (that is, {a, b, c} choose 3 can have {a, a, a}).



How do we calculate "n choose k by m" where we allow only m duplicates?










share|cite|improve this question









$endgroup$




"n choose k" is how many combinations of: k-sized elements from n unique choices.



"n multichoose k" is how many k-sized elements from n choices, where full multiplicity is allowed (that is, {a, b, c} choose 3 can have {a, a, a}).



How do we calculate "n choose k by m" where we allow only m duplicates?







combinatorics






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 21 '18 at 2:06









pixelspixels

1085




1085












  • $begingroup$
    What do you mean by $n$ choose $k$ by $m$?
    $endgroup$
    – Prakhar Nagpal
    Dec 21 '18 at 4:23


















  • $begingroup$
    What do you mean by $n$ choose $k$ by $m$?
    $endgroup$
    – Prakhar Nagpal
    Dec 21 '18 at 4:23
















$begingroup$
What do you mean by $n$ choose $k$ by $m$?
$endgroup$
– Prakhar Nagpal
Dec 21 '18 at 4:23




$begingroup$
What do you mean by $n$ choose $k$ by $m$?
$endgroup$
– Prakhar Nagpal
Dec 21 '18 at 4:23










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