existence and uniqueness for $dot x(t)=f(t,x(t))$, with $f$ measurable in $t$.












1












$begingroup$


Consider the following scalar ODE



$$dot x(t) = f(t,x(t))$$
defined on a compact interval $[0,T]$.



Assume that $f$ is Lipschitz continuous in $x$, but it is measurable in $t$.
What can we say about the existence and uniqueness?



The standard Picard theorem assumes that $f$ is continuous in $t$.










share|cite|improve this question









$endgroup$

















    1












    $begingroup$


    Consider the following scalar ODE



    $$dot x(t) = f(t,x(t))$$
    defined on a compact interval $[0,T]$.



    Assume that $f$ is Lipschitz continuous in $x$, but it is measurable in $t$.
    What can we say about the existence and uniqueness?



    The standard Picard theorem assumes that $f$ is continuous in $t$.










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      Consider the following scalar ODE



      $$dot x(t) = f(t,x(t))$$
      defined on a compact interval $[0,T]$.



      Assume that $f$ is Lipschitz continuous in $x$, but it is measurable in $t$.
      What can we say about the existence and uniqueness?



      The standard Picard theorem assumes that $f$ is continuous in $t$.










      share|cite|improve this question









      $endgroup$




      Consider the following scalar ODE



      $$dot x(t) = f(t,x(t))$$
      defined on a compact interval $[0,T]$.



      Assume that $f$ is Lipschitz continuous in $x$, but it is measurable in $t$.
      What can we say about the existence and uniqueness?



      The standard Picard theorem assumes that $f$ is continuous in $t$.







      real-analysis ordinary-differential-equations






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Dec 25 '18 at 21:59









      M.AM.A

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      1599






















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          $begingroup$

          The answer is almost provided by Carathéodory’s existence theorem.






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            $begingroup$

            The answer is almost provided by Carathéodory’s existence theorem.






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              $begingroup$

              The answer is almost provided by Carathéodory’s existence theorem.






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                $begingroup$

                The answer is almost provided by Carathéodory’s existence theorem.






                share|cite|improve this answer









                $endgroup$



                The answer is almost provided by Carathéodory’s existence theorem.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 25 '18 at 22:21









                mathcounterexamples.netmathcounterexamples.net

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