A function analytic in the unit disk belongs to the class Nevanlinna if and only if it is the quotient of two...
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I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it.
functional-analysis proof-explanation harmonic-functions analytic-functions
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I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it.
functional-analysis proof-explanation harmonic-functions analytic-functions
$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15
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up vote
0
down vote
favorite
I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it.
functional-analysis proof-explanation harmonic-functions analytic-functions
I'm trying to understand a part of this proof from Duren, in the converse, I don't see it clear when it says "by analytic completion of the Poisson Formula,..." and then the result; I tried to prove it's true, but I don't get it.
functional-analysis proof-explanation harmonic-functions analytic-functions
functional-analysis proof-explanation harmonic-functions analytic-functions
asked Nov 16 at 17:29
Kale36
403
403
$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15
add a comment |
$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15
$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15
$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15
add a comment |
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$F(z)$ is analytic and from Poisson formula then as he said in following $$f(z)=dfrac{phi}{psi}$$
– Nosrati
Nov 16 at 18:15