What is the range of parameters rho and theta in normal equation of a straight line?
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I'm implementing Hough Transform in MatLab to detect straight lines in an Image. It uses normal form of a straight line equation
$$x cos(theta) + y sin(theta) = rho$$
I'm interested in the lines which pass through the 1st quadrant only, that too in the rectangle with vertices $(0,0), (M,0), (0,N), (M,N)$ i.e. any line that doesn't pass through this rectangle, I'm not interested in finding the equation of that line. Orientation of the line can be anything. What is the range of values for the parameters $rho$ and $theta$?
If I assume $theta$ varies from $-90^text{o}$ to $90^text{o}$, what is the range of values for $rho$? Can $rho$ be negative?
geometry
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up vote
2
down vote
favorite
I'm implementing Hough Transform in MatLab to detect straight lines in an Image. It uses normal form of a straight line equation
$$x cos(theta) + y sin(theta) = rho$$
I'm interested in the lines which pass through the 1st quadrant only, that too in the rectangle with vertices $(0,0), (M,0), (0,N), (M,N)$ i.e. any line that doesn't pass through this rectangle, I'm not interested in finding the equation of that line. Orientation of the line can be anything. What is the range of values for the parameters $rho$ and $theta$?
If I assume $theta$ varies from $-90^text{o}$ to $90^text{o}$, what is the range of values for $rho$? Can $rho$ be negative?
geometry
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up vote
2
down vote
favorite
up vote
2
down vote
favorite
I'm implementing Hough Transform in MatLab to detect straight lines in an Image. It uses normal form of a straight line equation
$$x cos(theta) + y sin(theta) = rho$$
I'm interested in the lines which pass through the 1st quadrant only, that too in the rectangle with vertices $(0,0), (M,0), (0,N), (M,N)$ i.e. any line that doesn't pass through this rectangle, I'm not interested in finding the equation of that line. Orientation of the line can be anything. What is the range of values for the parameters $rho$ and $theta$?
If I assume $theta$ varies from $-90^text{o}$ to $90^text{o}$, what is the range of values for $rho$? Can $rho$ be negative?
geometry
I'm implementing Hough Transform in MatLab to detect straight lines in an Image. It uses normal form of a straight line equation
$$x cos(theta) + y sin(theta) = rho$$
I'm interested in the lines which pass through the 1st quadrant only, that too in the rectangle with vertices $(0,0), (M,0), (0,N), (M,N)$ i.e. any line that doesn't pass through this rectangle, I'm not interested in finding the equation of that line. Orientation of the line can be anything. What is the range of values for the parameters $rho$ and $theta$?
If I assume $theta$ varies from $-90^text{o}$ to $90^text{o}$, what is the range of values for $rho$? Can $rho$ be negative?
geometry
geometry
edited Nov 18 at 18:21
learner
226
226
asked Nov 18 at 18:17
Nagabhushan S N
22814
22814
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                                1 Answer
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1
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As depicted in the graph we have better split for negative anf for positive values of $theta$.
Thus we must have
$$
left{ {matrix{
   {left{ matrix{
   - rho /cos theta  le M hfill cr 
   - rho /sin theta  le N hfill cr}  right.} hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {left{ matrix{
  rho /cos theta  - Ntan theta  le M hfill cr 
  0 le rho  hfill cr}  right.} hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
that is
$$
left{ {matrix{
   { - Mcos theta  le rho  le  - Nsin theta } hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {0 le rho  le Mcos theta  + Nsin theta } hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
add a comment |
                                1 Answer
                                1
                        
active
oldest
votes
                                1 Answer
                                1
                        
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted

As depicted in the graph we have better split for negative anf for positive values of $theta$.
Thus we must have
$$
left{ {matrix{
   {left{ matrix{
   - rho /cos theta  le M hfill cr 
   - rho /sin theta  le N hfill cr}  right.} hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {left{ matrix{
  rho /cos theta  - Ntan theta  le M hfill cr 
  0 le rho  hfill cr}  right.} hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
that is
$$
left{ {matrix{
   { - Mcos theta  le rho  le  - Nsin theta } hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {0 le rho  le Mcos theta  + Nsin theta } hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
add a comment |
up vote
1
down vote
accepted

As depicted in the graph we have better split for negative anf for positive values of $theta$.
Thus we must have
$$
left{ {matrix{
   {left{ matrix{
   - rho /cos theta  le M hfill cr 
   - rho /sin theta  le N hfill cr}  right.} hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {left{ matrix{
  rho /cos theta  - Ntan theta  le M hfill cr 
  0 le rho  hfill cr}  right.} hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
that is
$$
left{ {matrix{
   { - Mcos theta  le rho  le  - Nsin theta } hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {0 le rho  le Mcos theta  + Nsin theta } hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted

As depicted in the graph we have better split for negative anf for positive values of $theta$.
Thus we must have
$$
left{ {matrix{
   {left{ matrix{
   - rho /cos theta  le M hfill cr 
   - rho /sin theta  le N hfill cr}  right.} hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {left{ matrix{
  rho /cos theta  - Ntan theta  le M hfill cr 
  0 le rho  hfill cr}  right.} hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
that is
$$
left{ {matrix{
   { - Mcos theta  le rho  le  - Nsin theta } hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {0 le rho  le Mcos theta  + Nsin theta } hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$

As depicted in the graph we have better split for negative anf for positive values of $theta$.
Thus we must have
$$
left{ {matrix{
   {left{ matrix{
   - rho /cos theta  le M hfill cr 
   - rho /sin theta  le N hfill cr}  right.} hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {left{ matrix{
  rho /cos theta  - Ntan theta  le M hfill cr 
  0 le rho  hfill cr}  right.} hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
that is
$$
left{ {matrix{
   { - Mcos theta  le rho  le  - Nsin theta } hfill & {left| {; - pi /2 < theta  < 0} right.} hfill  cr 
   {0 le rho  le Mcos theta  + Nsin theta } hfill & {left| {;0 < theta  < pi /2} right.} hfill  cr 
 } } right.
$$
answered Nov 19 at 1:21
G Cab
16.9k31237
16.9k31237
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